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A wooden cube whose edge length is 10 inches is composed of

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A wooden cube whose edge length is 10 inches is composed of  [#permalink]

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New post Updated on: 02 Nov 2013, 04:03
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A wooden cube whose edge length is 10 inches is composed of smaller cubes with edge lengths of one inch. The outside surface of the large cube is painted red and then it is split up into its smaller cubes. If one cube is randomly selected from the small cubes, what is the probability that the cube will have AT LEAST one red face?

A. 36.0%
B. 48.8%
C. 50.0%
D. 52.5%
E. 60%

Can someone elaborate on the approach to tackle a problem such as this one?

Originally posted by PatrickS on 01 Nov 2013, 21:46.
Last edited by Bunuel on 02 Nov 2013, 04:03, edited 1 time in total.
Renamed the topic and edited the question.
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Re: A wooden cube whose edge length is 10 inches is composed of  [#permalink]

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New post 02 Nov 2013, 04:09
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PatrickS wrote:
A wooden cube whose edge length is 10 inches is composed of smaller cubes with edge lengths of one inch. The outside surface of the large cube is painted red and then it is split up into its smaller cubes. If one cube is randomly selected from the small cubes, what is the probability that the cube will have AT LEAST one red face?

A. 36.0%
B. 48.8%
C. 50.0%
D. 52.5%
E. 60%

Can someone elaborate on the approach to tackle a problem such as this one?


The cube is composed of 10^3 little cubes. Out of them 8^3 non-exposed central cubes won't be colored at all.

Thus the probability is P(at least one red face) = 1 - P(no red face) = 1 - 8^3/10^3= 488/10^3.

Answer: B.
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Re: Painted Cube  [#permalink]

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New post 01 Nov 2013, 21:54
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This was my approach but it took me at least 5 min to figure it out, anyone can think of a quicker way?

Step 1: Calculate the total number of cubes
Volume = L*W*H=10*10*10=1000 cubes in total

Step 2: Calculate the number of cubes that are NOT painted:
Volume=L*W*H=8*8*8= 512 - took 8 since on each 2D slice we will have the first and last cube painted

Step 3: Calculate the number of cubes that will have at least 1 side painted:
#Cubes with at least 1 side painted = 1000-512=488

Step 4: Calculate probability
P(Cubes with at least 1 side) = \(\frac{#Cubes with at least 1 side painted}{Total number of cubes}\)= \(\frac{488}{1000}\)=48.8%
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Re: A wooden cube whose edge length is 10 inches is composed of  [#permalink]

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New post 02 Nov 2013, 04:10
Bunuel wrote:
PatrickS wrote:
A wooden cube whose edge length is 10 inches is composed of smaller cubes with edge lengths of one inch. The outside surface of the large cube is painted red and then it is split up into its smaller cubes. If one cube is randomly selected from the small cubes, what is the probability that the cube will have AT LEAST one red face?

A. 36.0%
B. 48.8%
C. 50.0%
D. 52.5%
E. 60%

Can someone elaborate on the approach to tackle a problem such as this one?


The cube is composed of 10^3 little cubes. Out of them 8^3 non-exposed central cubes won't be colored at all.

Thus the probability is P(at least one red face) = 1 - P(no red face) = 1 - 8^3/10^3= 488/10^3.

Answer: B.


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if-a-4-cm-cube-is-cut-into-1-cm-cubes-then-what-is-the-107843.html
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a-large-cube-consists-of-125-identical-small-cubes-how-110256.html
64-small-identical-cubes-are-used-to-form-a-large-cube-151009.html

Hope it helps.
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Re: A wooden cube whose edge length is 10 inches is composed of  [#permalink]

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New post 21 May 2014, 08:28
Total number of small cubes = 10^3 = 1000

All the cubes which are in side the outer layer of cubes have no side colored.

