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At a certain picnic, each of the guests was served either a
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09 Feb 2010, 09:24
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At a certain picnic, each of the guests was served either a single scoop or a double scoop icecream. How many of the guests were served a double scoop of icecream? (1) At the picnic, 60 percent of the guests were served a double scoop of icecream. (2) A total of 120 scoops of icecream were served to all the guests at the picnic. OPEN DISCUSSION OF THIS QUESTION IS HERE: http://gmatclub.com/forum/atacertain ... 40734.html
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08 Feb 2012, 05:11
At a certain picnic, each of the guests was served either a single scoop or a double scoop icecream. How many of the guests were served a double scoop of icecream?(1) At the picnic, 60 percent of the guests were served a double scoop of icecream > \(\frac{x}{y}=\frac{4}{6}=\frac{2}{3}\), where \(x\) is the # of people served single scoop and \(y\) the # of people served double scoop. Clearly insufficient to calculate single numerical value of \(y\). (2) A total of 120 scoops of icecream were served to all the guests at the picnic > \(1*x+2*y=120\). Again not sufficient. (1)+(2) \(x=\frac{2}{3}y\) and \(x+2y=120\): we have 2 distinct linear equations with 2 unknowns, hence we can solve for \(x\) and \(y\). Sufficient. (Just to illustrate: \(\frac{2}{3}y+2y=120\) > \(y=45\)) Answer: C.
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Re: At a certain picnic, each of the guests was served either a
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21 Jun 2011, 11:47
At a certain picnic, each of the guests was served either a single scoop or a double scoop of ice cream. How many of the guests were served a double scoop of ice cream? (1) At the picnic, 60 percent of the guests were served a double scoop of ice cream. (2) A total of 120 scoops of ice cream were served to all the guests at the picnic. OPEN DISCUSSION OF THIS QUESTION IS HERE: atacertainpicniceachoftheguestswasservedeithera140734.html



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Re: At a certain picnic, each of the guests was served either a
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21 Jun 2011, 11:54
1) insufficient. It just tells us that 60% is double leaving 40% for single scoops. However we can not relate this to a specific number since we don't know how many people were served. There are only two categories. Either double OR single.
2) This just tells us that 120 scoops are divided over double and single. No further relationship between double or single.
1+2) 60% of the 120 scoops were double. 40% was single scoop so 48 scoops can be attributed to them, leaving 72 scoops for the 60% of people who had double scoops. Since these are scoops and not people, divide 72/2 and we get 36 people



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Re: At a certain picnic, each of the guests was served either a
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21 Jun 2011, 12:01
The question is asking how many people got double scoops
1 = 60/x got double scoops SUFFICIENT 2 = This question states the scoops of ice cream given out in general but it doesn't answer the question of "How many people got double scoops" INSUFFICIENT
So we have A B C D E
We then combine them. 60/x=120 SUFFICIENT Answer is C



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21 Jun 2011, 12:12
Adelabu you mean insufficient at statement 1 right?



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21 Jun 2011, 12:49
Actually no I meant SUFFICIENT. But looking at your post above I can see where I went wrong.
So since Statement 1 isn't telling me a specific number it will be insufficient? I was solving in the sense that the problem could be solved, without really going past that 60%.



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21 Jun 2011, 12:58
Aaah oke, sorry I misunderstood! Yeah it's not possible to solve for an actual number just knowing that x% had double scoops.. Remember, they're not just asking if you can solve it, they're asking for a value of the number of people.. Therefore you will need statement 2 aswell Good luck



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21 Jun 2011, 13:09
Thanks. I'm glad I replied to this post, I'll never forget that little trick now.



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21 Jun 2011, 13:16
You're welcome! Good luck with everything!



