Author 
Message 
TAGS:

Hide Tags

Intern
Joined: 05 Jul 2010
Posts: 8

At a loading dock, each worker on the night crew loaded
[#permalink]
Show Tags
Updated on: 26 Sep 2012, 11:56
Question Stats:
74% (01:47) correct 26% (01:51) wrong based on 1808 sessions
HideShow timer Statistics
At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load? (A) 1/2 (B) 2/5 (C) 3/5 (D) 4/5 (E) 5/8
Official Answer and Stats are available only to registered users. Register/ Login.
Originally posted by jeepsdaddy on 07 Oct 2010, 08:12.
Last edited by Bunuel on 26 Sep 2012, 11:56, edited 3 times in total.
Edited the question and added the OA




Math Expert
Joined: 02 Sep 2009
Posts: 47871

Re: Help me with the ANSWER .. Rates + Ratio Question.
[#permalink]
Show Tags
07 Oct 2010, 08:21




Director
Status: =Given to Fly=
Joined: 04 Jan 2011
Posts: 816
Location: India
Concentration: Leadership, Strategy
GMAT 1: 650 Q44 V37 GMAT 2: 710 Q48 V40 GMAT 3: 750 Q51 V40
GPA: 3.5
WE: Education (Education)

Re: Please help me understand this question in terms of solving
[#permalink]
Show Tags
26 Mar 2011, 05:33
Let the number of boxes loaded by each worker in the day crew be x Then the number of boxes loaded by each worker in the night crew is 3x/4 The number of people in the day crew = y The number of people in the night crew = 4y/5 Total number of boxes loded: Day crew = xy Night crew = 3x/4 * 4y/5 = 3xy/5 Total = xy + 3xy/5 = 8xy/5 Fraction loaded by the day crew = xy/(8xy/5) = 5/8 Ans  'E'
_________________
"Wherever you go, go with all your heart"  Confucius
Useful Threads
1. How to Review and Analyze your Mistakes (Post by BB at GMAT Club)
2. 4 Steps to Get the Most out out of your CATs (Manhattan GMAT Blog)
My Experience With GMAT
1. From 650 to 710 to 750  My Tryst With GMAT
2. Quest to do my Best  My GMAT Journey Log




Manager
Joined: 08 Sep 2010
Posts: 197
Location: India
WE 1: 6 Year, Telecom(GSM)

Re: Help me with the ANSWER .. Rates + Ratio Question.
[#permalink]
Show Tags
07 Oct 2010, 10:05
Just take the Box Loaded by each Night crew is Bn and Box Loaded by each Day Crew is Bd.Then According to question (Bn)=(3/4)(Bd) i.e (Bn)/(Bd)=3/4
Now again let Night Crew Has Nn number of crew members and Day crew has Nd members.Then according to question (Nn)=(4/5)(Nd) i.e (Nn)/(Nd)=4/5
As number of box carried by the group will be the product of Number of crew multiplied by the number of boxes carried by each member, According to question we need to find out { (Nd)(Bd) } / { (Nn)(Bn)+(Nd)(Bd) }
Dividing the Nominator and denominator by (Nd)(Bd),
We get, 1 / { (Nn)(Bn)/(Nd)(Bd) + 1 } i.e 1 / { (Nn)/(Nd)*(Bn)/(Bd) + 1 }
i.e 1 / { (3/4)*(4/5) + 1} =5/8
So answer is E. Thanks for a valued Question.
Consider KUDOS if you like the Solution.



Manager
Joined: 27 May 2008
Posts: 107

Re: Help me with the ANSWER .. Rates + Ratio Question.
[#permalink]
Show Tags
07 Oct 2010, 23:13
its 5/8, Work done by day crew will be 4x (let x=1), the count of day crew = 5x Work done by day crew will be 3x (let x=1), the count of day crew = 4x Total amount work done by both is 5*4+4*3 = 20+12 = 32 Ratio of amount of work done by day crew to total amount of work done is = 20/32 =5/8.



