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Updated on: 03 Jul 2018, 11:26
Originally posted by Newman2019 on 03 Jul 2018, 10:13.
Last edited by Bunuel on 03 Jul 2018, 11:26, edited 2 times in total.
Last edited by Bunuel on 03 Jul 2018, 11:26, edited 2 times in total.
Renamed the topic, edited the question, added the OA and moved to DS forum.
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
28% (02:19) correct
72%
(02:25)
wrong
based on 51
sessions
History
Date
Time
Result
Not Attempted Yet
Can n/196 be an integer?
(1) n is a multiple of 24 but not 16
(2) n is a multiple of 8 but not 48
(1) n is a multiple of 24 but not 16
(2) n is a multiple of 8 but not 48
03 Jul 2018, 10:27
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Can n/196 be an integer?
Notice that the question asks whether \(\frac{n}{196} = \frac{n}{2^2*7^2}\) CAN be an integer, not whether it IS an integer. n/196 could be an integer if n has 2 in the power of at least 2 and 7 in the power of at least 2.
(1) n is a multiple of 24 but not 16.
Since the question asks whether n/196 CAN be an integer, then we are only interested in the numbers n is NOT divisible by, to check whether this discards this possibility. We are told that n is NOT divisible by 2^4. No problem. We needed 2 in the power of at least 2. So, for example, if n = 24*7^2, then n will be divisible by 196. So, n/196 CAN be an integer. Sufficient.
(2) n is a multiple of 8 but not 48
Again, since the question asks whether n/196 CAN be an integer, then we are only interested in the numbers n is NOT divisible by, to check whether this discards this possibility. We are told that n is NOT divisible by 2^4*3. No problem. We needed 2 in the power of at least 2 and are not concerned about 3 at all. So, for example, if n = 8*7^2, then n will be divisible by 196. So, n/196 CAN be an integer. Sufficient.
Answer: D.
Hope it's clear.
Notice that the question asks whether \(\frac{n}{196} = \frac{n}{2^2*7^2}\) CAN be an integer, not whether it IS an integer. n/196 could be an integer if n has 2 in the power of at least 2 and 7 in the power of at least 2.
(1) n is a multiple of 24 but not 16.
Since the question asks whether n/196 CAN be an integer, then we are only interested in the numbers n is NOT divisible by, to check whether this discards this possibility. We are told that n is NOT divisible by 2^4. No problem. We needed 2 in the power of at least 2. So, for example, if n = 24*7^2, then n will be divisible by 196. So, n/196 CAN be an integer. Sufficient.
(2) n is a multiple of 8 but not 48
Again, since the question asks whether n/196 CAN be an integer, then we are only interested in the numbers n is NOT divisible by, to check whether this discards this possibility. We are told that n is NOT divisible by 2^4*3. No problem. We needed 2 in the power of at least 2 and are not concerned about 3 at all. So, for example, if n = 8*7^2, then n will be divisible by 196. So, n/196 CAN be an integer. Sufficient.
Answer: D.
Hope it's clear.
03 Jul 2018, 23:04
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Bunuel if the question asks
Is n/196 an integer?
then the correct choice would be E.
Correct me if I am wrong.
Is n/196 an integer?
then the correct choice would be E.
Correct me if I am wrong.
