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Car A travels at three times the average speed of car B. Car A started

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Joined: 02 Sep 2009
Posts: 51218
Car A travels at three times the average speed of car B. Car A started  [#permalink]

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13 Jul 2016, 00:59
00:00

Difficulty:

25% (medium)

Question Stats:

76% (02:10) correct 24% (02:37) wrong based on 149 sessions

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Car A travels at three times the average speed of car B. Car A started to travel at 12:00 o'clock, car B started to travel at 16:00 o'clock. What is the speed of car B (in Km/h) if the total distance that both cars traveled until 18:00 was 1000 Km?

A. 10.
B. 25.
C. 30.
D. 38.
E. 50.

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Joined: 30 Mar 2016
Posts: 14
Location: India
GMAT 1: 690 Q51 V31
GPA: 3.23
Re: Car A travels at three times the average speed of car B. Car A started  [#permalink]

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13 Jul 2016, 01:18
1
1
Bunuel wrote:
Car A travels at three times the average speed of car B. Car A started to travel at 12:00 o'clock, car B started to travel at 16:00 o'clock. What is the speed of car B (in Km/h) if the total distance that both cars traveled until 18:00 was 1000 Km?

A. 10.
B. 25.
C. 30.
D. 38.
E. 50.

Total distance - 1000KM
Time ratio A:B - 3:1
Speed Ratio A : B - 3 : 1
So distance(speed*time) ratio will be - 3*3 : 1*1 - 9:1
So total distance travlled by B - 100KM
Time taken by B (18:00-16:00 =2) - 2 hours

Speed of B - 50 KMPH
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Status: In the realms of Chaos & Night
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Re: Car A travels at three times the average speed of car B. Car A started  [#permalink]

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13 Jul 2016, 03:23
1
1
Bunuel wrote:
Car A travels at three times the average speed of car B. Car A started to travel at 12:00 o'clock, car B started to travel at 16:00 o'clock. What is the speed of car B (in Km/h) if the total distance that both cars traveled until 18:00 was 1000 Km?

A. 10.
B. 25.
C. 30.
D. 38.
E. 50.

Distance = Speed x time
Speed of Car B = x; Time Travelled = 2 Hrs
Speed of Car A = 3x; Time Travelled = 6 Hrs

x*2 + 3x*6 = 1000
=>x=50Km/Hr Ans
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Re: Car A travels at three times the average speed of car B. Car A started  [#permalink]

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13 Jul 2016, 04:55
Bunuel wrote:
Car A travels at three times the average speed of car B. Car A started to travel at 12:00 o'clock, car B started to travel at 16:00 o'clock. What is the speed of car B (in Km/h) if the total distance that both cars traveled until 18:00 was 1000 Km?

A. 10.
B. 25.
C. 30.
D. 38.
E. 50.

Total distance= Distance travelled by A +Distance travelled by car B

Distance= speed*time
Distance of A= 3x * 6

Distance of B= x*2

(3x * 6) + (x*2) = 1000
x= 50 KM/hr

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Joined: 20 Feb 2015
Posts: 795
Concentration: Strategy, General Management
Re: Car A travels at three times the average speed of car B. Car A started  [#permalink]

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13 Jul 2016, 05:12
let Sa and Sb be the speed of car A and B
and Da and Db be the distance travelled by car A and car B
as per the question
Sa=3Sb
Da=3Sb*6=18Sb
Db=Sb*2=2Sb
18Sb+2Sb=1000
Sb=1000/20=50Km/h
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Joined: 15 Sep 2011
Posts: 326
Location: United States
WE: Corporate Finance (Manufacturing)
Car A travels at three times the average speed of car B. Car A started  [#permalink]

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18 Jul 2016, 18:49
Top Contributor
$$3x:1x$$ ratio of the rates, where $$x$$ is the rate of car b
$$6:2$$ ratio of the times
$$18x:2x$$ multiply them together to get ratio of the distances
Therefore, since the sum of the two distances is the unknown multiplier and equals the distance of 1000, $$20x = 1000$$, $$x = 50$$

Option E.
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Joined: 16 Aug 2015
Posts: 18
Location: India
Re: Car A travels at three times the average speed of car B. Car A started  [#permalink]

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15 May 2018, 00:09
Let x be the average speed of B. That gives average speed of A as 3x

Total distance = 3x*(18-12) + x*(18-16) = 1000

Solving this, x = 50

Ans: E
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Re: Car A travels at three times the average speed of car B. Car A started  [#permalink]

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14 Jul 2018, 08:25
Bunuel wrote:
Car A travels at three times the average speed of car B. Car A started to travel at 12:00 o'clock, car B started to travel at 16:00 o'clock. What is the speed of car B (in Km/h) if the total distance that both cars traveled until 18:00 was 1000 Km?

A. 10.
B. 25.
C. 30.
D. 38.
E. 50.

We can let x = the speed of car B and thus 3x = the speed of car A. We see that car A has traveled for 6 hours and car B has travel for 2 hours. Thus we have:

6(3x) + 2x = 1000

20x = 1000

x = 50

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Joined: 14 Dec 2017
Posts: 518
Location: India
Re: Car A travels at three times the average speed of car B. Car A started  [#permalink]

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14 Jul 2018, 10:32
Bunuel wrote:
Car A travels at three times the average speed of car B. Car A started to travel at 12:00 o'clock, car B started to travel at 16:00 o'clock. What is the speed of car B (in Km/h) if the total distance that both cars traveled until 18:00 was 1000 Km?

A. 10.
B. 25.
C. 30.
D. 38.
E. 50.

Let average speed of car B = X, hence speed of car A = 3X

Total distance traveled = 1000 km

Car A is driven for 6 hrs & Car B is driven for 2 hrs.

We have 6*(3X) + 2*X = 1000

hence X = 50 km per hr

Thanks,
GyM
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Re: Car A travels at three times the average speed of car B. Car A started &nbs [#permalink] 14 Jul 2018, 10:32
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