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Company P had 15 percent more employees in December than it

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Company P had 15 percent more employees in December than it  [#permalink]

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New post 08 Oct 2012, 00:49
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Re: Company P had 15 percent more employees in December than it  [#permalink]

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New post 08 Oct 2012, 00:50
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Re: Company P had 15 percent more employees in December than it  [#permalink]

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New post 16 Feb 2013, 11:57
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thinktank wrote:
Okay, so now i ve fallen into this really Stupid trap here . I got A) 391 . 15% of 460 is 69 . So i did 460-69 = 391 . I know i am wrong now and this is a dumb mistake . But what am i missing here ??
Kindly Help..
Thanks in Advance


If 100 is increased by 50%, we get 150.
However if 150 is decreased by 50% we do not get 100 and instead we get 75.
The mistake you are doing is thinking that a 15% decrease from 460 is the same as a 15% increase from the right answer choice.
From the above illustration, we can see that equating as such is incorrect.
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Re: Company P had 15 percent more employees in December than it  [#permalink]

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New post 08 Oct 2012, 01:31
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No. of employees in December = 1.15 * No. of employees in January
No. of employees in January = No. of employees in december / 1.15 = 460/1.15
= 400

Answer is B.
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Re: Company P had 15 percent more employees in December than it  [#permalink]

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New post 08 Oct 2012, 01:47
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Number of employees in Jan = 460 /1.15 = 400
Answer B
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Re: Company P had 15 percent more employees in December than it  [#permalink]

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New post Updated on: 08 Oct 2012, 06:11
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Bunuel wrote:
Company P had 15 percent more employees in December than it had in January. If Company P had 460 employees in December, how many employees did it have in January?

(A) 391
(B) 400
(C) 410
(D) 423
(E) 445


Since \(15%=\frac{15}{100}=\frac{3}{20}\), it means that \(460\) represents \(23/20\) of the number of employees in January. Then, \(1/20\) of that number is \(460/23 = 20.\)
Therefore, the number of employees in January was \(20\cdot20=400.\)

Answer B.

PS Bunuel, just another small typo...see above (slution). And I am mad at myself, why I didn't see it before...
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Originally posted by EvaJager on 08 Oct 2012, 03:39.
Last edited by EvaJager on 08 Oct 2012, 06:11, edited 2 times in total.
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Re: Company P had 15 percent more employees in December than it  [#permalink]

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New post 08 Oct 2012, 03:53
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If J = # of employees in January, and D = # of employees in December..
D = (J + 15% of J) = (1.15)*J Plug in known values (D = 460)
Therefore, (1.15)*J = 460 Solve for J
J = 460/(1.15) = 400 B
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Re: Company P had 15 percent more employees in December than it  [#permalink]

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New post 08 Oct 2012, 05:49
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Let the no. of employees in Jan=x
Therefore the no.of employees in Dec will be =Total employees in Jan PLUS increased no of employees
=>{x + (15% of x)}
=> 1.15x

It is given that;
Total no.of employees in Dec = 460
so, 1.15x=460
solve for x , we will get x= 400

Answer: B
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Re: Company P had 15 percent more employees in December than it  [#permalink]

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New post 09 Oct 2012, 21:05
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First, we need to determine which one to use for base January or December, that is whether,
J= 1.15D
Or
0.85J = D

The question says . employees in December are 15% more than in January. Therefore we are actually taking J as base and hence get number of employees in December as D=115% of J => 1.15J
Or 1.15J =460 => J =400 Ans (B)
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Re: Company P had 15 percent more employees in December than it  [#permalink]

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New post 11 Oct 2012, 02:39
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please. experts can give an opinion about the level (real) of this question ?? of course I know that is not important the level but to solve it 300 or 700 no matter what

back to question.

J --------------- D

X 1.15

1.15 x = 460 X = 400 B in 30 seconds ( thanks to sleepless nights)

or 1.15 is what % of 460 ----> translate 1.15 = x/100 * 460 -----> = 4 only B fits the bill

C should not possible following this process of reasoning
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Re: Company P had 15 percent more employees in December than it  [#permalink]

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New post 16 Feb 2013, 11:19
Okay, so now i ve fallen into this really Stupid trap here . I got A) 391 . 15% of 460 is 69 . So i did 460-69 = 391 . I know i am wrong now and this is a dumb mistake . But what am i missing here ??
Kindly Help..
Thanks in Advance
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Re: Company P had 15 percent more employees in December than it  [#permalink]

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New post 28 Oct 2013, 20:53
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thinktank wrote:
Okay, so now i ve fallen into this really Stupid trap here . I got A) 391 . 15% of 460 is 69 . So i did 460-69 = 391 . I know i am wrong now and this is a dumb mistake . But what am i missing here ??
Kindly Help..
Thanks in Advance



I solved the problem by estimation, I won't try to explain that, just for the fact that 410 could be a trap. So I'll try to explain on BackSolving the problem.

