Bunuel wrote:

Car A travels at three times the average speed of car B. Car A started to travel at 12:00 o'clock, car B started to travel at 16:00 o'clock. What is the speed of car B (in Km/h) if the total distance that both cars traveled until 18:00 was 1000 Km?

A. 10.

B. 25.

C. 30.

D. 38.

E. 50.

Total distance - 1000KM

Time ratio A:B - 3:1

Speed Ratio A : B - 3 : 1

So distance(speed*time) ratio will be - 3*3 : 1*1 - 9:1

So total distance travlled by B - 100KM

Time taken by B (18:00-16:00 =2) - 2 hours

Speed of B - 50 KMPH