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Updated on: 01 Oct 2023, 02:53
Originally posted by Sajjad1994 on 18 Feb 2021, 10:45.
Last edited by BottomJee on 01 Oct 2023, 02:53, edited 3 times in total.
Last edited by BottomJee on 01 Oct 2023, 02:53, edited 3 times in total.
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Area of
Circle A: \(64π\) Area of
Circle B: \(4π\)
Circle A: \(64π\) Area of
Circle B: \(4π\)
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66% (01:45) correct
34%
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Consider two circles A and B for which the following is true: the diameter of circle A is 8 times the radius of circle B in centimeters.
In the table below, select the values for the areas of circle A and circle B that are consistent with the information above. Make only two selections, one in each column.
In the table below, select the values for the areas of circle A and circle B that are consistent with the information above. Make only two selections, one in each column.
|
Area of Circle A |
Area of Circle B |
-------- |
| \(4π\) | ||
| \(9π\) | ||
| \(16π\) | ||
| \(36π\) | ||
| \(64π\) |
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Official Answer
Area of
Circle A: \(64π\) Area of
Circle B: \(4π\)
Circle A: \(64π\) Area of
Circle B: \(4π\)
rocky620
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23 Feb 2021, 06:45
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Let the radius of Circle B = x, then diameter of Circle A = 8x (hence radius = 4x)
Area of Circle A = \(\pi*16x^2\)
Area of Circle B = \(\pi*x^2\)
\(\frac{Area of Circle A}{Area of Circle B}\) = \(\frac{\pi*16x^2}{\pi*x^2}\) = \(\frac{16}{1}\)
Only 4\(\pi\) & 64\(\pi\) are in this ratio. So,
Area of Circle A = \(64\pi\)
Area of Circle B = \(4\pi\)
Area of Circle A = \(\pi*16x^2\)
Area of Circle B = \(\pi*x^2\)
\(\frac{Area of Circle A}{Area of Circle B}\) = \(\frac{\pi*16x^2}{\pi*x^2}\) = \(\frac{16}{1}\)
Only 4\(\pi\) & 64\(\pi\) are in this ratio. So,
Area of Circle A = \(64\pi\)
Area of Circle B = \(4\pi\)
18 Apr 2024, 07:46
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