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Car A travels at three times the average speed of car B. Car A started

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Car A travels at three times the average speed of car B. Car A started  [#permalink]

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New post 13 Jul 2016, 01:59
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Car A travels at three times the average speed of car B. Car A started to travel at 12:00 o'clock, car B started to travel at 16:00 o'clock. What is the speed of car B (in Km/h) if the total distance that both cars traveled until 18:00 was 1000 Km?

A. 10.
B. 25.
C. 30.
D. 38.
E. 50.

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Re: Car A travels at three times the average speed of car B. Car A started  [#permalink]

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New post 13 Jul 2016, 02:18
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Bunuel wrote:
Car A travels at three times the average speed of car B. Car A started to travel at 12:00 o'clock, car B started to travel at 16:00 o'clock. What is the speed of car B (in Km/h) if the total distance that both cars traveled until 18:00 was 1000 Km?

A. 10.
B. 25.
C. 30.
D. 38.
E. 50.


Total distance - 1000KM
Time ratio A:B - 3:1
Speed Ratio A : B - 3 : 1
So distance(speed*time) ratio will be - 3*3 : 1*1 - 9:1
So total distance travlled by B - 100KM
Time taken by B (18:00-16:00 =2) - 2 hours

Speed of B - 50 KMPH
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Re: Car A travels at three times the average speed of car B. Car A started  [#permalink]

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New post 13 Jul 2016, 04:23
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Bunuel wrote:
Car A travels at three times the average speed of car B. Car A started to travel at 12:00 o'clock, car B started to travel at 16:00 o'clock. What is the speed of car B (in Km/h) if the total distance that both cars traveled until 18:00 was 1000 Km?

A. 10.
B. 25.
C. 30.
D. 38.
E. 50.


Distance = Speed x time
Speed of Car B = x; Time Travelled = 2 Hrs
Speed of Car A = 3x; Time Travelled = 6 Hrs

x*2 + 3x*6 = 1000
=>x=50Km/Hr Ans
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Re: Car A travels at three times the average speed of car B. Car A started  [#permalink]

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New post 13 Jul 2016, 05:55
Bunuel wrote:
Car A travels at three times the average speed of car B. Car A started to travel at 12:00 o'clock, car B started to travel at 16:00 o'clock. What is the speed of car B (in Km/h) if the total distance that both cars traveled until 18:00 was 1000 Km?

A. 10.
B. 25.
C. 30.
D. 38.
E. 50.


Total distance= Distance travelled by A +Distance travelled by car B

Distance= speed*time
Distance of A= 3x * 6

Distance of B= x*2

(3x * 6) + (x*2) = 1000
x= 50 KM/hr

E is the answer
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Re: Car A travels at three times the average speed of car B. Car A started  [#permalink]

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New post 13 Jul 2016, 06:12
let Sa and Sb be the speed of car A and B
and Da and Db be the distance travelled by car A and car B
as per the question
Sa=3Sb
Da=3Sb*6=18Sb
Db=Sb*2=2Sb
18Sb+2Sb=1000
Sb=1000/20=50Km/h
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Car A travels at three times the average speed of car B. Car A started  [#permalink]

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New post 18 Jul 2016, 19:49
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\(3x:1x\) ratio of the rates, where \(x\) is the rate of car b
\(6:2\) ratio of the times
\(18x:2x\) multiply them together to get ratio of the distances
Therefore, since the sum of the two distances is the unknown multiplier and equals the distance of 1000, \(20x = 1000\), \(x = 50\)

Option E.
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Re: Car A travels at three times the average speed of car B. Car A started  [#permalink]

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New post 15 May 2018, 01:09
Let x be the average speed of B. That gives average speed of A as 3x

Total distance = 3x*(18-12) + x*(18-16) = 1000

Solving this, x = 50

Ans: E
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Re: Car A travels at three times the average speed of car B. Car A started  [#permalink]

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New post 14 Jul 2018, 09:25
Bunuel wrote:
Car A travels at three times the average speed of car B. Car A started to travel at 12:00 o'clock, car B started to travel at 16:00 o'clock. What is the speed of car B (in Km/h) if the total distance that both cars traveled until 18:00 was 1000 Km?

A. 10.
B. 25.
C. 30.
D. 38.
E. 50.


We can let x = the speed of car B and thus 3x = the speed of car A. We see that car A has traveled for 6 hours and car B has travel for 2 hours. Thus we have:

6(3x) + 2x = 1000

20x = 1000

x = 50

Answer: E
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Re: Car A travels at three times the average speed of car B. Car A started  [#permalink]

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New post 14 Jul 2018, 11:32
Bunuel wrote:
Car A travels at three times the average speed of car B. Car A started to travel at 12:00 o'clock, car B started to travel at 16:00 o'clock. What is the speed of car B (in Km/h) if the total distance that both cars traveled until 18:00 was 1000 Km?

A. 10.
B. 25.
C. 30.
D. 38.
E. 50.


Let average speed of car B = X, hence speed of car A = 3X

Total distance traveled = 1000 km

Car A is driven for 6 hrs & Car B is driven for 2 hrs.

We have 6*(3X) + 2*X = 1000

hence X = 50 km per hr


Answer E.


Thanks,
GyM
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Re: Car A travels at three times the average speed of car B. Car A started &nbs [#permalink] 14 Jul 2018, 11:32
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