Last visit was: 02 Sep 2026, 03:48 It is currently 02 Sep 2026, 03:48
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 02 Sep 2026
Posts: 113,029
Own Kudos:
838,548
 [9]
Given Kudos: 111,268
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 113,029
Kudos: 838,548
 [9]
1
Kudos
Add Kudos
8
Bookmarks
Bookmark this Post
User avatar
freedom128
Joined: 30 Sep 2017
Last visit: 01 Oct 2020
Posts: 939
Own Kudos:
1,395
 [3]
Given Kudos: 402
GMAT 1: 720 Q49 V40
GPA: 3.8
Products:
GMAT 1: 720 Q49 V40
Posts: 939
Kudos: 1,395
 [3]
1
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
User avatar
exc4libur
Joined: 24 Nov 2016
Last visit: 22 Mar 2022
Posts: 1,678
Own Kudos:
1,494
 [2]
Given Kudos: 607
Location: United States
Posts: 1,678
Kudos: 1,494
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
MayankSingh
Joined: 08 Jan 2018
Last visit: 20 Dec 2024
Posts: 289
Own Kudos:
279
 [1]
Given Kudos: 249
Location: India
Concentration: Operations, General Management
GMAT 1: 640 Q48 V27
GMAT 2: 730 Q51 V38
GPA: 3.9
WE:Project Management (Manufacturing)
Products:
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
IMO E

N = {N1, N2, N3 ,................., N9 } [assume 9 elements]
N1-N9 : Negative integers ; Common difference = D (+ve)
P= {P1, P2, ..........................,P9}
P1-P9 : Positive integers ; Common difference = K (+ve)


(1) The sum of the largest term of the sequence N and the smallest term of the sequence P is zero.
N9+P1=0
N9= - P1

------(N9-D).........N9............0.........N1..........(N1+K)
To be an AP,
D=(N1-N9)=K
So not sufficient

(2) For every integer in sequence N, there exists an integer in sequence P with the same magnitude.
C= { -8,-6,-4 , 4, 6, 8 } - Not in AP
C= {-12,-4,4,12} - In AP
Not sufficient

Together:C= { -8,-6,-4 , 4, 6, 8 } - Not in AP
C= {-12,-4,4,12} - In AP
Not sufficient.
User avatar
aka007
Joined: 15 Nov 2019
Last visit: 19 Mar 2026
Posts: 42
Own Kudos:
37
 [1]
Given Kudos: 84
Posts: 42
Kudos: 37
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
IMO the answer is E

S1:
largest term on N is -1 & smallest of P is +1 (condition of S1 satisfied)
now, whether C is a AP or not entirely depends on the common difference D.
If the next term on N is -2 whereas the next term on P is +5. NOT AP
If N (-3,-1) and P (1,3) then yes AP

Hence the statement is not sufficient.

S2:

the terms are of equal magnitude
N(-3,-1) and P (1,3) yes AP
N(-2,-1) and P (1,2) no AP

statement is not sufficient

Combining both the statements we do not get any addl value, therefore the answer is E
User avatar
Lipun
Joined: 05 Jan 2020
Last visit: 08 Jan 2025
Posts: 141
Own Kudos:
167
 [1]
Given Kudos: 291
Posts: 141
Kudos: 167
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Let S(N)=N1+(N-1)C1, N1 is the first term
Let S(P)=P1+(P-1)C2, P1 is the first term

1. Given the largest of S(N) is equal to smallest of S(P)
No info about the constants. Not sufficient.

2. Given for every integer in S(N), there is an integer value in S(P) having same magnitude.
If C1=4 and C2=2, then also the above statement holds good, but the set S(C) will not be in arithmetic sequence.

Considering 1 and 2 together also not sufficient info.

Note: For the overall sequence S(C) to be in arithmetic sequence, largest of S(N) - smallest of S(P) = C1 = C2
avatar
Vigasimrair
Joined: 06 Feb 2019
Last visit: 26 Mar 2021
Posts: 36
Own Kudos:
37
 [1]
Given Kudos: 370
Location: Russian Federation
GMAT 1: 690 Q45 V40
GMAT 1: 690 Q45 V40
Posts: 36
Kudos: 37
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
the answer is E.
Let's imagine that we have the following 2 sequences:

First case
(N) -10; -8; -6
(P) 6;8;10

or the following 2 sequences:

Second case
(N) -7; -5; -3; -1;
(P) 1;3;5;7

Both pieces of information are not sufficient, because in the first case we don't have an arithmetic sequence and in the second case we have arithmetic sequence.
User avatar
debjit1990
Joined: 26 Dec 2017
Last visit: 17 Jul 2026
Posts: 256
Own Kudos:
Given Kudos: 22
Location: India
GMAT 1: 580 Q42 V27
Products:
GMAT 1: 580 Q42 V27
Posts: 256
Kudos: 287
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Ans: B

Statement 1: The sum of the largest term of the sequence N and the smallest term of the sequence P is zero.

N={-9,-7,-5,-3,-1}
P={1,2,3,4,5}
C={-9,-7,-5,-3,-1,1,2,3,4,5}, so C is not an arithmatic sequence
N={-9,-7,-5,-3,-1}
P={1,3,5,7,9}
C={-9,-7,-5,-3,-1,1,3,5,7,9}, so C is an arithmatic sequence

No Statement 1 not sufficient.

(2) For every integer in sequence N, there exists an integer in sequence P with the same magnitude.
N={-9,-7,-5,-3,-1}
P={1,3,5,7,9}
C={-9,-7,-5,-3,-1,1,3,5,7,9}, so C is an arithmatic sequence
Sufficient.
User avatar
gullyboy09
Joined: 13 Oct 2025
Last visit: 01 Sep 2026
Posts: 297
Own Kudos:
Given Kudos: 71
Products:
Posts: 297
Kudos: 24
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi Bunuel, how come C can have same number of terms as N and P if both N and P have different set of numbers.
User avatar
egmat
User avatar
e-GMAT Representative
Joined: 02 Nov 2011
Last visit: 02 Sep 2026
Posts: 6,287
Own Kudos:
Given Kudos: 715
GMAT Date: 08-19-2020
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 6,287
Kudos: 33,890
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi gullyboy09,

This one is just a wording knot, not a math trap, so let's untangle the sentence itself.

The phrase "the number of terms in sequence C is equal to the number of terms in arithmetic sequences N and P" does not mean C matches N's count and P's count separately. It means C's count equals the combined total of N's terms plus P's terms.

In other words, the line is just telling you that C is the simple merge of N and P with nothing dropped and nothing duplicated:

- count(C) = count(N) + count(P)

The reason they bother to say this is to rule out any overlap. Since every term of N is negative and every term of P is positive, the two sets can never share a number, so when you pour both into C, you keep all of them.

Quick check with tiny numbers:
- N = {-3, -1} - 2 terms
- P = {1, 3} - 2 terms
- C = {-3, -1, 1, 3} - 4 terms

That 4 is exactly 2 + 2 - the terms of N and P, all present. So C always lines up, smallest to largest, as: all of N, then all of P.

Once you read it that way, the actual question becomes clean: C is the full negative-then-positive list, and you're just asking whether that whole list keeps one common difference - which is where statements (1) and (2) come in.

Answer: E

gullyboy09
Hi Bunuel, how come C can have same number of terms as N and P if both N and P have different set of numbers.
Moderators:
Math Expert
113029 posts
DI Forum Moderator
410 posts