Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 2007:30 AM PST
-08:30 AM PST
Learn what truly sets the UC Riverside MBA apart and how it helps in your professional growth
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
10 Dec 2019, 02:04
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
51% (02:39) correct
49%
(02:25)
wrong
based on 240
sessions
History
Date
Time
Result
Not Attempted Yet
Among all the students at a certain high school, the probability of picking a left-handed student is \(\frac{1}{4}\), and the probability of picking a student who is learning Spanish is \(\frac{2}{3}\) Which of the following could be the probability of picking a student who is either left-handed or learning Spanish or both?
I. \(\frac{2}{3}\)
II. \(\frac{3}{4}\)
III. \(\frac{5}{6}\)
A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III
Are You Up For the Challenge: 700 Level Questions
I. \(\frac{2}{3}\)
II. \(\frac{3}{4}\)
III. \(\frac{5}{6}\)
A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III
Are You Up For the Challenge: 700 Level Questions
15 Dec 2019, 01:51
Kudos
Bookmarks
Assume total students = LCM(3,4)=12
\(N(l)= \frac{1}{4}*12=3\)
\(N(s)= \frac{2}{3}*12=8\)
We need the minimum and maximum value of [N(l) U N(s)]
[N(l) U N(s)]= N(l) + N(s) - [N(l) ∩ N(s)]
1. For the maximum value, minimize [N(l) ∩ N(s)].
Minimum possible value of [N(l) ∩ N(s)]=0
[N(l) U N(s)]= N(l) + N(s)-0
[N(l) U N(s)]= 3+8=11
2. For the minimum value, maximize [N(l) ∩ N(s)].
Maximum possible value of [N(l) ∩ N(s)]=3
[N(l) U N(s)]= N(l) + N(s)-3
[N(l) U N(s)]= 3+8-3=8
probability of picking a student who is either left-handed or learning Spanish or both = P
\(\frac{8}{12} ≤ P ≤ \frac{11}{12}\)
All 3 options lie in the range.
\(N(l)= \frac{1}{4}*12=3\)
\(N(s)= \frac{2}{3}*12=8\)
We need the minimum and maximum value of [N(l) U N(s)]
[N(l) U N(s)]= N(l) + N(s) - [N(l) ∩ N(s)]
1. For the maximum value, minimize [N(l) ∩ N(s)].
Minimum possible value of [N(l) ∩ N(s)]=0
[N(l) U N(s)]= N(l) + N(s)-0
[N(l) U N(s)]= 3+8=11
2. For the minimum value, maximize [N(l) ∩ N(s)].
Maximum possible value of [N(l) ∩ N(s)]=3
[N(l) U N(s)]= N(l) + N(s)-3
[N(l) U N(s)]= 3+8-3=8
probability of picking a student who is either left-handed or learning Spanish or both = P
\(\frac{8}{12} ≤ P ≤ \frac{11}{12}\)
All 3 options lie in the range.
Bunuel
General Discussion
10 Dec 2019, 07:56
Kudos
Bookmarks
Bunuel
Use 2 by 2 matrix
Let the total number be 120 as the fractions have denominator 3 and 4
............S........NS
L...........b....... a.....\(120*\frac{1}{4}=30\)
R..........c.........d.... \(90\)
Total.....80......40....\(120\)
Now we are looking at
\(\frac{(a+b+c)}{120}\)
Least value will be when a=0 and b=30 and c=50....\(\frac{80}{120}=\frac{2}{3}\)
Greatest value will be when b=0 and a=30 and c=80...\(\frac{(80+30)}{120}=\frac{11}{12}\)
All the fractions are within this range, so E
Let us test
I. \(\frac{2}{3}\)....b=30, a=0 and c=50
II. \(\frac{3}{4}\).... b=20, a=10 and c=60
III. \(\frac{5}{6}\)...b=10, a=20 and c=70
