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let T be total number of artifacts initially.

stolen (1/7)T to (1/5)T

left (6/7)T to (4/5)T = new total

1/3 for display T/3

storage (6/7)T -T/3 to (4/5)- T/3

11/21 T to 7T/15

so storage to new total = (11T/21) / (6T/7) to (7T/15) / (4T/5)

i.e 11/18 to 7/12

Answer is D.
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Chetangupta
Before the regime change, the National Museum regularly displayed only one third of the artifacts in its collection; the other two thirds were kept in storage. The National Museum’s curator estimates that one seventh to one fifth of the artifacts in the museum’s collection disappeared during the regime change. If the National Museum now wishes to display the same number of artifacts as it did before the regime change, and if none of the missing artifacts are recovered, then the museum will keep in storage:

1) \(4/5\) to \(6/7\) of artifacts in collection

2) \(9/14\) to \(13/20\)

3) \(3/5\) to \(5/7\)

4) \(7/12\) to \(11/18\)

5) \(7/18\) to \(5/12\)

Since everything is in fraction terms, assume a total number of artifacts, say 210 (an easy multiple of 3, 7 and 5)

Regularly displayed = (1/3)*210 = 70
Kept in storage = 140

Disappeared artefacts = 1/7th to 1/5th = 30 to 42

So number of artefacts in storage now are 110 to 98

So museum will keep in its storage 110/180 to 98/168 of its collection.

We have only one option with 11/18 hence that must be the answer.

Answer (D)
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