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Cheever College offers several online courses via remote computer conn
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Cheever College offers several online courses via remote computer connection, in addition to traditional classroombased courses. A study of student performance at Cheever found that, overall, the average student grade for online courses matched that for classroombased courses. In this calculation of the average grade, course withdrawals were weighted as equivalent to a course failure, and the rate of withdrawal was much lower for students enrolled in classroombased courses than for students enrolled in online courses. If the statements above are true, which of the following must also be true of Cheever College? (A) Among students who did not withdraw, students enrolled in online courses got higher grades, on average, than students enrolled in classroombased courses. (B) The number of students enrolled per course at the start of the school term is much higher, on average, for the online courses than for the classroombased courses. (C) There are no students who take both an online and a classroombased course in the same school term. (D) Among Cheever College students with the best grades, a significant majority take online, rather than classroombased, courses. (E) Courses offered online tend to deal with subject matter that is less challenging than that of classroombased courses. Verbal Question of The Day: Day 199: Critical Reasoning Subscribe to GMAT Question of the Day: Email  RSSFor All QOTD Questions Click Here
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Originally posted by GMATD11 on 12 May 2011, 01:37.
Last edited by Bunuel on 26 Oct 2018, 03:04, edited 1 time in total.
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Re: Cheever College offers several online courses via remote computer conn
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12 Jan 2018, 01:52
Here we have another inference question, so we don't have a conclusion with a wellstructured line of reasoning. As always, make sure that you clearly understand the given information and pay attention to the details:  Cheever College offers traditional classroombased courses (CBCs) AND several online courses (OCs) via remote computer connection.
 According to a study, the average student grade for OCs was the same as the average student grade for CBCs.
 When calculating average grade for that study, course withdrawals were weighted as equivalent to a course failure.
 The rate of withdrawal was much lower for CBC students than for OC students.
OC students were more likely to withdraw. In the eyes of the study, those students who withdrew failed the course. So before factoring in the students who did NOT withdraw, we are starting with a higher proportion of failure among the OC students. For example, if there were twice as many withdrawals from OCs as there were from CBCs, then we'd be starting with a failure rate that is twice as high among OC students as it is for CBC students (again, BEFORE factoring in the students who did not withdraw). Now let's factor in the students who did NOT withdraw. Let's say that the average grade among OC students who did not withdraw was the SAME as the average grade among CBC students who did not withdraw. As stated above, there were more OC withdrawals. So if the nonwithdrawal averages are equal and there are more OC withdrawals, then the overall average of OC students would have to be lower than the overall average of CBC students. But we are told that this is not the case and that the overall averages are the same for both groups. Remember, when we are just looking at the withdrawals, we are starting with a higher failure proportion among OC students. In order for the average of the OC students to "catchup" to the average of the CBC students, the average of the OC students who did NOT withdraw would have to be HIGHER than the average of the CBC students who did not withdraw. Otherwise, the CBC students would have a higher overall average. Quote: (A) Among students who did not withdraw, students enrolled in online courses got higher grades, on average, than students enrolled in classroombased courses. As described in the preceding analysis, choice (A) has to be true. Keep this one. Quote: (B) The number of students enrolled per course at the start of the school term is much higher, on average, for the online courses than for the classroombased courses. The study is concerned with AVERAGE grades, so we cannot determine anything about the actual number of students per course. Eliminate (B). Quote: (C) There are no students who take both an online and a classroombased course in the same school term. The study compares average student grade for OCs to average student grade for CBCs. This study could be conducted even if some students took both types of courses. The study would simply include the student's OC grades in the OC average and include the student's CBC grades in the CBC average. So we might have students who took both types and we might not. (C) cannot be determined. Quote: (D) Among Cheever College students with the best grades, a significant majority take online, rather than classroombased, courses. As with choice (B), the findings involve AVERAGE grades. It is certainly possible that a large portion of the students with the BEST grades took CBCs. As long as the AVERAGE of OC students who did not withdraw was higher than the AVERAGE of the CBC students who did not withdraw, it doesn't matter which group has the students with the BEST grades. For example, it is possible that the 10 best students all took CBCs, the rest of the CBC students did poorly, and most of the OC students did fairly well. Choice (D) might be true, but we don't know for sure. And we certainly cannot determine that a significant majority of the students with the best grades took OCs rather than CBCs. Eliminate (D). Quote: (E) Courses offered online tend to deal with subject matter that is less challenging than that of classroombased courses. The information in the passage does not offer any evidence to EXPLAIN the data. All we can determine is that the average of the OC students who did NOT withdraw has to be higher than the average of the CBC students who did not withdraw. A number of factors could explain this result (better teachers, better courses, etc). Choice (E) is a possible explanation, but we cannot determine whether it is true based on the information in the passage. Eliminate (E). Choice (A) is the only statement that HAS to be true.
