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# Absolute Reciprocity Is ( |x-1y-1| )-1 > xy? (1) xy >

Author Message
Manager
Joined: 05 Oct 2005
Posts: 199
Absolute Reciprocity Is ( |x-1y-1| )-1 > xy? (1) xy >  [#permalink]

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26 Jan 2006, 09:07
1

Absolute Reciprocity
Is ( |x-1y-1| )-1 > xy?

(1) xy > 1
(2) x2 > y2

PLZ explain

no A

thanks

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26 Jan 2006, 12:11
A.

The statement can be reduced to is |xy| < xy ?. This can only be true if xy is negative. Thus, we need to find out is xy < 0 ?

I. It is given xy > 0, thus xy is not negative...SUFF.

II. Since x^2 > y^2, we can't tell figure out the sign of x or y.
If x,y > 0, then xy > 0.
x > 0, y < 0, then xy < 0....INSUFF.
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Posts: 9460
Re: Absolute Reciprocity Is ( |x-1y-1| )-1 > xy? (1) xy >  [#permalink]

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04 Mar 2018, 06:58
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--== Message from the GMAT Club Team ==--

THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION.
This discussion does not meet community quality standards. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

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Re: Absolute Reciprocity Is ( |x-1y-1| )-1 > xy? (1) xy > &nbs [#permalink] 04 Mar 2018, 06:58
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