Last visit was: 18 Nov 2025, 20:13 It is currently 18 Nov 2025, 20:13
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
yikes000
Joined: 29 Dec 2023
Last visit: 08 Mar 2024
Posts: 19
Own Kudos:
554
 [69]
Given Kudos: 1
Posts: 19
Kudos: 554
 [69]
3
Kudos
Add Kudos
66
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
KLSVGMAT
Joined: 13 Aug 2023
Last visit: 27 Feb 2024
Posts: 1
Own Kudos:
9
 [9]
Given Kudos: 5
Posts: 1
Kudos: 9
 [9]
8
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
General Discussion
User avatar
yikes000
Joined: 29 Dec 2023
Last visit: 08 Mar 2024
Posts: 19
Own Kudos:
Given Kudos: 1
Posts: 19
Kudos: 554
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
nyota.benson
Joined: 31 Jul 2023
Last visit: 26 Jan 2024
Posts: 9
Own Kudos:
Given Kudos: 5
Posts: 9
Kudos: 23
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Yeah this would need an explanation.
User avatar
chetan2u
User avatar
GMAT Expert
Joined: 02 Aug 2009
Last visit: 15 Nov 2025
Posts: 11,238
Own Kudos:
43,696
 [3]
Given Kudos: 335
Status:Math and DI Expert
Location: India
Concentration: Human Resources, General Management
GMAT Focus 1: 735 Q90 V89 DI81
Products:
Expert
Expert reply
GMAT Focus 1: 735 Q90 V89 DI81
Posts: 11,238
Kudos: 43,696
 [3]
2
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
yikes000
Although large mammals like elephants and whales tend to live longer than small ones like mice, larger breeds of dogs have shorter life spans, on average, than smaller breeds. A researcher studying the relationship between average body mass and average life span in breeds of dogs concluded that, for every 2 kilograms of body mass, life span is 1 month less. According to this conclusion, the average life span of a breed with an average body mass of x kg is y months less than the average life span of a breed with an average body mass of 10 kg.

Select for x and for y values that are jointly consistent with the information provided. Make only two selections, one in each column.

Attachment:
DI - 6.png

Select for x and for y values that are jointly consistent with the information provided. Make only two selections, one in each column.
These type of questions are quite regular in focus edition test. The wording tells us that there are various possibilities for x and y, and just one of them is in option.

Only way to do this is by finding the relation between x and y.

x: Average life body mass
y: Difference in life span

For every increase in 2kg mass, life span decreases by 1 month.
So (Mass increase)=\(M_1-M_2=2y\)
Now mass is increasing from 10 to x, so
\(M_1-M_2=x-10=2y\)
\(x=2y+10\)

We can check options now.
x is surely even and larger than y.
so x can be 30 or 20
x=20: 20=2y+10 or y=5…..Not in options
x=30: 30=2y+10 or y=10…..Yes

Answer:
y=10
x=30
User avatar
sayan640
Joined: 29 Oct 2015
Last visit: 10 Nov 2025
Posts: 1,180
Own Kudos:
Given Kudos: 783
GMAT 1: 570 Q42 V28
Products:
GMAT 1: 570 Q42 V28
Posts: 1,180
Kudos: 813
Kudos
Add Kudos
Bookmarks
Bookmark this Post
For every 2 kgs , life span is 1 month less.

Hence , for every extra 10 kgs , life span 10/2 = 5 months less.

But see , y is not 5 in any of the options.

Hence , x=10 + 10 = 20 can be ruled out.

Try with x= 30 , In that case the extra will be = 30 -10 = 20 kgs ( Since we are comparing with a 10 kg breed)

Hence , for every extra 20 kgs , life span will be 20/2 = 10 months less.

y=10 ; x= 30

Note you cant try with x=15 or 25 as they are not even divisible by 2 and no option in y is given in decimals.
GMATinsight
User avatar
HarshZsssh
Joined: 20 Aug 2024
Last visit: 12 Apr 2025
Posts: 42
Own Kudos:
Given Kudos: 24
Posts: 42
Kudos: 10
Kudos
Add Kudos
Bookmarks
Bookmark this Post
is there any trick to solve these kind of ques like at first glance my mind stop working after seeing the question how can i solve this but after seeing ur it felt lott easier
sayan640
For every 2 kgs , life span is 1 month less.