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OG12 Q31
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30 Sep 2013, 21:29
Cheever College offers several online courses via remote computer connection, in addition to traditional classroombased courses. A study of student performance at Cheever found that, overall, the average student grade for online courses matched that for classroombased courses. In this calculation of the average grade, course withdrawals were weighted as equivalent to a course failure, and the rate of withdrawal was much lower for students enrolled in classroombased courses than for students enrolled in online courses. If the statements above are true, which of the following must also be true of Cheever College? (A) Among students who did not withdraw, students enrolled in online courses got higher grades, on average, than students enrolled in classroombased courses. (B) The number of students enrolled per course at the start of the school term is much higher, on average, for the online courses than for the classroombased courses. (C) There are no students who take both an online and a classroombased course in the same school term. (D) Among Cheever College students with the best grades, a significant majority take online, rather than classroom based, courses. (E) Courses offered online tend to deal with subject matter that is less challenging than that of classroombased courses.
I am facing difficulty in solving this problem.
Using Inference technique as mentioned, i was able to eliminate
Option C  OFS Option D  OFS (best grade is not talked in the passage) Option E  OFS (less complex subject not discussed in argument)
Option A  iSAWT (I felt student who didnt withdraw got higher score is not right answer choice as the argument is only about the enrolled/withdrawl student count)
Hence, I marked option B as right choice.
Please help me in understanding what i am missing in making logical structure of this argument and in doing prethinking.
Thanks, Ankur



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Re: OG12 Q31
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02 Oct 2013, 01:17
ankurjohar wrote: Cheever College offers several online courses via remote computer connection, in addition to traditional classroombased courses. A study of student performance at Cheever found that, overall, the average student grade for online courses matched that for classroombased courses. In this calculation of the average grade, course withdrawals were weighted as equivalent to a course failure, and the rate of withdrawal was much lower for students enrolled in classroombased courses than for students enrolled in online courses. If the statements above are true, which of the following must also be true of Cheever College? (A) Among students who did not withdraw, students enrolled in online courses got higher grades, on average, than students enrolled in classroombased courses. (B) The number of students enrolled per course at the start of the school term is much higher, on average, for the online courses than for the classroombased courses. (C) There are no students who take both an online and a classroombased course in the same school term. (D) Among Cheever College students with the best grades, a significant majority take online, rather than classroom based, courses. (E) Courses offered online tend to deal with subject matter that is less challenging than that of classroombased courses.
I am facing difficulty in solving this problem.
Using Inference technique as mentioned, i was able to eliminate
Option C  OFS Option D  OFS (best grade is not talked in the passage) Option E  OFS (less complex subject not discussed in argument)
Option A  iSAWT (I felt student who didnt withdraw got higher score is not right answer choice as the argument is only about the enrolled/withdrawl student count)
Hence, I marked option B as right choice.
Please help me in understanding what i am missing in making logical structure of this argument and in doing prethinking.
Thanks, Ankur Hi Ankur, You are correct in rejecting options C, D, and E as OFS. However, the reasons for selecting option B and rejecting option A are correct. First, let's talk about option B: (B) The number of students enrolled per course at the start of the school term is much higher, on average, for the online courses than for the classroombased courses. Nowhere does the passage talk about number of students. The passage only talks about withdrawal rate, which refers to proportion of students who withdraw from the course. We do not know anything about the number of students in either traditional or online courses. So, option B is incorrect. Coming to option A: (A) Among students who did not withdraw, students enrolled in online courses got higher grades, on average, than students enrolled in classroombased courses. You are correct that the passage only talks about students who withdrew and not about students who did not withdrew. But what is the relation between students who withdrew and students who did not withdrew? The relation is: Students who did not withdrew + Students who withdrew = Total number of students enrolled Now, we are given average grade for all the enrolled students and we also know average grade of Students who withdrew  the grade is "0" or "failed". From this, don't you think we can make some judgement about the average of students who did not withdrew. We can! If average grade for "all enrolled students" was same for traditional and online courses And "Number of students who withdrew i.e. who got "Fail" grade" were higher for online courses than traditional courses Then, in such a case, the average grade of students who did not withdrew must be higher for online courses than traditional courses. Do you get it? If you look back now, you can see that Students who did not withdrew and Students who withdrew constitute all the students. Right? In such cases, where two sets constitute everything or the universe, then in a lot of cases, on the basis of information of one set, we can make inferences about the other set. Does it help? Thanks, Chiranjeev
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Re: Cheever College offers several online courses via remote computer conn
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07 May 2014, 23:51
Cheever College offers several online courses via remote computer connection, in addition to traditional classroombased courses. A study of student performance at Cheever found that, overall, the average student grade for online courses matched that for classroombased courses. In this calculation of the average grade, course withdrawals were weighted as equivalent to a course failure, and the rate of withdrawal was much lower for students enrolled in classroombased courses than for students enrolled in online courses.
