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my approach to the question.
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SOLUTION.JPG [ 26.35 KiB | Viewed 1632 times ]
27 Jan 2025, 05:45
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| Night | Day | Total | |
| Box | 3 | 4 | |
| Workers | 4 | 5 | |
| Total | 12 | 20 | 32 |
= 20/32 = 5/8
jeepsdaddy
28 Feb 2026, 23:49
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day crew loads=x boxes/ member
night crew loads = 3x/4 boxes/ member
day crew workers= y
night crew workers= 4y/5
total boxes loaded/ day= xy+ (3x/4)*(4y/5)= xy+3xy/5= 8xy/5
required fraction= xy/(8xy/5) = 5/8
Answer E
night crew loads = 3x/4 boxes/ member
day crew workers= y
night crew workers= 4y/5
total boxes loaded/ day= xy+ (3x/4)*(4y/5)= xy+3xy/5= 8xy/5
required fraction= xy/(8xy/5) = 5/8
Answer E
jeepsdaddy
