Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 2007:30 AM PST
-08:30 AM PST
Learn what truly sets the UC Riverside MBA apart and how it helps in your professional growth
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
16 Aug 2024, 06:07
Kudos
Bookmarks
P: 1
Q: 4
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
84% (02:37) correct
16%
(02:51)
wrong
based on 972
sessions
History
Date
Time
Result
Not Attempted Yet
After a 16-member team at Company A saw a certain software demonstration, each of the team members gave the software exactly one of the ratings 1, 2, 3, 4, or 5, where greater numbers indicate higher ratings. The team's manager intended to record the 16 ratings but accidentally recorded one team member's rating twice. The ratings she recorded show two ratings of 1, two ratings of 2, two ratings of 3, two ratings of 4, and nine ratings of 5, for a total of 17 ratings. The manager determined that the extra rating was ____P____, and after this extra rating was removed, the average (arithmetic mean) of the remaining 16 ratings was exactly ____Q____.
Select for P and for Q the options that create a statement that is consistent with the information provided. Make only two selections, one in each column.
Select for P and for Q the options that create a statement that is consistent with the information provided. Make only two selections, one in each column.
ID: 700356
| P | Q | |
| 1 | ||
| 2 | ||
| 3 | ||
| 4 | ||
| 5 |
ShowHide Answer
Official Answer
P: 1
Q: 4
22 Aug 2024, 05:59
Kudos
Bookmarks
After the extra rating was removed, there were 16 ratings.
Looking at the answer choices, we see that they are all integers: 1, 2, 3, 4, and 5.
So, since average = sum/number, the sum of all the ratings must be a multiple of 16 so that sum/16 = an integer.
Adding all 17 ratings, we get 1 + 1 + 2 + 2 + 3 + 3 + 4 + 4 + (5 × 9) = 65
If we remove one 1, the sum becomes 64, which equals 16 × 4.
If we remove any other of the 17 ratings we get the following:
65 - 2 = 63 not a multiple of 16
65 - 3 = 62 not a multiple of 16
65 - 4 = 61 not a multiplel of 16
65 - 5 = 60 not a multiple of 16
So, the only way to get a sum of the ratings that is a multiple of 16 is to remove one 1.
Thus, the correct answer for P is 1, and the correct answer for Q is 64/16 = 4.
Looking at the answer choices, we see that they are all integers: 1, 2, 3, 4, and 5.
So, since average = sum/number, the sum of all the ratings must be a multiple of 16 so that sum/16 = an integer.
Adding all 17 ratings, we get 1 + 1 + 2 + 2 + 3 + 3 + 4 + 4 + (5 × 9) = 65
If we remove one 1, the sum becomes 64, which equals 16 × 4.
If we remove any other of the 17 ratings we get the following:
65 - 2 = 63 not a multiple of 16
65 - 3 = 62 not a multiple of 16
65 - 4 = 61 not a multiplel of 16
65 - 5 = 60 not a multiple of 16
So, the only way to get a sum of the ratings that is a multiple of 16 is to remove one 1.
Thus, the correct answer for P is 1, and the correct answer for Q is 64/16 = 4.
General Discussion
21 Oct 2024, 10:34
Kudos
Bookmarks
1. We are given a set of 17 ratings and need to find the extra rating - P - and the average of the remaining 16 ratings - Q.
2. It is known that \(Q = \frac{sum - P}{16} = \frac{2 * 1 + 2 * 2 + 2 * 3 + 2 * 4 + 9 * 5 - P}{16} = \frac{65 - P}{16}= \frac{64 + 1 - P}{16} = 4 + \frac{1-P}{16}\).
3. If P is 2, 3, 4, or 5 then Q won't be a whole number. So, P = 1.
4. Then, \(Q = 4 + \frac{1 - 1}{16} = 4\).
5. So, our answer will be P = 1 and Q = 4.
2. It is known that \(Q = \frac{sum - P}{16} = \frac{2 * 1 + 2 * 2 + 2 * 3 + 2 * 4 + 9 * 5 - P}{16} = \frac{65 - P}{16}= \frac{64 + 1 - P}{16} = 4 + \frac{1-P}{16}\).
3. If P is 2, 3, 4, or 5 then Q won't be a whole number. So, P = 1.
4. Then, \(Q = 4 + \frac{1 - 1}{16} = 4\).
5. So, our answer will be P = 1 and Q = 4.