Hence , for every extra 10 kgs , life span 10/2 = 5 months less.

But see , y is not 5 in any of the options.

Hence , x=10 + 10 = 20 can be ruled out.

Try with x= 30 , In that case the extra will be = 30 -10 = 20 kgs ( Since we are comparing with a 10 kg breed)

Hence , for every extra 20 kgs , life span will be 20/2 = 10 months less.

y=10 ; x= 30

Note you cant try with x=15 or 25 as they are not even divisible by 2 and no option in y is given in decimals.
GMATinsight
User avatar
MartyMurray
Joined: 11 Aug 2023
Last visit: 18 Nov 2025
Posts: 1,630
Own Kudos:
6,117
 [3]
Given Kudos: 173
GMAT 1: 800 Q51 V51
Expert
Expert reply
GMAT 1: 800 Q51 V51
Posts: 1,630
Kudos: 6,117
 [3]
3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Although large mammals like elephants and whales tend to live longer than small ones like mice, larger breeds of dogs have shorter life spans, on average, than smaller breeds. A researcher studying the relationship between average body mass and average life span in breeds of dogs concluded that, for every 2 kilograms of body mass, life span is 1 month less. According to this conclusion, the average life span of a breed with an average body mass of x kg is y months less than the average life span of a breed with an average body mass of 10 kg.

Select for x and for y values that are jointly consistent with the information provided. Make only two selections, one in each column.


Find the relationship between \(x\) and \(y\)

From the passage:

for every 2 kilograms of body mass, life span is 1 month less

So, with regard to specifics of the question, for every 2 kilograms of body mass over 10 kilograms, the lifespan will be 1 month less than the lifespan of a breed with a body mass of 10 kilograms.

Thus, the relationship between \(x\) and \(y\) is the following:

\(\frac{x - 10}{2} = y\)

Find two values in the list that fit the relationship

10

15

20

25

30

35


Since \(\frac{x - 10}{2} = y\), \(x = 2y + 10\).

The smallest possible \(y\) is \(10\). So, the smallest possible \(x\) is \(2(10) + 10 = 30\).

\(\frac{30 - 10}{2} = 10\)

We see that \(x = 30\) and \(y = 10\) fit the relationship.

Correct answer: 30, 10
User avatar
DonBosco7
Joined: 03 Mar 2020
Last visit: 18 Nov 2025
Posts: 81
Own Kudos:
Given Kudos: 84
Products:
Posts: 81
Kudos: 15
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Although large mammals like elephants and whales tend to live longer than small ones like mice, larger breeds of dogs have shorter life spans, on average, than smaller breeds. A researcher studying the relationship between average body mass and average life span in breeds of dogs concluded that, for every 2 kilograms of body mass, life span is 1 month less. According to this conclusion, the average life span of a breed with an average body mass of x kg is y months less than the average life span of a breed with an average body mass of 10 kg.

I solved it as such:
1] given that for every 2 kilograms of body mass, life span is 1 month less:- this line essentially gives you the ratio between BM (body mass) and LS (life span)

---------> hence BM/LS = 2/1

2] According to this conclusion, the average life span of a breed with an average body mass of x kg is y months less

----------> can be written as BM/LS = x/y

3] But additional info added to the above statement is that of a comparison or difference with a breed having a body mass 10 kg

----------> can be written as BM/LS = x-10/y

----------> x-10/y = 2/1

----------> x-10 = 2y

Now check the option for x and y

----------> 30-10 = 2(10)

hence, x = 30 & y = 10
User avatar
adi007
Joined: 08 Oct 2016
Last visit: 18 Nov 2025
Posts: 23
Own Kudos:
2
 [1]
Given Kudos: 40
Posts: 23
Kudos: 2
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Its simple when thinks in terms of equation.
2 kg -> a - 1(month)
a is just the constant from which we will subtract 1 month.
10 kg = a - 5
x = (a-5) - y (via 10kg case) = a - x/2 (via x case)
x = 10 + 2 y ( Final equation)
Now just check which solution satisfy this equation.
x = 30 and y = 10 Ans
Moderators:
Math Expert
105355 posts
496 posts