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Circle Q has radius r. Circle P has a radius that is 50% greater than

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Math Expert
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V
Joined: 02 Sep 2009
Posts: 58464
Circle Q has radius r. Circle P has a radius that is 50% greater than  [#permalink]

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New post 05 Mar 2019, 04:43
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A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

82% (01:05) correct 18% (02:00) wrong based on 28 sessions

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D
Joined: 18 Aug 2017
Posts: 5043
Location: India
Concentration: Sustainability, Marketing
GPA: 4
WE: Marketing (Energy and Utilities)
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Re: Circle Q has radius r. Circle P has a radius that is 50% greater than  [#permalink]

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New post 05 Mar 2019, 11:04
Bunuel wrote:
Circle Q has radius r. Circle P has a radius that is 50% greater than r. In terms of r, what is the area of circle P ?


A. \(\frac{\pi r^2}{2}\)

B. \(\frac{3\pi r^2}{2}\)

C. \(2\pi r^2\)

D. \(\frac{9\pi r^2}{4}\)

E. \(3\pi r^2\)


let radius of circle Q = 2 and circle p = 3
so area of P = 9Pi
\(\frac{9\pi r^2}{4}\)
option D sufficies
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Re: Circle Q has radius r. Circle P has a radius that is 50% greater than  [#permalink]

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New post 05 Mar 2019, 17:39
Bunuel wrote:
Circle Q has radius r. Circle P has a radius that is 50% greater than r. In terms of r, what is the area of circle P ?


A. \(\frac{\pi r^2}{2}\)

B. \(\frac{3\pi r^2}{2}\)

C. \(2\pi r^2\)

D. \(\frac{9\pi r^2}{4}\)

E. \(3\pi r^2\)


Radius of Circle \(Q = r\)

Radius of Circle \(P = 50\)% greater than \(r = r + \frac{50}{100}r = \frac{100r + 50r}{100} = \frac{150r}{100} = \frac{3}{2}r\)

Area of Circle \(P = {\pi}*(\frac{3}{2}r)^2\) \(= \frac{9\pi r^2}{4}\)

Answer D
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Re: Circle Q has radius r. Circle P has a radius that is 50% greater than   [#permalink] 05 Mar 2019, 17:39
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