Dillesh4096 wrote:
Adam, Brian and Charlie can complete a certain work in 75, 50 and 40 days respectively. All 3 started working together, but Charlie took a leave in between and hence the work got completed in 18 days. For how many days was Charlie on leave?
A. 2
B. 3
C. 4
D. 5
E. 6
Let, Total Work = LCM (75, 50, 40) units = 600 units
i..e. A does 600 units in 75 days i.e.
A's work per day = 600/75 = 8 units
B's work per day = 600/50 = 12 units
C's work per day = 600/40 = 15 units
18days' work of A = 8*18 = 144 unit
18days' work of B = 12*18 = 216 unit
Work done by both A and B in 18 days = 144+216 = 360 units
Work Done by C = 600 - 360 = 240 units
C's days worked = 240 / 15 = 16 days
Charlie's leaves = 18 days - 16 days = 2 days
Answer: Option A
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