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03 Feb 2021, 07:15
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Total Bulbs for
Both Shifts: 36 Total First-Shift
Bulbs: 12
Both Shifts: 36 Total First-Shift
Bulbs: 12
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Difficulty:
45%
(medium)
Question Stats:
71% (02:37) correct
29%
(02:54)
wrong
based on 1023
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At a certain factory, the number of first-shift workers is 2/3 the number of second-shift workers. Every day, each second-shift worker can make 4/3 as many light bulbs as each first-shift worker.
In the first column, identify a possible number of total light bulbs made on one day by the two shifts combined; in the second column, identify the corresponding number of total light bulbs that the first-shift workers made on the same day. Make only two selections, one in each column.
In the first column, identify a possible number of total light bulbs made on one day by the two shifts combined; in the second column, identify the corresponding number of total light bulbs that the first-shift workers made on the same day. Make only two selections, one in each column.
|
Total Bulbs for Both Shifts |
Total First-Shift Bulbs |
Value |
| 3 | ||
| 6 | ||
| 12 | ||
| 24 | ||
| 36 |
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Official Answer
Total Bulbs for
Both Shifts: 36 Total First-Shift
Bulbs: 12
Both Shifts: 36 Total First-Shift
Bulbs: 12
rocky620
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Joined: 10 Nov 2018
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Location: India
Concentration: General Management, Strategy
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GMAT 1: 590 Q49 V22
WE:Other (Retail: E-commerce)
10 Feb 2021, 10:26
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First Shift Workers = FW
Second Shift Workers = SW
Let the number of SW = x, so the number of FW= \(\frac{2}{3}\)x
Let the number of bulbs produced by FW = n, so the number of bulbs produced by SW = \(\frac{4}{3}\)n
Total bulbs produced by FW = \(\frac{2}{3}\)xn
Total bulbs produced by SW = \(\frac{4}{3}\)xn
Total bulbs produced by FW & SW = \(\frac{2}{3}\)xn + \(\frac{4}{3}\)xn = 2xn
So,
\(\frac{Bulbs produced by FW}{Bulbs produced by FW+SW}\) =\(\frac{2}{3}xn/2xn \)= \(\frac{1}{3}\)
In the first column, identify a possible number of total light bulbs made on one day by the two shifts combined; in the second column, identify the corresponding number of total light bulbs that the first-shift workers made on the same day. Make only two selections, one in each column.
3 - 9 & 1 are not in the choices. Eliminate
6 - 18 & 2 are not in the choices. Eliminate
12 - Total First-Shift Bulbs
24 - 72 & 8 are not in the choices. Eliminate
36 - Total Bulbs for Both Shifts
Second Shift Workers = SW
Let the number of SW = x, so the number of FW= \(\frac{2}{3}\)x
Let the number of bulbs produced by FW = n, so the number of bulbs produced by SW = \(\frac{4}{3}\)n
Total bulbs produced by FW = \(\frac{2}{3}\)xn
Total bulbs produced by SW = \(\frac{4}{3}\)xn
Total bulbs produced by FW & SW = \(\frac{2}{3}\)xn + \(\frac{4}{3}\)xn = 2xn
So,
\(\frac{Bulbs produced by FW}{Bulbs produced by FW+SW}\) =\(\frac{2}{3}xn/2xn \)= \(\frac{1}{3}\)
In the first column, identify a possible number of total light bulbs made on one day by the two shifts combined; in the second column, identify the corresponding number of total light bulbs that the first-shift workers made on the same day. Make only two selections, one in each column.
3 - 9 & 1 are not in the choices. Eliminate
6 - 18 & 2 are not in the choices. Eliminate
12 - Total First-Shift Bulbs
24 - 72 & 8 are not in the choices. Eliminate
36 - Total Bulbs for Both Shifts
General Discussion
14 May 2025, 07:46
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