Number of cubes inside the outer layer = 8*8*8 = 512

probability that the cube will have AT LEAST one red face = 1- probability that the cube will have no red face

=1-(512/1000) = 1-0.512 = 0.488 = 48.8%

Answer is B
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Re: A wooden cube whose edge length is 10 inches is composed of  [#permalink]

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New post 09 Sep 2014, 23:08
Bunuel wrote:
PatrickS wrote:
A wooden cube whose edge length is 10 inches is composed of smaller cubes with edge lengths of one inch. The outside surface of the large cube is painted red and then it is split up into its smaller cubes. If one cube is randomly selected from the small cubes, what is the probability that the cube will have AT LEAST one red face?

A. 36.0%
B. 48.8%
C. 50.0%
D. 52.5%
E. 60%

Can someone elaborate on the approach to tackle a problem such as this one?


The cube is composed of 10^3 little cubes. Out of them 8^3 non-exposed central cubes won't be colored at all.

Thus the probability is P(at least one red face) = 1 - P(no red face) = 1 - 8^3/10^3= 488/10^3.

Answer: B.

Hi Bunuel,
I tried this with the counting method:
8*8 squares in the inside of every side of the cube.
now we choose one side, and what's left there is 39 cubes. same for that exact opposite side.
now all that's left is to connect the two sides (8 cubes to connect * 4 edges to connect)
I get to 494/1000. where am I going wrong?
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Re: A wooden cube whose edge length is 10 inches is composed of  [#permalink]

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New post 10 Sep 2014, 04:17
ronr34 wrote:
Bunuel wrote:
PatrickS wrote:
A wooden cube whose edge length is 10 inches is composed of smaller cubes with edge lengths of one inch. The outside surface of the large cube is painted red and then it is split up into its smaller cubes. If one cube is randomly selected from the small cubes, what is the probability that the cube will have AT LEAST one red face?

A. 36.0%
B. 48.8%
C. 50.0%
D. 52.5%
E. 60%

Can someone elaborate on the approach to tackle a problem such as this one?


The cube is composed of 10^3 little cubes. Out of them 8^3 non-exposed central cubes won't be colored at all.

Thus the probability is P(at least one red face) = 1 - P(no red face) = 1 - 8^3/10^3= 488/10^3.

Answer: B.

Hi Bunuel,
I tried this with the counting method:
8*8 squares in the inside of every side of the cube.
now we choose one side, and what's left there is 39 cubes. same for that exact opposite side.
now all that's left is to connect the two sides (8 cubes to connect * 4 edges to connect)
I get to 494/1000. where am I going wrong?


How is there 39 cubes left? Does 39 and 8^2 total 100?
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: A wooden cube whose edge length is 10 inches is composed of  [#permalink]

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New post 10 Sep 2014, 13:23
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Though this question can be done better the way already discussed, Let's count the number of cubes with 1-face, 2-faces and 3-faces painted. This might give us a better picture if the question is modifies as : probability of getting a cube with exactly 2 faces painted or exactly 3 faces painted.

1-face painted:

Cubes with one face painted lies on each face except along the edges of the face.
So total number of 1-face painted cubes = 8*8*6 = 384<when we exclude edges, we are left with 8*8><6 for 6 faces>

2-faces painted:
Such cubes exist along the edges except the ones at the corners. And total number of edges = 12
So, total number of 2-faces painted cubes = 8*12 = 96 <Out of 10 cubes along an edge, only 8 are 2-faces painted, the ones at the corners are all three faces painted>

3-faces painted:
The ones at the corners are 3-faces painted. Number of corners = 8
Total number of 3-faces painted cubes= 8.
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Re: A wooden cube whose edge length is 10 inches is composed of  [#permalink]

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New post 30 Oct 2016, 13:08
We have in total 10*10*10 = 1000 cubes.

Let s count the zero no red face and the substract it from 1000.

The number of cubes with no red face are 8*8*8=512 it is a cube inscribed in the biggest cube with a side equal to 8 inches.

So 1000-512= 488... it gives 48,8% [b]

Answer B

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Re: A wooden cube whose edge length is 10 inches is composed of  [#permalink]

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