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Cars Y and Z travel side by side at the same rate of speed

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Director
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Cars Y and Z travel side by side at the same rate of speed [#permalink]

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New post 07 Oct 2008, 00:29
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Cars Y and Z travel side by side at the same rate of speed along parallel roads as shown above. When car Y reaches point P, it forks to the left at angle x, changes speed and continues to stay even with car Z as shown by the dotted line. The speed of car Y beyond point P is what percent of the speed of car Z?

1) The speed of car Z is 50 miles per hour

2) x=45


(sorry about the crappy drawing)
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Re: DS: veritas prep cars [#permalink]

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New post 07 Oct 2008, 00:47
B for me.

If the speed of car z is s mph then, speed of car y will be x/sqrt2 mph and percentage can be found out.

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Director
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Re: DS: veritas prep cars [#permalink]

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New post 07 Oct 2008, 00:56
where did x/sqrt2 come from? did you use an isoceles triangle? totally lost on this one

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Re: DS: veritas prep cars [#permalink]

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New post 07 Oct 2008, 01:07
did also the veritas course and i´m completely lost on this as well?

bigtreezel - did you like the veritas course?

cheers
dom

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Re: DS: veritas prep cars [#permalink]

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New post 07 Oct 2008, 01:15
no, I just got the books from a friend that took the course. My friend ended up getting 730, but he was scoring pretty high before the course

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Re: DS: veritas prep cars [#permalink]

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New post 07 Oct 2008, 03:31
bigtreezl wrote:
where did x/sqrt2 come from? did you use an isoceles triangle? totally lost on this one


You are right. Stmt2 gives one of the angles as 45 degree and since this is a right angled triangle, it will be an isosceles triangle.

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Re: DS: veritas prep cars [#permalink]

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New post 07 Oct 2008, 05:09
friends

can someone pls write down the exact distance&rate formula workout so that i (we) can follow your concepts?

cheers

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Re: DS: veritas prep cars   [#permalink] 07 Oct 2008, 05:09
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Cars Y and Z travel side by side at the same rate of speed

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