Jan = 10% + +5% = December
391 39.1 (Stop Here)
400 40 20 460
410 41 (Stop here)
423 42.3 (Stop here)
445 44.5(Stop here)

Both Numbers must be divisible in order to arrive at 460

or Try to Solve this way:

J=15%+D
D=460

Solve for J = .15+460
Multiply by 100

46000/115 = 400
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Re: Company P had 15 percent more employees in December than it  [#permalink]

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New post 24 Jan 2014, 09:08
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just use the answer choices.

400*15/100=60 === 60+400=460. Ans B.
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Re: Company P had 15 percent more employees in December than it  [#permalink]

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New post 25 May 2014, 13:05
Bunuel wrote:
Company P had 15 percent more employees in December than it had in January. If Company P had 460 employees in December, how many employees did it have in January?

(A) 391
(B) 400
(C) 410
(D) 423
(E) 445

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I'm having a problem.
I started solving this problem when December is x and January is 0.85x. IF x=460 shouldn't January be 460x0.85=391

Where am I going wrong?
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Re: Company P had 15 percent more employees in December than it  [#permalink]

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New post 25 May 2014, 13:17
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bytatia wrote:
Bunuel wrote:
Company P had 15 percent more employees in December than it had in January. If Company P had 460 employees in December, how many employees did it have in January?

(A) 391
(B) 400
(C) 410
(D) 423
(E) 445


I'm having a problem.
I started solving this problem when December is x and January is 0.85x. IF x=460 shouldn't January be 460x0.85=391

Where am I going wrong?


x is 15% more than y means, that \(x=1.15y\), or that \(y=\frac{x}{1.15}\approx{0.87x}\).

\(y=0.85x\) means that y is 15% less than x, which is not the same as x is 15% more than y.
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Re: Company P had 15 percent more employees in December than it  [#permalink]

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New post 03 Jun 2016, 05:33
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Bunuel wrote:
Company P had 15 percent more employees in December than it had in January. If Company P had 460 employees in December, how many employees did it have in January?

(A) 391
(B) 400
(C) 410
(D) 423
(E) 445


There are actually two great methods to solving a problem such like this. The first is create a simple word translation. We are given that Company P had 15 percent more employees in December than it had in January and that it had 460 employees in December.

So we can say:

D = number of employees in December

J = number of employees in January

J x 1.15 = D

J x 1.15 = 460

J = 460/1.15

J = 46,000/115 = 400

Alternately, we could have looked at our answer choices and used divisibility and a little logic. We know that the answer choices represent the number of employees in January.

Thus we can say the following:

(Answer Choice)(1.15) = 460

Answer Choice x 115/100 = 460

Right away we can see that answer choice B stands out because it is divisible by 100. If we do the arithmetic, we see that:

400 x 115/100 = 400/100 x 115 = 4 x 115 = 460.

Thus B is the correct answer.
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Re: Company P had 15 percent more employees in December than it  [#permalink]

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New post 16 Aug 2017, 09:09
15% more in December = 115% (taking employees in January = 100%)

SO,
115% = 460
100% = (?) -> 460 x 100 / 115
= 400 (b)
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Company P had 15 percent more employees in December than it  [#permalink]

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New post 14 Sep 2017, 23:16
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115/100 = 460
then no of employee = 460*100/115
divide by 5
460*20/23
20*20 = 400
answer B
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Company P had 15 percent more employees in December than it  [#permalink]

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New post Updated on: 13 Mar 2019, 13:50
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Bunuel wrote:
Company P had 15 percent more employees in December than it had in January. If Company P had 460 employees in December, how many employees did it have in January?

(A) 391
(B) 400
(C) 410
(D) 423
(E) 445


Let J = # of employees in Jan
So, 1.15J = # of employees in Dec

This means that 1.15J = 460
So, J = 460/1.15 = 400

Answer: B

ASIDE: Many people will conclude that, if the December population is 15% greater than the January population, then it must be the case that the January population is 15% less than the December population. If you have this common misconception then you would have (incorrectly) answered A

To better understand the issue, examine the following example:
A = 100
B = 150
Notice that B is 50% greater than A. HOWEVER, A is not 50% less than B. In fact, A is 33 1/3% less than B.

For more on this misconception, read the following article: https://www.gmatprepnow.com/articles/co ... 93-part-ii


Cheers,
Brent
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Originally posted by BrentGMATPrepNow on 06 Sep 2018, 13:53.
Last edited by BrentGMATPrepNow on 13 Mar 2019, 13:50, edited 1 time in total.
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Re: Company P had 15 percent more employees in December than it  [#permalink]

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New post 20 Sep 2018, 06:39
[quote="thevenus"]Let the no. of employees in Jan=x
Therefore the no.of employees in Dec will be =Total employees in Jan PLUS increased no of employees
=>{x + (15% of x)}
=> 1.15x
What happened to the x+?
As per your statement it should be x+1.15x

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Re: Company P had 15 percent more employees in December than it   [#permalink] 20 Sep 2018, 06:39

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