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If c = cost of catabrian and e = cost of espadrille

profit (catabrian)= c *60% and profit espadrille = e*90%
the percentage profit for the two shoes is 85% => 60%*c + 90%*e = 85% (c+e)


If we assume that the total cost (both shoes) is 100 => c+e = 100 the profit for both shoes is 85
we can have solve these equations

(1) c+e = 100
(2) 0,6*c +0,9 e = 85 <=> 6c +9e = 850

We find c = 50/3 and e = 250/3 for a cost of 100 , we can find the relation by use ratio of cost of the two shoes c/e = 1/5 => e = 5 c

The solution that respect this relation is c = 80 and e = 400­
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­Price of CA: 1.6 cost
Price of E: 1.9 cost

Avg price: 1.85 cost

.................CA....................................Avg................E
Price/Cost: 1.6...................................1.85...............1.9
//////////// ____________+0.25_____(.....)__-0.05____
////////////______________5_______(.....)_____1____
Cost........:1......................................(.....)..................5

price of E = 5 * price of CA

=> CA: 80; E: 400­
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Hello from the GMAT Club BumpBot!

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