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Re: At a certain picnic, each of the guests was served either a
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14 Apr 2012, 13:13
Bunuel wrote: At a certain picnic, each of the guests was served either a single scoop or a double scoop icecream. How many of the guests were served a double scoop of icecream?
(1) At the picnic, 60 percent of the guests were served a double scoop of icecream > \(\frac{x}{y}=\frac{4}{6}=\frac{2}{3}\), where \(x\) is the # of people served single scoop and \(y\) the # of people served double scoop. Clearly insufficient to calculate single numerical value of \(y\).
(2) A total of 120 scoops of icecream were served to all the guests at the picnic > \(1*x+2*y=120\). Again not sufficient.
(1)+(2) \(x=\frac{2}{3}y\) and \(x+2y=120\): we have 2 distinct linear equations with 2 unknowns, hence we can solve for \(x\) and \(y\). Sufficient. (Just to illustrate: \(\frac{2}{3}y+2y=120\) > \(y=45\))
Answer: C. Hello Bunuel, Why can't we just assume that Y (double scope) = 2 X ? So we will have X + 2 x = 120 hence B is enough.



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Re: At a certain picnic, each of the guests was served either a
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14 Apr 2012, 13:24
Lstadt wrote: Bunuel wrote: At a certain picnic, each of the guests was served either a single scoop or a double scoop icecream. How many of the guests were served a double scoop of icecream?
(1) At the picnic, 60 percent of the guests were served a double scoop of icecream > \(\frac{x}{y}=\frac{4}{6}=\frac{2}{3}\), where \(x\) is the # of people served single scoop and \(y\) the # of people served double scoop. Clearly insufficient to calculate single numerical value of \(y\).
(2) A total of 120 scoops of icecream were served to all the guests at the picnic > \(1*x+2*y=120\). Again not sufficient.
(1)+(2) \(x=\frac{2}{3}y\) and \(x+2y=120\): we have 2 distinct linear equations with 2 unknowns, hence we can solve for \(x\) and \(y\). Sufficient. (Just to illustrate: \(\frac{2}{3}y+2y=120\) > \(y=45\))
Answer: C. Hello Bunuel, Why can't we just assume that Y (double scope) = 2 X ? So we will have X + 2 x = 120 hence B is enough. Because we don't know whether the # of guests who were served a single scoop of icecream (x) equals to the # of guests who were served a double scoop icecream (y).
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Re: At a certain picnic, each of the guests was served either a
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07 May 2014, 04:07
G = total guests G.4= Get a single scoop G.6= Get 2 scoops G.4 + 2(G.6) = 120 scoops G1.6=120 G= 5/8 *120 = 75 G*.6 = 45



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Re: At a certain picnic, each of the guests was served either a
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01 Aug 2015, 09:21
Lstadt wrote: Bunuel wrote: At a certain picnic, each of the guests was served either a single scoop or a double scoop icecream. How many of the guests were served a double scoop of icecream?
(1) At the picnic, 60 percent of the guests were served a double scoop of icecream > \(\frac{x}{y}=\frac{4}{6}=\frac{2}{3}\), where \(x\) is the # of people served single scoop and \(y\) the # of people served double scoop. Clearly insufficient to calculate single numerical value of \(y\).
(2) A total of 120 scoops of icecream were served to all the guests at the picnic > \(1*x+2*y=120\). Again not sufficient.
(1)+(2) \(x=\frac{2}{3}y\) and \(x+2y=120\): we have 2 distinct linear equations with 2 unknowns, hence we can solve for \(x\) and \(y\). Sufficient. (Just to illustrate: \(\frac{2}{3}y+2y=120\) > \(y=45\))
Answer: C. Hello Bunuel, Why can't we just assume that Y (double scope) = 2 X ? So we will have X + 2 x = 120 hence B is enough. I too faced the same issue and later realized the reason for confusion. The short answer, I believe, is ambiguity: the question leaves some room for interpretation of the wordings. Let's look at the specific part of the question: ....A total of 120 scoops of ice cream were served....This can be interpreted in two ways: 1. scoops as 'servings'This would mean a total of 120 servings of ice cream were given out. Clearly then, the answer cannot be derived since we cannot compute what proportion of those 120 servings were 1 scoop variants versus the proportion of servings that were 2 scoop varients. 2. Scoops as, well, individual scoops of ice creamHere, the interpretation is that '120 scoops' refers to total count (or sum) of scoops that had been served (i.e. the sum of single + double scoops. If I served 1 single scoop and 1 double scoop, then the total number of scoops served would be 1+2=3) Then the problem is definitely solvable. How? The problem provides the information that they were in the ratio 2:1 (The ratio of 1scoop servings to 2scoop servings) Thus, I could set up the equation x + 2x =120 where x= number of single scoops given out and 2x= number of double scoops given out. I just hope such ambiguous questions will not pop up during the official exam attempt. Eh, on second thought, it wouldn't matter: The pace and environment in the test center will make everything such a blur that one wouldn't even be in a position to detect ambiguity in hind sight