If the statements above are true, which of the following must also be true of Cheever College?
(A) Among students who did not withdraw, students enrolled in online courses got higher grades, on average, than students enrolled in classroombased courses. (B) The number of students enrolled per course at the start of the school term is much higher, on average, for the online courses than for the classroombased courses. (C) There are no students who take both an online and a classroombased course in the same school term. (D) Among Cheever College students with the best grades, a significant majority take online, rather than classroombased, courses. (E) Courses offered online tend to deal with subject matter that is less challenging than that of classroombased courses.
the average student grade for online courses = the average student grade for classroombased courses withdrawal= failure withdrawal for online courses > withdrawal for classroombased courses
so it can be deduced A : to have the same average with students in classroombased courses, students in online courses should get higher grades on average to compensate the higher withdrawal.
D is not correct bcz in the argument we don't care about the best grades, higher grades is enough to justify the equation. consider the following scenario:
in classroom based courses: total #enrolled: 30 #withdrawal: 1 (consider withdrawal score 0) #best score 100/100: 3 if we consider passing score 50, and if we consider the worst case: # of who just passed : 26 ave= 3*100+ 26*50= 1600/30=53.3
in online courses: total #enrolled: 30 #withdrawal: 5 #best score 100/100: 1 and consider the best case for this group: the remaining got 99/100
ave= (100+ 24*99)/30=82.53
so, in this case the average must be higher in classroombased courses. and we can see what is matter here is the average higher grades not the best grades.



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Re: Cheever College offers several online courses via remote computer conn
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08 Jan 2018, 12:32
Cheever College offers several online courses via remote computer connection, in addition to traditional classroombased courses. A study of student performance at Cheever found that, overall, the average student grade for online courses matched that for classroombased courses. In this calculation of the average grade, course withdrawals were weighted as equivalent to a course failure, and the rate of withdrawal was much lower for students enrolled in classroombased courses than for students enrolled in online courses. If the statements above are true, which of the following must also be true of Cheever College? (A) Among students who did not withdraw, students enrolled in online courses got higher grades, on average, than students enrolled in classroombased courses.  Correct(B) The number of students enrolled per course at the start of the school term is much higher, on average, for the online courses than for the classroombased courses.  We can't say anything about the number of students(C) There are no students who take both an online and a classroombased course in the same school term.  Can't say(D) Among Cheever College students with the best grades, a significant majority take online, rather than classroombased, courses.  Can't say anything about the "best" students. We just know about the "average".(E) Courses offered online tend to deal with subject matter that is less challenging than that of classroombased courses.  Challenging? out of scope
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Re: Cheever College offers several online courses via remote computer conn
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12 Jan 2018, 12:13
souvik101990 wrote: Verbal Question of The Day: Day 199: Critical Reasoning Subscribe to GMAT Question of the Day: Email  RSSFor All QOTD Questions Click HereCheever College offers several online courses via remote computer connection, in addition to traditional classroombased courses. A study of student performance at Cheever found that, overall, the average student grade for online courses matched that for classroombased courses. In this calculation of the average grade, course withdrawals were weighted as equivalent to a course failure, and the rate of withdrawal was much lower for students enrolled in classroombased courses than for students enrolled in online courses. If the statements above are true, which of the following must also be true of Cheever College? (A) Among students who did not withdraw, students enrolled in online courses got higher grades, on average, than students enrolled in classroombased courses. (B) The number of students enrolled per course at the start of the school term is much higher, on average, for the online courses than for the classroombased courses. (C) There are no students who take both an online and a classroombased course in the same school term. (D) Among Cheever College students with the best grades, a significant majority take online, rather than classroombased, courses. (E) Courses offered online tend to deal with subject matter that is less challenging than that of classroombased courses. Every question of the day will be followed by an expert reply by GMATNinja in 1215 hours. Stay tuned! Post your answers and explanations to earn kudos. IMO  A Option A  Correct answer; If classroom guys got less F than online course enrolled guys but still have the similar average grade, the guys who completed online course must have had better grades than classroom enrolled guys. B  Not necessary with given stem info. C  Irrelevant, no information provided D  Information is provided about the average grade, not the best grades. Also, no other information available about numbers of classroom students and remote course enrolled students. E  As per stem, we are talking about each course average grade comparison so out of scope.
