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# area

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Manager
Joined: 04 Sep 2006
Posts: 113

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04 Jun 2009, 11:35
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In triangle ABC, D is the middle point of AC, E is the middle point of BC, and F is the middle point of CD (Not AB). What is the ratio of the area of ABC to that of FBC?

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Senior Manager
Joined: 16 Jan 2009
Posts: 339
Concentration: Technology, Marketing
GMAT 1: 700 Q50 V34
GPA: 3
WE: Sales (Telecommunications)

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04 Jun 2009, 13:50
Thats a toug one!!
Could you please post source / OA / explanation?
_________________

Lahoosaher

Intern
Joined: 10 Jun 2009
Posts: 3

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10 Jun 2009, 12:11

I sketched it like an isosceles triangle.

Area of ABC:
Let base = AC = X
Area ABC = 1/2 (X) h

Area of FBC:
Let base = FC = [AC / 2] / 2 = [X/2]/2 = X/4
Area of FBC = 1/2 (X/4) h

Compare:
1/2 (X) h : 1/2 (X/4) h
X : X/4
4X : 1X
Intern
Joined: 03 Jun 2009
Posts: 47

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10 Jun 2009, 12:32
IMO Area od ABC : Area of FBC = 4:1

My approach was....

Let Area of Abc be X.

=> Area of BDC = x/2 (since BD divides ABC into 2 equal halves)

=> Area of BFC = x/4 (since BF divides BDC into 2 equal halves)

Therefore Area of ABC : Area of BFC = x:x/4 = 4:1

Wats the OA??
Manager
Joined: 28 Jan 2004
Posts: 198
Location: India

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10 Jun 2009, 15:12
Pls. post the OA.This is a good and a tricky question.
Intern
Joined: 10 Jun 2009
Posts: 29
Location: Stockholm, Sweden

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11 Jun 2009, 02:50
The answer is 4:1 only if AB = BC. If you divide the triangle in half ABD and DBC share one side, DB, while one side of each triangle, AD & DC, has the same lenght. The ratio of the remaining side of each triangle, AB and BC, can have an infinite number of values. Since you can compute the area of a triangle using the lenght of all three sides the ratio of the area the two triangles must have an infinite number of values, depending of what kind of triangle that is originally used in the question (which is not mentioned here).

Please take note that English is not my native language
Director
Joined: 13 Nov 2003
Posts: 778
Location: BULGARIA

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11 Jun 2009, 07:34
Hi,

I will try to explain my solution:

Since DE connects the centers of AC and BC then it is parralel to AB and is 1/2 AB. Then Triangle DEC has area 1/4 of the area of ABC.
Now Triangle DFC has the same area as triangle FCE since DF=FE and the height is same.
Triangle FCE has the same area as triangle FBE since BE=EC and height is the same.
So triangles DFC, FCE and FBE have same areas.
Then the area of FBC= area DCE and the ratio is 4/1

Regards

--== Message from GMAT Club Team ==--

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Re: area &nbs [#permalink] 11 Jun 2009, 07:34
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