Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Jun 3008:00 AM PDT
-11:59 PM PDT
Join us June 30th for 2 weeks of GMAT questions (just 8 per day) to help with your prep and to compete with your fellow GMAT Clubbers for a chance to win a prize fund of $30,000 for you and your team-mates!
Jul 0901:00 PM EDT
-02:00 PM EDT
More Target Test Prep students are earning 100th percentile GMAT scores. Don’t settle for less when the Target Test Prep course gives you everything you need to score high on the GMAT. Start your 5-day free trial today.
Jul 1206:30 AM PDT
-08:30 AM PDT
Join our webinar to master GMAT RC Main Point Questions! Learn effective strategies to decipher passage themes and purposes. Senior Verbal Expert- Sunita Singhvi will equip you with tools to navigate complexities and avoid common traps set by the GMAT.
Jul 1211:00 AM IST
-01:00 PM IST
Attend this session to learn how to Deconstruct arguments, Pre-Think Author’s Assumptions, and apply Negation Test.
Jul 1311:00 AM EDT
-12:30 PM EDT
Looking for your GMAT motivation to break through the score plateau? Pragati improved her score by massive 160 points with strategic guidance and hard-work! Find out how personalized mentorship and a strong mindset can turn GMAT struggles into success.
Jul 1508:00 PM PDT
-09:00 PM PDT
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Jul 1611:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
56% (02:34) correct
44%
(02:21)
wrong
based on 154
sessions
History
Date
Time
Result
Not Attempted Yet
As the figure shows, line x=k equally divides the triangle into two parts with the same area. k=?
(A) 2^(1/2)
(B) 2
(C) 2*2^(1/2)
(D) 3
(E) 3^(1/2)
Attachment:
Untitled.png [ 22.42 KiB | Viewed 3848 times ]
28 Apr 2019, 01:34
Kudos
Bookmarks
The small triangle and the large triangle are similar triangles. When two shapes are similar, if their sides are in a 1 to r ratio, their areas are always in a 1 to r^2 ratio. So if their areas are in a 1 to 2 ratio, their sides must be in a 1 to √2 ratio, and in particular, the horizontal base of the large triangle, 4, is √2 times the base of the small triangle, which is k, so k = 4/√2 = 2√2.
Or we can use coordinate geometry. The hypotenuse of either triangle is the line y = x/2. So in the smaller triangle, the vertex along the hypotenuse is at y = k/2. So we now know, in terms of k, the dimensions of that triangle: if we take the horizontal line as the base, the base is k, and the height is k/2. So its area is k^2/4. Since its area is equal to 2 (half the area of the big triangle) we find k^2 = 8, and k = 2√2.
Or we can use coordinate geometry. The hypotenuse of either triangle is the line y = x/2. So in the smaller triangle, the vertex along the hypotenuse is at y = k/2. So we now know, in terms of k, the dimensions of that triangle: if we take the horizontal line as the base, the base is k, and the height is k/2. So its area is k^2/4. Since its area is equal to 2 (half the area of the big triangle) we find k^2 = 8, and k = 2√2.
General Discussion