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Re: Cheever College offers several online courses via remote computer conn
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06 Mar 2019, 10:16
GMATD11 wrote: Cheever College offers several online courses via remote computer connection, in addition to traditional classroombased courses. A study of student performance at Cheever found that, overall, the average student grade for online courses matched that for classroombased courses. In this calculation of the average grade, course withdrawals were weighted as equivalent to a course failure, and the rate of withdrawal was much lower for students enrolled in classroombased courses than for students enrolled in online courses.
If the statements above are true, which of the following must also be true of Cheever College?
(A) Among students who did not withdraw, students enrolled in online courses got higher grades, on average, than students enrolled in classroombased courses. Logical consequence of the passage. Apply statistics from quant. makes sense(B) The number of students enrolled per course at the start of the school term is much higher, on average, for the online courses than for the classroombased courses. New information. The passage doesn't provide the number of students enrolled at the start of the school term(C) There are no students who take both an online and a classroombased course in the same school term. New information(D) Among Cheever College students with the best grades, a significant majority take online, rather than classroombased, courses. This is a could be true option. Like a not sufficient DS statement, you will get both yes and no answer for this (E) Courses offered online tend to deal with subject matter that is less challenging than that of classroombased courses. New information
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Re: Cheever College offers several online courses via remote computer conn
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11 Jun 2019, 19:32
ankurjohar wrote: Cheever College offers several online courses via remote computer connection, in addition to traditional classroombased courses. A study of student performance at Cheever found that, overall, the average student grade for online courses matched that for classroombased courses. In this calculation of the average grade, course withdrawals were weighted as equivalent to a course failure, and the rate of withdrawal was much lower for students enrolled in classroombased courses than for students enrolled in online courses. If the statements above are true, which of the following must also be true of Cheever College? (A) Among students who did not withdraw, students enrolled in online courses got higher grades, on average, than students enrolled in classroombased courses. (B) The number of students enrolled per course at the start of the school term is much higher, on average, for the online courses than for the classroombased courses. (C) There are no students who take both an online and a classroombased course in the same school term. (D) Among Cheever College students with the best grades, a significant majority take online, rather than classroom based, courses. (E) Courses offered online tend to deal with subject matter that is less challenging than that of classroombased courses.
I am facing difficulty in solving this problem.
Using Inference technique as mentioned, i was able to eliminate
Option C  OFS Option D  OFS (best grade is not talked in the passage) Option E  OFS (less complex subject not discussed in argument)
Option A  iSAWT (I felt student who didnt withdraw got higher score is not right answer choice as the argument is only about the enrolled/withdrawl student count)
Hence, I marked option B as right choice.
Please help me in understanding what i am missing in making logical structure of this argument and in doing prethinking.
Thanks, Ankur Hi Ankur Let us start form the basics 1. Average of online students = average of Offline students 2. More withdrawals in Online = more fail grades in Online 3. Average of online Students = (Average of passed online candidates X number of passed candidates + 0 X number of Failed online candidates) / Total online candidates Average of Offline Students = (Average of passed offline candidates X number of passed candidates + 0 X number of Failed offline candidates) / Total Offline candidates now both the averages are equal and there are more proportion of failed candidates in Online students. So for the overall averages to be equal the passed online candidates would have performed better than passed offline candidates. I hope the above explanation clarifies.



