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Company P had 15 percent more employees in December than it [#permalink]
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08 Oct 2012, 01:49
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Re: Company P had 15 percent more employees in December than it [#permalink]
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Re: Company P had 15 percent more employees in December than it [#permalink]
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08 Oct 2012, 02:31
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No. of employees in December = 1.15 * No. of employees in January No. of employees in January = No. of employees in december / 1.15 = 460/1.15 = 400 Answer is B.
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Re: Company P had 15 percent more employees in December than it [#permalink]
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08 Oct 2012, 02:47
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Number of employees in Jan = 460 /1.15 = 400 Answer B
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Re: Company P had 15 percent more employees in December than it [#permalink]
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08 Oct 2012, 04:39
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Bunuel wrote: Company P had 15 percent more employees in December than it had in January. If Company P had 460 employees in December, how many employees did it have in January?
(A) 391 (B) 400 (C) 410 (D) 423 (E) 445
Since \(15%=\frac{15}{100}=\frac{3}{20}\), it means that \(460\) represents \(23/20\) of the number of employees in January. Then, \(1/20\) of that number is \(460/23 = 20.\) Therefore, the number of employees in January was \(20\cdot20=400.\) Answer B. PS Bunuel, just another small typo...see above ( slution). And I am mad at myself, why I didn't see it before...
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Last edited by EvaJager on 08 Oct 2012, 07:11, edited 2 times in total.



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Re: Company P had 15 percent more employees in December than it [#permalink]
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08 Oct 2012, 04:53
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If J = # of employees in January, and D = # of employees in December.. D = (J + 15% of J) = (1.15)*J Plug in known values (D = 460)Therefore, (1.15)*J = 460 Solve for JJ = 460/(1.15) = 400 B
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Re: Company P had 15 percent more employees in December than it [#permalink]
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08 Oct 2012, 06:49
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Let the no. of employees in Jan=x Therefore the no.of employees in Dec will be =Total employees in Jan PLUS increased no of employees =>{x + (15% of x)} => 1.15x It is given that; Total no.of employees in Dec = 460 so, 1.15x=460 solve for x , we will get x= 400 Answer: B
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Re: Company P had 15 percent more employees in December than it [#permalink]
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09 Oct 2012, 22:05
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First, we need to determine which one to use for base January or December, that is whether, J= 1.15D Or 0.85J = D The question says . employees in December are 15% more than in January. Therefore we are actually taking J as base and hence get number of employees in December as D=115% of J => 1.15J Or 1.15J =460 => J =400 Ans (B)
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Re: Company P had 15 percent more employees in December than it [#permalink]
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11 Oct 2012, 03:39
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please. experts can give an opinion about the level (real) of this question ?? of course I know that is not important the level but to solve it 300 or 700 no matter what back to question. J  D X 1.15 1.15 x = 460 X = 400 B in 30 seconds ( thanks to sleepless nights) or 1.15 is what % of 460 > translate 1.15 = x/100 * 460 > = 4 only B fits the bill C should not possible following this process of reasoning
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Re: Company P had 15 percent more employees in December than it [#permalink]
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16 Feb 2013, 12:19
Okay, so now i ve fallen into this really Stupid trap here . I got A) 391 . 15% of 460 is 69 . So i did 46069 = 391 . I know i am wrong now and this is a dumb mistake . But what am i missing here ?? Kindly Help.. Thanks in Advance



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Re: Company P had 15 percent more employees in December than it [#permalink]
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16 Feb 2013, 12:57
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thinktank wrote: Okay, so now i ve fallen into this really Stupid trap here . I got A) 391 . 15% of 460 is 69 . So i did 46069 = 391 . I know i am wrong now and this is a dumb mistake . But what am i missing here ?? Kindly Help.. Thanks in Advance If 100 is increased by 50%, we get 150. However if 150 is decreased by 50% we do not get 100 and instead we get 75. The mistake you are doing is thinking that a 15% decrease from 460 is the same as a 15% increase from the right answer choice. From the above illustration, we can see that equating as such is incorrect.
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Re: Company P had 15 percent more employees in December than it [#permalink]
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28 Oct 2013, 21:53
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thinktank wrote: Okay, so now i ve fallen into this really Stupid trap here . I got A) 391 . 15% of 460 is 69 . So i did 46069 = 391 . I know i am wrong now and this is a dumb mistake . But what am i missing here ?? Kindly Help.. Thanks in Advance I solved the problem by estimation, I won't try to explain that, just for the fact that 410 could be a trap. So I'll try to explain on BackSolving the problem. Jan = 10% + +5% = December 391 39.1 (Stop Here) 400 40 20 460 410 41 (Stop here) 423 42.3 (Stop here) 445 44.5(Stop here) Both Numbers must be divisible in order to arrive at 460 or Try to Solve this way: J=15%+D D=460 Solve for J = .15+460 Multiply by 100 46000/115 = 400



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Re: Company P had 15 percent more employees in December than it [#permalink]
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just use the answer choices. 400*15/100=60 === 60+400=460. Ans B.
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Re: Company P had 15 percent more employees in December than it [#permalink]
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25 May 2014, 14:05
Bunuel wrote: Company P had 15 percent more employees in December than it had in January. If Company P had 460 employees in December, how many employees did it have in January? (A) 391 (B) 400 (C) 410 (D) 423 (E) 445 Practice Questions Question: 57 Page: 159 Difficulty: 550 I'm having a problem. I started solving this problem when December is x and January is 0.85x. IF x=460 shouldn't January be 460x0.85=391 Where am I going wrong?



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Re: Company P had 15 percent more employees in December than it [#permalink]
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25 May 2014, 14:17



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Re: Company P had 15 percent more employees in December than it [#permalink]
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03 Jun 2016, 06:33
Bunuel wrote: Company P had 15 percent more employees in December than it had in January. If Company P had 460 employees in December, how many employees did it have in January?
(A) 391 (B) 400 (C) 410 (D) 423 (E) 445 There are actually two great methods to solving a problem such like this. The first is create a simple word translation. We are given that Company P had 15 percent more employees in December than it had in January and that it had 460 employees in December. So we can say: D = number of employees in December J = number of employees in January J x 1.15 = D J x 1.15 = 460 J = 460/1.15 J = 46,000/115 = 400 Alternately, we could have looked at our answer choices and used divisibility and a little logic. We know that the answer choices represent the number of employees in January. Thus we can say the following: (Answer Choice)(1.15) = 460 Answer Choice x 115/100 = 460 Right away we can see that answer choice B stands out because it is divisible by 100. If we do the arithmetic, we see that: 400 x 115/100 = 400/100 x 115 = 4 x 115 = 460. Thus B is the correct answer.
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Re: Company P had 15 percent more employees in December than it [#permalink]
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16 Aug 2017, 10:09
15% more in December = 115% (taking employees in January = 100%)
SO, 115% = 460 100% = (?) > 460 x 100 / 115 = 400 (b)



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Company P had 15 percent more employees in December than it [#permalink]
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15 Sep 2017, 00:16
115/100 = 460 then no of employee = 460*100/115 divide by 5 460*20/23 20*20 = 400 answer B
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