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In order to prove the third statement 1.e y>3, you are assuming x=0. Is this allowed to assume x=0.

Thanks & regards, Sunil01

So we need to figure out whether y must be greater than 3. So I think to myself - what is so great about y = 3 that it cannot happen while y = 4 can probably happen? That is why I put y = 3 and see the numbers I get.

If y = 3, total earning = 20 + 3*6 = 38 I know that this week he earned more than twice of last week. So if he sold 3 bikes this week, he must have earned less than $19 last week. But last week he MUST have earned at least $20, right? That is his fixed salary. This is the reason y cannot be 3 or less. It MSUT be more than 3. We don't assume that x is 0. We say that even if x = 0, his last week's salary cannot be $19. This means he sold at least 4 bikes this week.
_________________

Re: As a bicycle salesperson, Norman earns a fixed salary of $20 [#permalink]

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17 Feb 2016, 01:02

VeritasPrepKarishma wrote:

Sunil01 wrote:

Hi Karishma and Bunuel,

In order to prove the third statement 1.e y>3, you are assuming x=0. Is this allowed to assume x=0.

Thanks & regards, Sunil01

So we need to figure out whether y must be greater than 3. So I think to myself - what is so great about y = 3 that it cannot happen while y = 4 can probably happen? That is why I put y = 3 and see the numbers I get.

If y = 3, total earning = 20 + 3*6 = 38 I know that this week he earned more than twice of last week. So if he sold 3 bikes this week, he must have earned less than $19 last week. But last week he MUST have earned at least $20, right? That is his fixed salary. This is the reason y cannot be 3 or less. It MSUT be more than 3. We don't assume that x is 0. We say that even if x = 0, his last week's salary cannot be $19. This means he sold at least 4 bikes this week.

In order to prove the third statement 1.e y>3, you are assuming x=0. Is this allowed to assume x=0.

Thanks & regards, Sunil01

So we need to figure out whether y must be greater than 3. So I think to myself - what is so great about y = 3 that it cannot happen while y = 4 can probably happen? That is why I put y = 3 and see the numbers I get.

If y = 3, total earning = 20 + 3*6 = 38 I know that this week he earned more than twice of last week. So if he sold 3 bikes this week, he must have earned less than $19 last week. But last week he MUST have earned at least $20, right? That is his fixed salary. This is the reason y cannot be 3 or less. It MSUT be more than 3. We don't assume that x is 0. We say that even if x = 0, his last week's salary cannot be $19. This means he sold at least 4 bikes this week.

Nicely explained thanks Karishma

Hi, although the explanation is almost same as a post above this explanation, but since you did not understand my English, I got to start looking into my Verbal .. Kidding... Till the time you are learning, its ok, and I am sure none is contributing for appreciation. _________________

Re: As a bicycle salesperson, Norman earns a fixed salary of $20 [#permalink]

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10 Jul 2016, 02:11

I got this as the last qn (7#) or one before last .. Is it better to mark last 3-4 qns randomly when the time left is around 3 minutes or attend a qn or two properly in those three minutes and and leave the last 1/2 qn ? Experts pls advise.

I got this as the last qn (7#) or one before last .. Is it better to mark last 3-4 qns randomly when the time left is around 3 minutes or attend a qn or two properly in those three minutes and and leave the last 1/2 qn ? Experts pls advise.

If you are left with just a few mins with 3-4 questions in hand, try to give a quick shot to each. Read the question stem and you might be able to narrow down the choices based on some simple logic. Take a guess out of those and move on. It increases the probability of a correct answer. Don't leave 1-2 questions unanswered at the end. Try to take a smart guess.
_________________

Re: As a bicycle salesperson, Norman earns a fixed salary of $20 [#permalink]

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01 Jul 2017, 08:28

mbaiseasy wrote:

Test the inequalities: I. \(y>2x\) Let x = 1 bicycle; Earnings: 26 dollars Let y = 3 bicylce; Earnings: 38 dollars Is 38 more than twice of 26? NO! II. \(y > x\) Surely, there must be more bicycles sold in the second week. Always true! YES! III. y>3 Testing I, we found that when y = 3 and x = 1, we still couldn't achieve the condition that the second week's earning is more than twice the first. Therefore, y must be greater than 3. YES!

As a bicycle salesperson, Norman earns a fixed salary of $20 [#permalink]

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25 Aug 2017, 08:11

Hi - i did the following but not able to get option 1 ...experts please let me know why this is wrong

2* Money earned last week = Money earned this week

2* (x+20) = (y +20)

2x + 40 = y + 20

2x + 20 = y

With this algebraic equation, obviously 2 and 3 have to be right

But per this algebraic equation, even 1 has to be right as the equation is 2x + 20 = y ....so Y has to go above and beyond 2x for the algebraic equation to hold true .... hence i selected 1 also ...

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