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Re: At a certain picnic, each of the guests was served either a
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18 Jun 2016, 10:31
kad wrote: At a certain picnic, each of the guests was served either a single scoop or a double scoop of ice cream. How many of the guests were served a double scoop of ice cream?
(1) At the picnic, 60 percent of the guests were served a double scoop of ice cream.
(2) A total of 120 scoops of ice cream were served to all the guests at the picnic.
Please, help me..it seems to be an easy question but I could not solve it... Can anyone tell that why is Answer choice E not a correct one. Combining both statements Let total guest were 90then as per (1) 60% of 90 =54 were given double scoop means a total of 108 scoop were used to serve double scoop and rest 12 were single scoop(total 120scoop as per (2)) Again if total guest were 80then as per (1) 60% of 80 =48 were given double scoop means a total of 96 scoop were used to serve double scoop and rest 24 were single scoop(total 120scoop as per (2)) getting different answers thanks



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Re: At a certain picnic, each of the guests was served either a
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19 Jun 2016, 08:39
rohit8865 wrote: kad wrote: At a certain picnic, each of the guests was served either a single scoop or a double scoop of ice cream. How many of the guests were served a double scoop of ice cream?
(1) At the picnic, 60 percent of the guests were served a double scoop of ice cream.
(2) A total of 120 scoops of ice cream were served to all the guests at the picnic.
Please, help me..it seems to be an easy question but I could not solve it... Can anyone tell that why is Answer choice E not a correct one. Combining both statements Let total guest were 90then as per (1) 60% of 90 =54 were given double scoop means a total of 108 scoop were used to serve double scoop and rest 12 were single scoop(total 120scoop as per (2)) Again if total guest were 80then as per (1) 60% of 80 =48 were given double scoop means a total of 96 scoop were used to serve double scoop and rest 24 were single scoop(total 120scoop as per (2)) getting different answers thanks At a certain picnic, each of the guests was served either a single scoop or a double scoop icecream. How many of the guests were served a double scoop of icecream?(1) At the picnic, 60 percent of the guests were served a double scoop of icecream > \(\frac{x}{y}=\frac{4}{6}=\frac{2}{3}\), where \(x\) is the # of people served single scoop and \(y\) the # of people served double scoop. Clearly insufficient to calculate single numerical value of \(y\). (2) A total of 120 scoops of icecream were served to all the guests at the picnic > \(1*x+2*y=120\). Again not sufficient. (1)+(2) \(x=\frac{2}{3}y\) and \(x+2y=120\): we have 2 distinct linear equations with 2 unknowns, hence we can solve for \(x\) and \(y\). Sufficient. (Just to illustrate: \(\frac{2}{3}y+2y=120\) > \(y=45\)) Answer: C. OPEN DISCUSSION OF THIS QUESTION IS HERE: atacertainpicniceachoftheguestswasservedeithera140734.html
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Collection of Questions: PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.
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15 Dec 2017, 07:35
amod243 wrote: At a certain picnic, each of the guests was served either a single scoop or a double scoop icecream. How many of the guests were served a double scoop of icecream? (1) At the picnic, 60 percent of the guests were served a double scoop of icecream. (2) A total of 120 scoops of icecream were served to all the guests at the picnic. Guys, I am finding the explanation of the solution of this problem given in OG12 insufficient . can anyone please elaborate why the answer is C , IMO it should be E. Let the guests who took Double Scoop : D Let the guests who took Single Scoop : S Total Guests comprise of all people who took Single scoop & Double scoops = D + S . There fore G = D + S  Equation 1 Statement 1: .6(D+S)=D ( As it is stated that 60 % of guests had double scoops) ( Alone insufficient) Statement 2: D + S = 120 ( Alone insufficient) Therefore together we have 2 variables & 2 equations. Hence C



