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# Ann and Bob drive separately to a meeting. Ann s average driving speed

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Re: Ann and Bob drive separately to a meeting. Ann s average driving speed [#permalink]
Ann Bob
Speed 4 3
Distance 2 1
Time 2/4 1/3
1/2 1/3
3 2

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Re: Ann and Bob drive separately to a meeting. Ann s average driving speed [#permalink]
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Since the question provides data about the ratio of the speeds and the distances, it’s a good idea to work with the ratios given.

Ann’s average speed is greater than Bob’s average speed by $$\frac{1}{3}$$rd of Bob’s average driving speed. For example, if Bob’s average speed is 3 mph, Ann’s average speed is 4 mph.

$$\frac{Speed of Ann }{ Speed of Bob}$$ = $$\frac{4}{3}$$. Let’s say these speeds are 4x and 3x mph respectively

Ann drives twice as many miles as Bob i.e. Ann = 2 * Bob.

$$\frac{Distance by Ann }{ Distance by Bob}$$ = $$\frac{2}{1}$$. Let’s say these distances are 2y and y miles respectively.

Time taken = $$\frac{Distance }{ Speed}$$

Time taken by Ann = $$\frac{2y }{ 4x}$$ hours and Time taken by Bob =$$\frac{ y }{ 3x}$$ hours.

Therefore, ratio of time taken by Ann and Bob = $$\frac{2y }{ 4x}$$ * $$\frac{3x }{ y}$$ = $$\frac{3}{2}$$ or 3:2.

The correct answer option is B.

Hope that helps!
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Re: Ann and Bob drive separately to a meeting. Ann s average driving speed [#permalink]
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Re: Ann and Bob drive separately to a meeting. Ann s average driving speed [#permalink]
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