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01 Feb 2012, 19:16
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C
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Difficulty:
55%
(hard)
Question Stats:
58% (01:49) correct
42%
(01:42)
wrong
based on 338
sessions
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At how many points does line L intersect with the parabola represented by y = x² - 3x + 6?
(1) Line L is parallel to x-axis.
(2) Line L passes through the point (0, 16).
(1) Line L is parallel to x-axis.
(2) Line L passes through the point (0, 16).
02 Feb 2012, 09:19
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At how many points does line L intersect with the parabola represented by y = x² - 3x + 6?
Generally a parabola and a line can have 0, 1, or 2 intersection points.
Notice than in our case, since the coefficient of x^2 is positive, then we have an upward parabola, which intersects y-axis at (0, 6). Just to illustrate, below is the graph of y = x^2 - 3x + 6: 
parabola.gif [ 3.02 KiB | Viewed 9908 times ]
(1) Line L is parallel to x-axis. All three cases are possible: line L can be below the given parabola (no intersection), line L can go through the vertex (1 intersection) or cross it above the vertex (2 intersections). Not sufficient.
Notice that if it were: line L is parallel to y-axis then we would know that it would cross a parabola at one point, hence in this case the statement would be sufficient.
(2) Line L passes through the point (0, 16). Since (0, 16) is higher than y-intercept of parabola, then line L is "trapped" and must have at least one intersection with parabola (it'll have only one for example if L is x=0). Not sufficient.
(1)+(2) Line L intersect with the parabola at two points. Sufficient.
Answer: C.
Generally a parabola and a line can have 0, 1, or 2 intersection points.
Notice than in our case, since the coefficient of x^2 is positive, then we have an upward parabola, which intersects y-axis at (0, 6). Just to illustrate, below is the graph of y = x^2 - 3x + 6:
Attachment:
parabola.gif [ 3.02 KiB | Viewed 9908 times ]
(1) Line L is parallel to x-axis. All three cases are possible: line L can be below the given parabola (no intersection), line L can go through the vertex (1 intersection) or cross it above the vertex (2 intersections). Not sufficient.
Notice that if it were: line L is parallel to y-axis then we would know that it would cross a parabola at one point, hence in this case the statement would be sufficient.
(2) Line L passes through the point (0, 16). Since (0, 16) is higher than y-intercept of parabola, then line L is "trapped" and must have at least one intersection with parabola (it'll have only one for example if L is x=0). Not sufficient.
(1)+(2) Line L intersect with the parabola at two points. Sufficient.
Answer: C.
General Discussion
01 Feb 2012, 21:44
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At how many points does line L intersect with the parabola represented by y = x² - 3x + 6?
y = x² - 3x + 6?
Since a (coefficient of x²) is +ve, it's an upward parabola.
y intercept is 6
(1) Line L is parallel to x-axis.
Not sufficient, as we don't know where does it intersects the y axis.
(2) Line L passes through the point (0, 16).
Not sufficient as we don't know the slope, depending on slope line may intersect parabola at zero or multiple points.
(1) + (2)
Sufficient, lines intersects parabola at only two points i.e. where y = 16.
C
y = x² - 3x + 6?
Since a (coefficient of x²) is +ve, it's an upward parabola.
y intercept is 6
(1) Line L is parallel to x-axis.
Not sufficient, as we don't know where does it intersects the y axis.
(2) Line L passes through the point (0, 16).
Not sufficient as we don't know the slope, depending on slope line may intersect parabola at zero or multiple points.
(1) + (2)
Sufficient, lines intersects parabola at only two points i.e. where y = 16.
C
