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20 May 2020, 23:23
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
50% (02:39) correct
50%
(02:32)
wrong
based on 50
sessions
History
Date
Time
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Not Attempted Yet
As shown in the figure above, ABCDEF is a regular hexagon and P and Q are the midpoints of sides CD and EF respectively. AP and CQ intersect at point O. Find the value of angle AOQ?
A) 30º
B) 45º
C) 50º
D) 60º
E) 75º
Source: https://www.GMATinsight.com
Attachment:
Screenshot 2020-05-21 at 11.47.35 AM.png [ 233.79 KiB | Viewed 6536 times ]
Updated on: 22 Feb 2025, 02:06
Originally posted by GMATinsight on 20 May 2020, 23:24.
Last edited by Bunuel on 22 Feb 2025, 02:06, edited 2 times in total.
Last edited by Bunuel on 22 Feb 2025, 02:06, edited 2 times in total.
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Please check the video solution
21 May 2020, 05:26
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Assume angle CQP = angle CQA =x
Extend EF and CD to G; angle DGE = 60
In triangle CQG
angle QCG = 180- x-60 = 120-x
In triangle COP
angle COP = 180-(120-x)-x = 60
angle COP = angle AOQ = 60
Extend EF and CD to G; angle DGE = 60
In triangle CQG
angle QCG = 180- x-60 = 120-x
In triangle COP
angle COP = 180-(120-x)-x = 60
angle COP = angle AOQ = 60
Attachments
Untitled.png [ 9.48 KiB | Viewed 5250 times ]