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Re: Cheever College offers several online courses via remote computer conn
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12 Jun 2019, 06:56
Aarjay wrote: ankurjohar wrote: Cheever College offers several online courses via remote computer connection, in addition to traditional classroombased courses. A study of student performance at Cheever found that, overall, the average student grade for online courses matched that for classroombased courses. In this calculation of the average grade, course withdrawals were weighted as equivalent to a course failure, and the rate of withdrawal was much lower for students enrolled in classroombased courses than for students enrolled in online courses. If the statements above are true, which of the following must also be true of Cheever College? (A) Among students who did not withdraw, students enrolled in online courses got higher grades, on average, than students enrolled in classroombased courses. (B) The number of students enrolled per course at the start of the school term is much higher, on average, for the online courses than for the classroombased courses. (C) There are no students who take both an online and a classroombased course in the same school term. (D) Among Cheever College students with the best grades, a significant majority take online, rather than classroom based, courses. (E) Courses offered online tend to deal with subject matter that is less challenging than that of classroombased courses.
I am facing difficulty in solving this problem.
Using Inference technique as mentioned, i was able to eliminate
Option C  OFS Option D  OFS (best grade is not talked in the passage) Option E  OFS (less complex subject not discussed in argument)
Option A  iSAWT (I felt student who didnt withdraw got higher score is not right answer choice as the argument is only about the enrolled/withdrawl student count)
Hence, I marked option B as right choice.
Please help me in understanding what i am missing in making logical structure of this argument and in doing prethinking.
Thanks, Ankur Hi Ankur Let us start form the basics 1. Average of online students = average of Offline students 2. More withdrawals in Online = more fail grades in Online 3. Average of online Students = (Average of passed online candidates X number of passed candidates + 0 X number of Failed online candidates) / Total online candidates Average of Offline Students = (Average of passed offline candidates X number of passed candidates + 0 X number of Failed offline candidates) / Total Offline candidates now both the averages are equal and there are more proportion of failed candidates in Online students. So for the overall averages to be equal the passed online candidates would have performed better than passed offline candidates. I hope the above explanation clarifies. Hi [quote="Aarjay"] I understood your reasoning for A. But I'm not able to eliminate B Extending the logic from A...average is equal of 2 groups despite the withdrawls/failures numbers. Now if there wernt so many withdrawals in online classes then the average wouldn't have been same between the 2 groups and thus online classes average would infact be less.....this would be because of more number of people who dint withdaw Posted from my mobile device
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Re: Cheever College offers several online courses via remote computer conn
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29 Jun 2019, 23:52
bb61 wrote: Cheever College offers several online courses via remote computer connection, in addition to traditional classroombased courses. A study of student performance at Cheever found that, overall, the average student grade for online courses matched that for classroombased courses. In this calculation of the average grade, course withdrawals were weighted as equivalent to a course failure, and the rate of withdrawal was much lower for students enrolled in classroombased courses than for students enrolled in online courses.
If the statements above are true, which of the following must also be true of Cheever College?
(A) Among students who did not withdraw, students enrolled in online courses got higher grades, on average, than students enrolled in classroombased courses. (B) The number of students enrolled per course at the start of the school term is much higher, on average, for the online courses than for the classroombased courses. (C) There are no students who take both an online and a classroombased course in the same school term. (D) Among Cheever College students with the best grades, a significant majority take online, rather than classroombased, courses. (E) Courses offered online tend to deal with subject matter that is less challenging than that of classroombased courses.
the average student grade for online courses = the average student grade for classroombased courses withdrawal= failure withdrawal for online courses > withdrawal for classroombased courses
so it can be deduced A : to have the same average with students in classroombased courses, students in online courses should get higher grades on average to compensate the higher withdrawal.
D is not correct bcz in the argument we don't care about the best grades, higher grades is enough to justify the equation. consider the following scenario:
in classroom based courses: total #enrolled: 30 #withdrawal: 1 (consider withdrawal score 0) #best score 100/100: 3 if we consider passing score 50, and if we consider the worst case: # of who just passed : 26 ave= 3*100+ 26*50= 1600/30=53.3
in online courses: total #enrolled: 30 #withdrawal: 5 #best score 100/100: 1 and consider the best case for this group: the remaining got 99/100
ave= (100+ 24*99)/30=82.53
so, in this case the average must be higher in classroombased courses. and we can see what is matter here is the average higher grades not the best grades. How do we know that total students in both the courses should be equal? (E.g. 30 Taken here) It could be 100 for Online & 30 for Class Room. I did apply various math still not clear on how can we derive to A a the answer. I would appreciate if someone can explain through math.




Re: Cheever College offers several online courses via remote computer conn
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