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25 Mar 2025, 20:50
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Bunuel: please let me know where I go wrong.
I am not understanding where I go wrong with my work? Could you please help.
1- P(All 3)
Ways for all 3 is pick 2 for one type
ABCC
ABBC
AABC
Ways of arranging one example
4!/2! = 12
3 examples total - 3(12) = 36
Total ways 9C4 = 126
36/126 = 4/14 = P(All 3)
1- (4/14) = 10/14
I am not understanding where I go wrong with my work? Could you please help.
1- P(All 3)
Ways for all 3 is pick 2 for one type
ABCC
ABBC
AABC
Ways of arranging one example
4!/2! = 12
3 examples total - 3(12) = 36
Total ways 9C4 = 126
36/126 = 4/14 = P(All 3)
1- (4/14) = 10/14
Bunuel
18 Aug 2025, 12:31
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Hi experts
In combinations and probability questions, when does order of selection actually matter and when not? How to figure that out? I end up miscalculating in such questions cuz I get confused whether to account for the order of selection or not. Cud someone clear this? Bunuel chetan2u KarishmaB
In combinations and probability questions, when does order of selection actually matter and when not? How to figure that out? I end up miscalculating in such questions cuz I get confused whether to account for the order of selection or not. Cud someone clear this? Bunuel chetan2u KarishmaB
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18 Aug 2025, 14:42
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Pablopikachu
It will differ question to question, but broadly imo it is always good to ask after reading the question whether am I just selecting or am I arranging, if you're just selecting then the order does not matter, and if you are arranging the order most likely matters. One example is 10 people running a marathon, how many ways can 3 winners be decided? => for this you only need to select 3 winners so just 10C3, the order does not matter. Now, if it asked, how many different possible ways of winning Gold, Silver, Bronze? => you first need to select 3 winners 10C3, and then arrange them winning G, S, and B 3! => 10C3*3!
