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After the price of chocolates was discounted by 40%, a
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Updated on: 30 Oct 2012, 23:05
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66% (02:16) correct 34% (02:34) wrong based on 170 sessions
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After the price of chocolates was discounted by 40%, a shopper can buy 4 more chocolates for $12 than he could buy at the original price. How many chocolates could be bought for $12 at the original price? (A) 6 (B) 8 (C) 10 (D) 12 (E) 16
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Originally posted by actleader on 30 Oct 2012, 22:49.
Last edited by Bunuel on 30 Oct 2012, 23:05, edited 1 time in total.
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Re: After the price of chocolates was discounted by 40%, a shopp
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30 Oct 2012, 23:21
Price per chocolate = P, No. Of choclotaes = N PN = 12 0.6P(N+4) = 12 P(N+4) = 20 4P = 8 P=2 N=6 ANSWER IS A Kudos Please... If my post helped.
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Re: After the price of chocolates was discounted by 40%, a
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30 Oct 2012, 23:12
actleader wrote: After the price of chocolates was discounted by 40%, a shopper can buy 4 more chocolates for $12 than he could buy at the original price. How many chocolates could be bought for $12 at the original price?
(A) 6 (B) 8 (C) 10 (D) 12 (E) 16 Say for $12 at the original price a shopper can buy \(x\) chocolates, then, the original price is \(\frac{12}{x}\) and discounted price is \(0.6*\frac{12}{x}\). For $12 at the discounted price a shopper can buy \(\frac{12}{(\frac{0.6*12}{x})}=\frac{x}{0.6}=\frac{10x}{6}\) chocolates. Given that \(x+4=\frac{10x}{6}\) > \(x=6\). Answer: A. Hope it's clear.
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Re: After the price of chocolates was discounted by 40%, a
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31 Oct 2012, 12:31
Also we can solve it as following: [12][/P]  number of bars of chocolate can be bought originally, where P is price of one bar of chocolate 0.6*P  new, discounted price of bar of chocolate and 12/0.6*P  number of bars of chocolate we can buy or [20][/P].
We are at the middle of the task
[12][/6]  [20][/P] = 4 and the price of 1 bar of chocolate = 2
so originally we can buy [12][/2] = 6
the answer is A



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Re: After the price of chocolates was discounted by 40%, a
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04 Nov 2012, 12:30
(Q0 + 4) * 0.6* P0 = Q0 * P0 ==> Q0 = 6 Brother Karamazov



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Re: After the price of chocolates was discounted by 40%, a
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03 Jan 2014, 08:49
actleader wrote: After the price of chocolates was discounted by 40%, a shopper can buy 4 more chocolates for $12 than he could buy at the original price. How many chocolates could be bought for $12 at the original price?
(A) 6 (B) 8 (C) 10 (D) 12 (E) 16 What about this approach Since 0.6 P means a decrease of 40% then Q has to increase 40% 4 = 40%x then X is 10 Now since originally price was P then P will have to increase 40% Then we need to decrease Q again 40% So 0.6 Q = 6 Answer is A Bunuel, is this approach valid? Cheers J



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Re: After the price of chocolates was discounted by 40%, a
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03 Jan 2014, 09:00
jlgdr wrote: actleader wrote: After the price of chocolates was discounted by 40%, a shopper can buy 4 more chocolates for $12 than he could buy at the original price. How many chocolates could be bought for $12 at the original price?
(A) 6 (B) 8 (C) 10 (D) 12 (E) 16 What about this approach Since 0.6 P means a decrease of 40% then Q has to increase 40% 4 = 40%x then X is 10 Now since originally price was P then P will have to increase 40% Then we need to decrease Q again 40% So 0.6 Q = 6 Answer is A Bunuel, is this approach valid? Cheers J The price decreases 3/5 times, thus the quantity increases by 5/3 times > x+4=5/3*x > x=6.
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Re: After the price of chocolates was discounted by 40%, a
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19 May 2016, 07:03
actleader wrote: After the price of chocolates was discounted by 40%, a shopper can buy 4 more chocolates for $12 than he could buy at the original price. How many chocolates could be bought for $12 at the original price?
(A) 6 (B) 8 (C) 10 (D) 12 (E) 16 Let the Price of Chocolate before discount is x and after reduction it is .6x so Total no of chocolates which can be brought before discount is 12/x and after discount 12/.6x No of Chocolates brought after discount are 4 more than the number of chocolates brought before discount Hebce 12/.6x  12/x = 4 ===> 20/x12/x =4 ===> (2012)/x = 4 x=2 so Total number of chocolates brought before the price reduction is 12/2 = 6



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Re: After the price of chocolates was discounted by 40%, a
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19 May 2016, 09:27
Let the number of chocolates bought in $12= n Price for each chocolate= x nx= 12 After price reduction to .60x one can buy 4 more chocolate= n+4 xn=.6x(n+4) .4n=2.4 n=6
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Re: After the price of chocolates was discounted by 40%, a
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19 May 2016, 09:38
actleader wrote: After the price of chocolates was discounted by 40%, a shopper can buy 4 more chocolates for $12 than he could buy at the original price. How many chocolates could be bought for $12 at the original price?
(A) 6 (B) 8 (C) 10 (D) 12 (E) 16 Hi, another method If we read the info and the price involved is 12 in original and final scenario, it tells us that NOW you can buy 4 chocolates for 40% price, so for 100%, one can buy 4*100/40 = 10... But earlier he could buy 4 less so answer = 104 = 6 A
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Re: After the price of chocolates was discounted by 40%, a
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18 Oct 2016, 18:11
From the prompt we can derive the following equations:
PQ=12 (P0.40P)(Q+4) = 12
(0.60P)(Q+4)= 12 0.60PQ+2.4P= 12 7.2 + 2.4P = 12 2.4P = 4.8 P = 2 (original price)
12/2 = 6 (original quantity)



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After the price of chocolates was discounted by 40%, a
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13 Feb 2017, 12:39
To continue my correction spree: "an buy 4 more chocolates for $12 than he could"IMO the "for" induces the test taker in error. It indicates that each chocolate costs 12$. The correct word is "with" 12 dollars to clearly indicate that 12 refers to the total budget and not to the individual chocolate price. Am I the only one here?



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Re: After the price of chocolates was discounted by 40%, a
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04 Aug 2019, 08:10
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Re: After the price of chocolates was discounted by 40%, a
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