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# According to the formula F=9/5 (C) +32, if the temperature

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Manager
Joined: 30 Mar 2013
Posts: 109
According to the formula F=9/5 (C) +32, if the temperature  [#permalink]

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27 Sep 2013, 22:25
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25
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Difficulty:

35% (medium)

Question Stats:

74% (02:08) correct 26% (02:18) wrong based on 500 sessions

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According to the formula F=9/5 (C) +32, if the temperature in degrees Farenheit (F) increases by 27, by how much does the temperature in degrees Celsius (C) increase?

A) 9
B) 15
C) 47
D) 48 3/5
E) 59
Math Expert
Joined: 02 Sep 2009
Posts: 51280
Re: According to the formula F=9/5 (C) +32,  [#permalink]

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28 Sep 2013, 03:09
2
3
usre123 wrote:
According to the formula F=9/5 (C) +32, if the temperature in degrees Farenheit (F) increases by 27, by how much does the temperature in degrees Celsius (C) increase?

A)9
B)15
C)47
D) 48 3/5
E) 59

You can plug in values.

C = 5/9*(F-32)

F=32 --> C=0;
F=32+27=59 --> C=5/9*27=15.

Increase = 15 degrees.

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Re: According to the formula F=9/5 (C) +32,  [#permalink]

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27 Sep 2013, 22:52
1
4
usre123 wrote:
According to the formula F=9/5 (C) +32, if the temperature in degrees Farenheit (F) increases by 27, by how much does the temperature in degrees Celsius (C) increase?

A)9
B)15
C)47
D) 48 3/5
E) 59

$$F_i = \frac{9}{5}* (C_i) +32$$

$$F_i+27= \frac{9}{5}* (C_f) +32$$

On Subtracting, we get$$27 = \frac{9}{5}* (C_f-C_i) \to (C_f-C_i) = 3*5 = 15$$

B.
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Posts: 51280
Re: According to the formula F=9/5 (C) +32,  [#permalink]

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28 Sep 2013, 03:11
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Manager
Joined: 30 Mar 2013
Posts: 109
Re: According to the formula F=9/5 (C) +32,  [#permalink]

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01 Oct 2013, 09:54
Bunuel wrote:
usre123 wrote:
According to the formula F=9/5 (C) +32, if the temperature in degrees Farenheit (F) increases by 27, by how much does the temperature in degrees Celsius (C) increase?

A)9
B)15
C)47
D) 48 3/5
E) 59

You can plug in values.

C = 5/9*(F-32)

F=32 --> C=0;
F=32+27=59 --> C=5/9*27=15.

Increase = 15 degrees.

I dont understand why you only multiplied 5/9 by 27. what about F-32?
Math Expert
Joined: 02 Sep 2009
Posts: 51280
According to the formula F=9/5 (C) +32, if the temperature  [#permalink]

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02 Oct 2013, 02:35
2
2
usre123 wrote:
Bunuel wrote:
usre123 wrote:
According to the formula F=9/5 (C) +32, if the temperature in degrees Farenheit (F) increases by 27, by how much does the temperature in degrees Celsius (C) increase?

A)9
B)15
C)47
D) 48 3/5
E) 59

You can plug in values.

C = 5/9*(F-32)

F=32 --> C=0;
F=32+27=59 --> C=5/9*27=15.

Increase = 15 degrees.

I dont understand why you only multiplied 5/9 by 27. what about F-32?

If F=59, then $$C = \frac{5}{9}*(F-32) = \frac{5}{9}*(59-32) = \frac{5}{9}*27 = 15$$.

Does this make sense?
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Re: According to the formula F=9/5 (C) +32, if the temperature  [#permalink]

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02 Jan 2017, 13:37
Could someone please explain what happens to the F=9/5 (C) +32? In all of the provided solutions, no one does anything with this, but I'm confused as to why that is.
Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 8690
Location: Pune, India
Re: According to the formula F=9/5 (C) +32, if the temperature  [#permalink]

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03 Jan 2017, 03:49
4
skimmingit wrote:
Could someone please explain what happens to the F=9/5 (C) +32? In all of the provided solutions, no one does anything with this, but I'm confused as to why that is.

32 is constant. It doesn't bring about the change. The change is defined by the relation between F and C only. 32 just gets cancelled out.

F1 = (9/5)*C1 + 32 ......(I)
F2 = (9/5)*C2 + 32 ......(II)

(II) - (I)

F2 - F1 = (9/5)*(C2 - C1) + 32 - 32

F2 - F1 = (9/5)*(C2 - C1)

27 = (9/5)*(C2 - C1)

(C2 - C1) = 15
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Re: According to the formula F=9/5 (C) +32, if the temperature  [#permalink]

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19 Aug 2017, 12:26
1
VeritasPrepKarishma wrote:
skimmingit wrote:
Could someone please explain what happens to the F=9/5 (C) +32? In all of the provided solutions, no one does anything with this, but I'm confused as to why that is.

32 is constant. It doesn't bring about the change. The change is defined by the relation between F and C only. 32 just gets cancelled out.

F1 = (9/5)*C1 + 32 ......(I)
F2 = (9/5)*C2 + 32 ......(II)

(II) - (I)

F2 - F1 = (9/5)*(C2 - C1) + 32 - 32

F2 - F1 = (9/5)*(C2 - C1)

27 = (9/5)*(C2 - C1)

(C2 - C1) = 15

hi mam

since the change is defined by the relation between F and C only, we can say directly that the "change in F" is equal to 9/5 times the "change in C". That's it...

thanks mam ..
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Re: According to the formula F=9/5 (C) +32, if the temperature  [#permalink]

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30 Aug 2018, 10:35
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Re: According to the formula F=9/5 (C) +32, if the temperature &nbs [#permalink] 30 Aug 2018, 10:35
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