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Amy's grade was 90th percentile of the 80 grades for her

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Senior Manager
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Amy's grade was 90th percentile of the 80 grades for her [#permalink]

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New post 09 Oct 2008, 09:07
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Amy's grade was 90th percentile of the 80 grades for her class. Of the 100 grades from another class, 19 were higher than Amy's, and the rest were lower. If no other grade was the same as Amy's grade, then Amy's grade was what percentile of the grades of the two classes of two classes combined?

A) 72nd
B) 80th
C) 81st
D) 85th
E) 92nd

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Re: gmat prep question [#permalink]

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New post 09 Oct 2008, 09:18
Answer avg percentile is 85.

Explanation:
==========
In the first class Amy's percentile is 90.

In the second class, amy's percentile is obviously 81.

the combiled avg percentile is 85.

thanks
SM

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Re: gmat prep question [#permalink]

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New post 09 Oct 2008, 09:19
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Nihit wrote:
Amy's grade was 90th percentile of the 80 grades for her class. Of the 100 grades from another class, 19 were higher than Amy's, and the rest were lower. If no other grade was the same as Amy's grade, then Amy's grade was what percentile of the grades of the two classes of two classes combined?

A) 72nd
B) 80th
C) 81st
D) 85th
E) 92nd



My answer is D (85th percentile)

this is how i did it. Combining the grades of both classes, there are 27 grades above amy. finding the percentile of 27 grades gives us 15 percentile. so 15 percent grades are above her so amy is at the 85th percentile.

let me know if the answer is correct.

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Senior Manager
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Re: gmat prep question [#permalink]

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New post 09 Oct 2008, 09:32
Can anyone explain how to do this question by weighted average method?

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Re: gmat prep question [#permalink]

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New post 09 Oct 2008, 10:30
Nihit wrote:
Amy's grade was 90th percentile of the 80 grades for her class. Of the 100 grades from another class, 19 were higher than Amy's, and the rest were lower. If no other grade was the same as Amy's grade, then Amy's grade was what percentile of the grades of the two classes of two classes combined?

A) 72nd
B) 80th
C) 81st
D) 85th
E) 92nd


Find Amy's real position in her class.

90% / 100% = x / 80
x = 90 * 80 / 100
x = 72

Amy's rank is 72. So, there are 8 people who above her.

In another class, there are 19 people who above her.

Total students = 80 + 100 = 180
Her rank when two classes combined = 180 - 19 - 8 = 153

Her percentile = 153 x 100% / 180 = 85th

The answer is D.

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Re: gmat prep question [#permalink]

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New post 09 Oct 2008, 10:42
Nihit wrote:
Can anyone explain how to do this question by weighted average method?


The weighed average method should not be used because there is no arithmetic mean involved in this questions. 8-)

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Re: gmat prep question   [#permalink] 09 Oct 2008, 10:42
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Amy's grade was 90th percentile of the 80 grades for her

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