Senior Manager
Joined: 21 Mar 2010
Posts: 292

Re: PS: loading dock
[#permalink]
Show Tags
14 Feb 2011, 12:13
el1981 wrote: At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all boxes loaded by two crews did the day crew load? A 1/2 B 2/5 C 3/5 D 4/5 E 5/8 night crew loads 3/4 of what day crew loads. Also, night crew is 4/5th day crew. Therefore if one day crew member loads x boxes Night crew is 4/5th of (1 ) * 3/4 = 3/5x Therefore total number of boxes per crew member (1 night + one day crew) 3/5x +x = 8/5x. The x/8/5x = 5/8



Retired Moderator
Joined: 20 Dec 2010
Posts: 1879

Re: Please help me understand this question in terms of solving
[#permalink]
Show Tags
26 Mar 2011, 05:40
scbguy wrote: at a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load ? A) 1/2 B)2/5 C)3/5 D)4/5 E)5/8 Please explain the step by step working of this question. Thanks Say, Day crew = 5 people Night crew = (4/5)*5 = 4 people Each person in day crew loaded = 4 boxes. Each person in night crew loaded = (3/4)*4= 3 boxes. Total boxes loaded by day crew = 5*4 = 20 Total boxes loaded by night crew = 4*3 = 12 Fraction of boxes loaded by day crew = 20/(20+12) = 20/32 = 5/8 Ans: "E"
_________________
~fluke
GMAT Club Premium Membership  big benefits and savings



Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 8182
Location: Pune, India

Re: Please help me understand this question in terms of solving
[#permalink]
Show Tags
27 Mar 2011, 19:42
scbguy wrote: at a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load ? A) 1/2 B)2/5 C)3/5 D)4/5 E)5/8 Please explain the step by step working of this question. Thanks Workers at night crew loaded 3/4 as many boxes as did day crew so they loaded fewer boxes. Night crew has 4/5 as many workers as the day crew so night crew has fewer workers too. Overall, night crew loaded 3/4 * 4/5 = 3/5 as many boxes as did day crew. So out of a total of 8 boxes, Night Crew loaded 3 and Day Crew loaded 5 so Day Crew loaded 5/8 of total boxes. Or Boxes loaded by Night Crew: Boxes loaded by Day Crew = 3/5 : 1 = 3:5 So day crew loaded 5/8 of total boxes. If you are uncomfortable with ratios, check out the following posts. They explain ratios and their applications: http://www.veritasprep.com/blog/2011/03 ... ofratios/http://www.veritasprep.com/blog/2011/03 ... osintsd/http://www.veritasprep.com/blog/2011/03 ... problems/*Didn't see fluke's response there! The concept used is pretty similar.
_________________
Karishma Veritas Prep GMAT Instructor
Save up to $1,000 on GMAT prep through 8/20! Learn more here >
GMAT selfstudy has never been more personalized or more fun. Try ORION Free!



Intern
Joined: 01 Nov 2010
Posts: 8
Location: United States
GMAT Date: 03302012
WE: Pharmaceuticals (Health Care)

Re: OG12 PS 138 Loading dock and workers
[#permalink]
Show Tags
22 Sep 2011, 13:59
Hi, I'm trying to plug in for Question # 138 in OG 12. Could anyone point out where i'm going wrong in my reasoning? I understand the solutions posted in the earlier posts but would like to know where i went wrong. No. of Boxes loaded by Night workers = 3/4 of Day workers No. of Night workers = 4/5 of Day workers. Let the number of Day workers = 100 and they load a total of 100 boxes. No. of boxes loaded by Night workers = 3/4 x 100 = 75 No. of Night workers = 4/5 x 100 = 80 total no. of boxes loaded by both workers = 175 total no. of boxes loaded by day workers = 100 fraction of boxes loaded by day workers out of the total = 100/175 = 4/7 The closest answer is 4/5 which is D. But the correct answer is 5/8 which is E.



Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 8182
Location: Pune, India

Re: OG12 PS 138 Loading dock and workers
[#permalink]
Show Tags
24 Sep 2011, 09:53
gmatyro wrote: Hi, I'm trying to plug in for Question # 138 in OG 12. Could anyone point out where i'm going wrong in my reasoning? I understand the solutions posted in the earlier posts but would like to know where i went wrong. No. of Boxes loaded by Night workers = 3/4 of Day workers No. of Night workers = 4/5 of Day workers. Let the number of Day workers = 100 and they load a total of 100 boxes. No. of boxes loaded by Night workers = 3/4 x 100 = 75 No. of Night workers = 4/5 x 100 = 80 total no. of boxes loaded by both workers = 175 total no. of boxes loaded by day workers = 100 fraction of boxes loaded by day workers out of the total = 100/175 = 4/7 The closest answer is 4/5 which is D. But the correct answer is 5/8 which is E. Here is the problem in your solution: It is given that EACH night worker loads 3/4 of the boxes loaded by EACH day worker. (not that total number of boxes loaded by night workers is 3/4 of the boxes loaded by day workers) If I want to take values and I say, each day worker loads 100 boxes, then each night worker loads 75 boxes. Total no of boxes loaded by day workers = 100*100 = 10,000 Total no of boxes loaded by night workers = 80*75 = 6000 Fraction of total boxes loaded by day workers = 10,000/16,000 = 5/8 Though, if I want to take numbers and plug in, I would take easier numbers. Say, there are 5 day workers. Then there are 4 night workers. Say, each day worker loads 4 boxes in a day. Each night worker then loads 3 boxes in a day. Total no of boxes loaded by day workers = 5*4 = 20 Total no of boxes loaded by night workers = 4*3 = 12 Fraction of boxes loaded by day workers = 20/32 = 5/8
_________________
Karishma Veritas Prep GMAT Instructor
Save up to $1,000 on GMAT prep through 8/20! Learn more here >
GMAT selfstudy has never been more personalized or more fun. Try ORION Free!



Director
Joined: 01 Feb 2011
Posts: 671

Re: OG12 PS 138 Loading dock and workers
[#permalink]
Show Tags
24 Sep 2011, 21:50
Night Crew rate = (3/4)* Day Crew rate. 1
Number of night Crew workers = (4/5)*Day crew workers.2
Total Work done by Day crew workers = Number of day crew workers * day crew worker rate.
Total Work done by Night crew workers = Number of night crew workers * night crew worker rate
= (4/5) Day crew workers * (3/4) * Day crew rate
= (3/5)* Total work done by Day crew workers
fraction of all the boxes loaded by the two crews did the day crew load = 1/(1+(3/5)) = 5/8
Answer is E.



Manager
Joined: 16 Feb 2012
Posts: 193
Concentration: Finance, Economics

Re: OG12 PS 138 Loading dock and workers
[#permalink]
Show Tags
01 Mar 2012, 04:30
I think that the biggest problem for solving this kind of questions is the language understanding (i.e. misunderstanding). I've had a lot of trouble with this one until I figured out that the night crew did 3/4 and the day crew did 4/4 of the work. And that the night crew had 4/5 workers and the day crew 5/5 workers. It can become quite messy for a nonnative person.
_________________
Kudos if you like the post!
Failing to plan is planning to fail.



Intern
Joined: 15 Nov 2011
Posts: 13
GMAT Date: 03102012

#138 in OG 12 edition problem solving word problem
[#permalink]
Show Tags
12 Apr 2012, 19:21
If you don't have the book in front of you the question is:
At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load? a. 1/2 b. 2/5 c. 3/5 d. 4/5 e. 5/8
I didn't know how to answer this question so I looked at the answer explanations and I still do not understand how to get the answer. The explanation says:
From this, the workers on the night crew will load 3/4(4/5)= 3/5 as many boxes as the day crew. The total loaded by both the day and night crews is thus 1 + 3/4= 5/5 + 3/5= 8/5 of the day crew's work. Therefore, the fraction of all the boxes loaded by the two crews that was done by the day crew was 1/8/5 = 1(5/8) = 5/8.
I understand the first sentence saying that the night crew will load 3/5 as many boxes as the day crew. Where I get mixed up is in the next sentence, The total loaded by both the day and night crews is thus 1 + 3/5 = 5/5 + 3/5 = 8/5 of the day crew's work. I do not understand where the 1 comes from. I am figuring that the number 1 represents the day crew. Is it saying the night crew loads 3/5 as many as the day crew so the day crew loads 5/5? Can someone please explain this to me??
Thanks,
Josh



Senior Manager
Joined: 13 Mar 2012
Posts: 289
Concentration: Operations, Strategy

Re: #138 in OG 12 edition problem solving word problem
[#permalink]
Show Tags
12 Apr 2012, 20:03
At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load? a. 1/2 b. 2/5 c. 3/5 d. 4/5 e. 5/8 SEE IT THIS WAY: day crew loads=x boxes/ member night crew loads = 3x/4 boxes/ member day crew workers= y night crew workers= 4y/5 total boxes loaded/ day= xy+ (3x/4)*(4y/5)= xy+3xy/5= 8xy/5 required fraction= xy/(8xy/5) = 5/8 Hence E Hope this clarifies..!!
_________________
Practice Practice and practice...!!
If my reply /analysis is helpful>please press KUDOS If there's a loophole in my analysis> suggest measures to make it airtight.