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25 Apr 2018, 13:15
Bunuel wrote: At a certain picnic, each of the guests was served either a single scoop or a double scoop icecream. How many of the guests were served a double scoop of icecream?
(1) At the picnic, 60 percent of the guests were served a double scoop of icecream > \(\frac{x}{y}=\frac{4}{6}=\frac{2}{3}\), where \(x\) is the # of people served single scoop and \(y\) the # of people served double scoop. Clearly insufficient to calculate single numerical value of \(y\).
(2) A total of 120 scoops of icecream were served to all the guests at the picnic > \(1*x+2*y=120\). Again not sufficient.
(1)+(2) \(x=\frac{2}{3}y\) and \(x+2y=120\): we have 2 distinct linear equations with 2 unknowns, hence we can solve for \(x\) and \(y\). Sufficient. (Just to illustrate: \(\frac{2}{3}y+2y=120\) > \(y=45\))
Answer: C. Hey pushpitkc you know what i dont get here, if it says"each of the guests was served either a single scoop or a double scoop icecream" and one statement says ' 60 percent of the guests were served a double scoop of icecream" and another statement says "A total of 120 scoops of icecream were served to all the guests at the picnic " then it means 120*0.6 = 72 so 72 guests received double scoop of icecream why Bunuel made sucj complicatd equations ? thank you



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25 Apr 2018, 20:20
dave13 wrote: Bunuel wrote: At a certain picnic, each of the guests was served either a single scoop or a double scoop icecream. How many of the guests were served a double scoop of icecream?
(1) At the picnic, 60 percent of the guests were served a double scoop of icecream > \(\frac{x}{y}=\frac{4}{6}=\frac{2}{3}\), where \(x\) is the # of people served single scoop and \(y\) the # of people served double scoop. Clearly insufficient to calculate single numerical value of \(y\).
(2) A total of 120 scoops of icecream were served to all the guests at the picnic > \(1*x+2*y=120\). Again not sufficient.
(1)+(2) \(x=\frac{2}{3}y\) and \(x+2y=120\): we have 2 distinct linear equations with 2 unknowns, hence we can solve for \(x\) and \(y\). Sufficient. (Just to illustrate: \(\frac{2}{3}y+2y=120\) > \(y=45\))
Answer: C. Hey pushpitkc you know what i dont get here, if it says"each of the guests was served either a single scoop or a double scoop icecream" and one statement says ' 60 percent of the guests were served a double scoop of icecream" and another statement says "A total of 120 scoops of icecream were served to all the guests at the picnic " then it means 120*0.6 = 72 so 72 guests received double scoop of icecream why Bunuel made sucj complicatd equations ? thank you 120 is not the number of the guests, it's the number of the scoops of icecream served (the number of guests is less, it turns out to be 75). So, you cannot say that 60% of 120 is the number of guests who were served a double scoop of icecream. OPEN DISCUSSION OF THIS QUESTION IS HERE: http://gmatclub.com/forum/atacertain ... 40734.html
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Collection of Questions: PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.
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