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30 Jun 2017, 02:26
00:00

Difficulty:

5% (low)

Question Stats:

87% (01:51) correct 13% (02:31) wrong based on 89 sessions

### HideShow timer Statistics

Ann, Carol, and Judy paid a total of $45 for their dinner at a restaurant. If Ann paid (2/5)th of what Judy paid, Carol paid$17 and Judy paid the rest, what fraction of the total amount did Judy pay?

(A) 2/9
(B) 14/45
(C) 1/3
(D) 2/5
(E) 4/9

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30 Jun 2017, 03:12
1
Bunuel wrote:
Ann, Carol, and Judy paid a total of $45 for their dinner at a restaurant. If Ann paid (2/5)th of what Judy paid, Carol paid$17 and Judy paid the rest, what fraction of the total amount did Judy pay?

(A) 2/9
(B) 14/45
(C) 1/3
(D) 2/5
(E) 4/9

Let's Assume Judy's share is = 5x
So, Ann's share would be = $$\frac{2}{5}$$ 5x = 2x

Thus,
2x + 5x + 17 = 45
2x + 5x = 28
7x = 28
x = 4

Judy's Contribution = 5x = 5.4 = 20
Judy's Contribution (%) = $$\frac{20}{45}$$ = $$\frac{4}{9}$$

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30 Jun 2017, 08:13
Bunuel wrote:
Ann, Carol, and Judy paid a total of $45 for their dinner at a restaurant. If Ann paid (2/5)th of what Judy paid, Carol paid$17 and Judy paid the rest, what fraction of the total amount did Judy pay?

(A) 2/9
(B) 14/45
(C) 1/3
(D) 2/5
(E) 4/9

Let contributions be -

Judy = $$5x$$
Ann = $$2x$$
Carol = $$17$$

SO, we have $$5x + 2x + 17 = 45$$

Or, $$7x = 28$$

Or, $$x = 4$$

So, Judy paid 20 ...

Quote:
what fraction of the total amount did Judy pay?

= $$\frac{20}{45}$$

= $$\frac{4}{9}$$

Thus, the correct answer must be (E) $$\frac{4}{9}$$
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