Current Student
Joined: 09 Jul 2013
Posts: 25
Location: United States (WA)
GPA: 3.65
WE: Military Officer (Military & Defense)

Re: At a loading dock, each worker on the night crew loaded
[#permalink]
Show Tags
09 Oct 2013, 06:38
I picked some smart numbers and used a table to organize the given information. Just another way to visualize the problem for me... So, let's say we have 5 day workers. That would give us 4 night workers (4/5 of day). Say the day workers load 12 boxes (I picked a smartish number), then the night workers would load 9 boxes (3/4 of what the Day workers load). Put it all in a table and see what you have.
 Day  Night  Total People 5 4 Boxes  12 9  Total 603696
I arrived at the Totals on the bottom by multiplying the people and boxes (5x12, 4x9).
So if you want to figure out what fraction of the total the day workers loaded, use:
\(\frac{60}{96}\)
This is (number of boxes the day crew loaded) divided by (total number of boxes)
This simplifies to \(\frac{5}{8}\). Thus, E is the answer.
Hope this method helps.



Current Student
Status: Eagles Become Vultures
Joined: 19 Jun 2014
Posts: 61
Concentration: Finance, Strategy
GPA: 4
WE: Corporate Finance (Energy and Utilities)

At a loading dock, each worker on the night crew loaded
[#permalink]
Show Tags
07 Jan 2015, 14:36
Let b  boxes and w  workers
Night crew loaded 0.75b per worker with 0.8w workers => 0.6bw Day crew loaded b per worker with w workers => bw Total loaded by both => 1.6bw Finally, divide bw / 1.6bw <=> 1/1.6 = 5/8



SVP
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1835
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)

At a loading dock, each worker on the night crew loaded
[#permalink]
Show Tags
07 Jan 2015, 22:53
Refer diagram below Attachment:
frac.png [ 3.33 KiB  Viewed 29605 times ]
Let boxes in day per worker = 1 Let workers in day = 1 Total boxes loaded in day = 1*1 = 1 Similarly, total boxes loaded in night \(= \frac{3}{4} * \frac{4}{5} = \frac{3}{5}\) Total boxes loaded \(= 1+\frac{3}{5} = \frac{8}{5}\) Fraction \(= \frac{1}{\frac{8}{5}} = \frac{5}{8}\) Answer = E
_________________
Kindly press "+1 Kudos" to appreciate



Manager
Joined: 07 Apr 2015
Posts: 176

At a loading dock, each worker on the night crew loaded
[#permalink]
Show Tags
15 Jun 2015, 01:01
Question: Okay so I got that far that the night crew loads 3/5 as many boxes as the day crew. However I then calculated 3/5 divided by 5/5 (total in my opinion). I looked at the OG's solution and I don't get why we first add 5/5 to 3/5. It does not make sense in my head as the total number of boxes would then be greater than 100%? Maybe its a language problem as the problem is kind of wordy...



Senior Manager
Status: Math is psychological
Joined: 07 Apr 2014
Posts: 421
Location: Netherlands
GMAT Date: 02112015
WE: Psychology and Counseling (Other)

At a loading dock, each worker on the night crew loaded
[#permalink]
Show Tags
18 Jun 2015, 01:17
I just calculated the number of boxes (for ONE worker) for the number or workers (based on the information in the stem), and found #boxes*#workers for each shift:
..............#Boxes........#Workers......Work done Night..........3.................4...................12....... Day............4.................5...................20....... Total.................................................32.......
In the end it is: 20/32 = 5/8. ANS E



Intern
Joined: 20 Dec 2014
Posts: 21

Re: At a loading dock, each worker on the night crew loaded
[#permalink]
Show Tags
01 Nov 2015, 14:44
What I did was construct a matrix with top columns as Boxes l Workers l Total the rows were then Day and Night. Next I filled in the day row under boxes as X and under workers as W For the Night row I did 3/4X under boxes column and 4/5 W under workers column. I assigned X to be 100 and W to be 100 to have some even numbers to work with. I then reasoned that for Day Crew Total boxes would be WX= 10,000 and night crew would be 75 X 80 = 6,000 = 16,000 total for both 10,000/16,000= 5/8Any suggestions or if this helps kudos please




Re: At a loading dock, each worker on the night crew loaded &nbs
[#permalink]
01 Nov 2015, 14:44



Go to page
1 2
Next
[ 28 posts ]



