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gmatbusters

Are there exactly 3 distinct symbols used to create the code words in language Q?

(1) The set of all code words in language Q is the set of all possible distinct horizontal arrangements of one or more symbols, with no repetition.
(2) There are exactly 15 code words in language Q

(1) The set of all code words in language Q is the set of all possible distinct horizontal arrangements of one or more symbols, with no repetition: here there could be a number of symbols, ie. 1 symbol {A}=1 arrangement/code word; 2 symbols {A,B}={A,B,AB,BA}=4 arrangements/code words; insufic.

(2) There are exactly 15 code words in language Q: we don't know how many symbols there are, insufic.

(1&2) our set has 15 code words, and they are equal to all possible distinct horizontal arrangements of one or more symbols;
if we have 1 symbol, call this {A}, then our set of "code words" and of "all possible distinct horizontal arrangements" is {A}=1
if we have 2 symbols, call them {A,B}, then our sets will have {A,B,AB,BA}=4
if we have 3 symbols, call them {A,B,C}, then our sets will have {3C1+3C2+3C3=3+3+1}=7
if we have 4 symbols, call them {A,B,C,D}, then our sets will have {4C1+4C2+4C3+4C4=4+6+4+1}=15, this is it.

Answer (C)
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gmatbusters

Are there exactly 3 distinct symbols used to create the code words in language Q?

(1) The set of all code words in language Q is the set of all possible distinct horizontal arrangements of one or more symbols, with no repetition.
(2) There are exactly 15 code words in language Q

(1) The set of all code words in language Q is the set of all possible distinct horizontal arrangements of one or more symbols, with no repetition: here there could be a number of symbols, ie. 1 symbol {A}=1 arrangement/code word; 2 symbols {A,B}={A,B,AB,BA}=4 arrangements/code words; insufic.

(2) There are exactly 15 code words in language Q: we don't know how many symbols there are, insufic.

(1&2) our set has 15 code words, and they are equal to all possible distinct horizontal arrangements of one or more symbols;
if we have 1 symbol, call this {A}, then our set of "code words" and of "all possible distinct horizontal arrangements" is {A}=1
if we have 2 symbols, call them {A,B}, then our sets will have {A,B,AB,BA}=4
if we have 3 symbols, call them {A,B,C}, then our sets will have {3C1+3C2+3C3=3+3+1}=7
if we have 4 symbols, call them {A,B,C,D}, then our sets will have {4C1+4C2+4C3+4C4=4+6+4+1}=15, this is it.

Answer (C)
I think we should use permutation. 3P1 + 3P2 + 3P3 = 15 for set containing 3 code words.
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Asked: Are there exactly 3 distinct symbols used to create the code words in language Q?


(1) The set of all code words in language Q is the set of all possible distinct horizontal arrangements of one or more symbols, with no repetition.
No numbers are given
NOT SUFFICIENT

(2) There are exactly 15 code words in language Q
It is not provided how code words are formed
NOT SUFFICIENT

(1) + (2)
(1) The set of all code words in language Q is the set of all possible distinct horizontal arrangements of one or more symbols, with no repetition.
(2) There are exactly 15 code words in language Q
If there are 3 distinct symbols
Number of 1 symbol code words = 3
Number of 2 symbol code words = 3*2 = 6
Number of 3 symbol code words = 3*2*1 = 6
Total codewords = 3 + 6+ 6 = 15
If the number of distinct symbols differ, then Total codewords will be different than 15.
SUFFICIENT

IMO C
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Are there exactly 3 distinct symbols used to create the code words in language Q?

(1) The set of all code words in language Q is the set of all possible distinct horizontal arrangements of one or more symbols, with no repetition.

(2) There are exactly 15 code words in language Q­


Statement 1:
No information about the number of code words present

Statement 2:
No information about the number of symbols present. There could be 15, there could be 3.

Combing:
3C1 + 3C2 * 2! + 3C3 = 3 + 6 + 6 = 15

thus C
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All explanations above which are using C (combination) are not good.

In this question, we should use P (permuatation) because we have to take the order of the code into account.

Of course we can use C * n! method, but it makes things more difficult.
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