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# At a monthly meeting, 2/5 of the attendees were males and

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VP
Joined: 03 Apr 2007
Posts: 1152
At a monthly meeting, 2/5 of the attendees were males and  [#permalink]

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01 Jun 2008, 08:38
2
00:00

Difficulty:

5% (low)

Question Stats:

87% (02:11) correct 13% (02:28) wrong based on 201 sessions

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At a monthly meeting, 2/5 of the attendees were males and 7/8 of the male attendees arrived on time. If 9/10 of the female attendees arrived on time, what fraction of the attendees at the monthly meeting did not arrive on time?

A. 11/100
B. 3/25
C. 7/50
D. 3/20
E. 4/25
Director
Joined: 10 Sep 2007
Posts: 882

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01 Jun 2008, 08:49
3
One can pick number or one can also do it without picking number depending on how comfortable one is with abstract calculations.
For picking a number choose some thing that can be evenly divided by all the denominators given in the question.
Solution by picking number
Picking nunber = 100
Males = 100*2/5 = 40
Female = 100 - 40 = 60
Males Arrived on time = 40 * 7/8 = 35
Males Not Arrived on time = 40 - 35 = 5
Females Arrived on time = 60 * 9/10 = 54
Females Not Arrived on time = 60 - 54 = 6
Total later arrivals = 6 + 5 = 11
Ratio = 11/100

Solution by abstract method
Total nunber = x
Males = x*2/5 = 2x/5
Female = x - 2x/5 = 3x/5
Males Not Arrived on time = 2x/5 * (1-7/8) = x/20
Females Not Arrived on time = 3x/5 * (1-9/10) = 3x/50
Total later arrivals = x/20 + 3x/50 = 11x/100
Ratio = 11x/100/x = 11/100

Current Student
Joined: 28 Dec 2004
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Schools: Wharton'11 HBS'12

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01 Jun 2008, 08:50
i get 11/100

i picked 100 cause its a multiple of 5, 2..
Director
Joined: 23 Sep 2007
Posts: 742

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01 Jun 2008, 10:25
I find that it is easier to draw the table and fill in the blanks, it saves a little time of having to set up the conditions in the mind

| M | F | Total
late | | |
not late | | |
total | 2/5 | 3/5 | 5/5

the table does not show like I intended for it to show
Senior Manager
Status: Gonna rock this time!!!
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Posts: 448
Location: India
GMAT 1: 640 Q43 V34
GMAT 2: 630 Q47 V29
WE: Information Technology (Computer Software)
Re: At a monthly meeting, 2/5 of the attendees were males and  [#permalink]

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24 Nov 2012, 07:09
2/5 of the attendees were males and 7/8 of the male attendees

How to pick nos? Here it is..

LCM of 5 and 8 is 40..
So pick no 40 for no of males..

so males=2/5 of total attendees= 40

therefore total=100.

7/8 of 40= 35 arrived on time

Hope it helps

Kudos if you like this approach..
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Intern
Joined: 28 Apr 2012
Posts: 15
Re: At a monthly meeting, 2/5 of the attendees were males and  [#permalink]

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02 Dec 2012, 12:00
Sachin9 wrote:
2/5 of the attendees were males and 7/8 of the male attendees

How to pick nos? Here it is..

LCM of 5 and 8 is 40..
So pick no 40 for no of males..

so males=2/5 of total attendees= 40

therefore total=100.

7/8 of 40= 35 arrived on time

Hope it helps

Kudos if you like this approach..

I got the answer right because after I couldn't figure it out picking numbers, I tried to solve another way but I was wondering if you could help me figure it out with picking numbers approach.

How do we know to pick numbers for males and not total attendees? I picked 40 because it went into 5, 8, and 10. Then I figured out 2/5 of males of total attendees is 16 and 7/8 of 16 on time is 14 on time which means 2 not on time.

If 2/5 were males then that means 3/5 were females so 3/5 of the 40 is 24. 9/10 of that number is approximately 21 people which is approximately 3 females not on time.

Then that would be 3 females not on time + 2 males not on time = 5 / 40= 1/8
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Re: At a monthly meeting, 2/5 of the attendees were males and  [#permalink]

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15 Mar 2018, 09:13
1
goalsnr wrote:
At a monthly meeting, 2/5 of the attendees were males and 7/8 of the male attendees arrived on time. If 9/10 of the female attendees arrived on time, what fraction of the attendees at the monthly meeting did not arrive on time?

A. 11/100
B. 3/25
C. 7/50
D. 3/20
E. 4/25

We can let the total number of attendees = 800. (This is a convenient number that allows the calculations to be easier.)

Thus, there are 2/5 x 800 = 320 males and 800 - 320 = 480 females.

Since 7/8 of the males arrived on time, 7/8 x 320 = 280 males arrived on time.

Since 9/10 of the female attendees arrived on time, 9/10 x 480 = 432 females arrived on time.

Thus, 800 - (280 + 432) = 88 attendees did not arrive on time.

Therefore, the fraction of the attendees who did not arrive on time is 88/800 = 11/100.

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Re: At a monthly meeting, 2/5 of the attendees were males and &nbs [#permalink] 15 Mar 2018, 09:13
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