NaeemHasan wrote:
VeritasPrepKarishma wrote:
harikris wrote:
Arrow AB which is a line segment exactly 5 units along with an arrowhead at A is to be constructed in the xy-plane. The x and y coordinates of A and B are to be integers that satisfy the inequalities 0 ≤ x ≤ 9 and 0 ≤ y ≤ 9. How many different arrows with these properties can be constructed ?
A. 50
B. 168
C. 200
D. 368
E. 536
Consider the diagram.
The arrows could be vertical, horizontal or diagonal.
Attachment:
Ques4.jpg
The vertical arrows are shown by the blue arrows. 5 of them will start from x = 0, 5 from x = 1 and so on till x = 9. So you have 50 of these blue arrows. You have another 50 vertical arrows which are the same arrows but with the arrow head on the opposite end (shown by the red arrow). So you have a total of 100 vertical arrows.
Similarly, you have 100 horizontal arrows.
Now check out the diagonal arrows. One co-ordinate should be of length 3 and another of 4 (so that the arrow length is 5 and all points are integers). Look at the purple arrows. The x co-ordinate is 3 and the y co-ordinate is 4. You can make 7*6 = 42 such arrows. Similarly, you can make 42 arrows with x cor-ordinate as 4 and y co-ordinate as 3. So you have 84 arrows. But you get another set of 84 arrows by keeping the arrows the same but putting the arrow head on the opposite end so you get a total of 2*84 = 168 arrows.
Similarly, you can make arrows in the opposite direction shown by the green arrows. So you have another 168 arrows.
Total = 100 + 100 + 168 + 168 = 536
Hi Karishma,
Can't the arrows start from point (1,2), (1,3), (2,3) etc.
Yes, they can. In the solution above:
"...5 of them will start from x = 0, 5 from x = 1 and so on till x = 9. So you have 50 of these blue arrows. "
5 will start from x = 0. For these, y will be 0, 1, 2, 3 and 4.
So the arrows will start from (0, 0), (0, 1), (0, 2) etc
5 will start from x = 1. For these too, y will be 0, 1, 2, 3 and 4.
So the arrows will start from (1, 0), (1, 1), (1, 2) etc
Similarly, arrows will start from (2, 0), ... (2, 4), ... (3, 0) ... etc
Does this help?
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