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07 Jul 2014, 06:47
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Hi,
Need assistance.
How do we find out if the circle(x-a)^2+(y-b)^2=9 has its center at (0,0)?
Thanks
Need assistance.
How do we find out if the circle(x-a)^2+(y-b)^2=9 has its center at (0,0)?
Thanks
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07 Jul 2014, 09:22
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anujpadia
HI there,
A circle with the equation \((x-a)^2\) \(+\) \((y-b)^2\) \(=\) \(c^2\) has its radius at the point with coordinates \((a,b)\) and has a radius of \(c\) units.
Hope this helps.
08 Jul 2014, 02:15
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Suppose if we have the values of (a=1 and b=1) for the question(x-a)^2+(y-b)^2=4
Do we require both values to find out or how do we go about it?
Do we require both values to find out or how do we go about it?
