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Computer Games Plus needs to get rid of its copies of an old

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Intern
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Joined: 22 Dec 2007
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Computer Games Plus needs to get rid of its copies of an old [#permalink]

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New post 11 Dec 2008, 23:18
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Please provide an easiest solution of the following prblem--

# Computer Games Plus needs to get rid of its copies of an old computer game. If it lowers the cost of the old computer game by $5 dollars, it can increase sales of the old computer game by 10 units and still generate exactly $100 of revenue from the old game. How many units of the old computer game did Computer Games Plus sell after implementing the new selling strategy.

A) 10
B) 15
C) 20
D) 30
E) 50

Source: Practice GMAT Problem Solving Questions of http://www.platinumgmat.com . the question link is-
http://www.platinumgmat.com/about_gmat/ ... on_id=2022

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Re: Critical Q Prb. Need Solution [#permalink]

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New post 12 Dec 2008, 09:34
i get 10..

suppose x=price and n=# of units

revenue=x*n

new revenue=> (x-5)(n+10)=100

xn=100 or n=100/x

solve for n you get n^2+10n-200 you n=10 or -20

but n is old n # of units, new # of units is 10+10=20

20 it is

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Re: Critical Q Prb. Need Solution [#permalink]

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New post 12 Dec 2008, 09:46
IMO C.

Let x be the cost of computer game earlier . So current cost = x-5 per game.

Let y be the number of units sold earlier, hence number of units now sold = y+10

x.y = 100 ( This is the catch of the problem " and still generate exactly $100 " )

(10+y)(x-5) = 100 ,
Solving both we get y = -20 or 10 , it cannot be -ive , hence y = 10

Number of units sold after the decrease in price = y+10 = 20.

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Re: Critical Q Prb. Need Solution [#permalink]

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New post 12 Dec 2008, 12:45
IMO: C.
The number of units sold before the new selling strategy was 10. But the number of units sold after implementing the strategy is 10+10=20. This is the number the question ask for. So C it is.

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Re: Critical Q Prb. Need Solution   [#permalink] 12 Dec 2008, 12:45
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