Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 1912:30 PM EST
-01:30 PM EST
Learn how Keshav, a Chartered Accountant, scored an impressive 705 on GMAT in just 30 days with GMATWhiz's expert guidance. In this video, he shares preparation tips and strategies that worked for him, including the mock, time management, and more
Nov 2001:30 PM EST
-02:30 PM IST
Learn how Kamakshi achieved a GMAT 675 with an impressive 96th %ile in Data Insights. Discover the unique methods and exam strategies that helped her excel in DI along with other sections for a balanced and high score.
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2407:00 PM PST
-08:00 PM PST
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
10 Jan 2020, 05:26
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
68% (02:43) correct
32%
(03:11)
wrong
based on 245
sessions
History
Date
Time
Result
Not Attempted Yet
A train meets with an accident and travels at 4/7th of its regular speed hereafter and hence it reaches its destination 36 minutes late. Had the accident occurred 30 kms further, the train would have been late by only 21 minutes. Find the regular speed of the train.
A. 80 kmph.
B. 85 kmph.
C. 90 kmph.
D. 95 kmph.
E. 100 kmph.
A. 80 kmph.
B. 85 kmph.
C. 90 kmph.
D. 95 kmph.
E. 100 kmph.
22 Jun 2020, 12:20
Kudos
Bookmarks
Train is late by 36 minutes. Had the accident occurred 30 kms further, the train would have been late by only 21.
Means, Train would have saved 15mins had it been running on its original speed for 30 Kms.
Let the normal speed and time taken at normal speed for 30km be S and T. Then , for 30 kms at (4/7)of speed train is taking 15 minutes more. Writing the equation as-
ST=(4/7)S * (T+15)
T= (4/7) T + (60/7)
(3/7) T= 60/7
T=20
Therefore speed is -
S=(30/20) km/minutes
Or 90 Km/hr.
Posted from my mobile device
Means, Train would have saved 15mins had it been running on its original speed for 30 Kms.
Let the normal speed and time taken at normal speed for 30km be S and T. Then , for 30 kms at (4/7)of speed train is taking 15 minutes more. Writing the equation as-
ST=(4/7)S * (T+15)
T= (4/7) T + (60/7)
(3/7) T= 60/7
T=20
Therefore speed is -
S=(30/20) km/minutes
Or 90 Km/hr.
Posted from my mobile device
24 Jan 2025, 01:06
Kudos
Bookmarks
Thinking about solving this by calculating total distance in two phases on 2 separate occasions just seems too tedious. Plus, I am not even great at making equations that make sense all the time, so I had to think only about the difference making 30 km stretch.
When the train covers the 30km at its regular speed, it saves 15 minutes.
Which is 30/(4x/7)-30/x=15/60 (taking speed as x)
210/4x-30/x=1/4
x=90.
When the train covers the 30km at its regular speed, it saves 15 minutes.
Which is 30/(4x/7)-30/x=15/60 (taking speed as x)
210/4x-30/x=1/4
x=90.
