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# Circle Q has radius r. Circle P has a radius that is 50% greater than

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Joined: 02 Sep 2009
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Circle Q has radius r. Circle P has a radius that is 50% greater than  [#permalink]

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05 Mar 2019, 04:43
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Difficulty:

35% (medium)

Question Stats:

78% (01:04) correct 22% (01:59) wrong based on 18 sessions

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Circle Q has radius r. Circle P has a radius that is 50% greater than r. In terms of r, what is the area of circle P ?

A. $$\frac{\pi r^2}{2}$$

B. $$\frac{3\pi r^2}{2}$$

C. $$2\pi r^2$$

D. $$\frac{9\pi r^2}{4}$$

E. $$3\pi r^2$$

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Re: Circle Q has radius r. Circle P has a radius that is 50% greater than  [#permalink]

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05 Mar 2019, 11:04
Bunuel wrote:
Circle Q has radius r. Circle P has a radius that is 50% greater than r. In terms of r, what is the area of circle P ?

A. $$\frac{\pi r^2}{2}$$

B. $$\frac{3\pi r^2}{2}$$

C. $$2\pi r^2$$

D. $$\frac{9\pi r^2}{4}$$

E. $$3\pi r^2$$

let radius of circle Q = 2 and circle p = 3
so area of P = 9Pi
$$\frac{9\pi r^2}{4}$$
option D sufficies
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Re: Circle Q has radius r. Circle P has a radius that is 50% greater than  [#permalink]

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05 Mar 2019, 17:39
Bunuel wrote:
Circle Q has radius r. Circle P has a radius that is 50% greater than r. In terms of r, what is the area of circle P ?

A. $$\frac{\pi r^2}{2}$$

B. $$\frac{3\pi r^2}{2}$$

C. $$2\pi r^2$$

D. $$\frac{9\pi r^2}{4}$$

E. $$3\pi r^2$$

Radius of Circle $$Q = r$$

Radius of Circle $$P = 50$$% greater than $$r = r + \frac{50}{100}r = \frac{100r + 50r}{100} = \frac{150r}{100} = \frac{3}{2}r$$

Area of Circle $$P = {\pi}*(\frac{3}{2}r)^2$$ $$= \frac{9\pi r^2}{4}$$

Re: Circle Q has radius r. Circle P has a radius that is 50% greater than   [#permalink] 05 Mar 2019, 17:39
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# Circle Q has radius r. Circle P has a radius that is 50% greater than

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