nalinnair
David used part of $100,000 to purchase a house. Of the remaining portion, he invested 1/3 of it at 4 percent simple annual interest and 2/3 of it at 6 percent simple annual interest. If after a year the income from the two investments totaled $320, what was the purchase price of the house?
(A) $96,000
(B) $94,000
(C) $88,000
(D) $75,000
(E) $40,000
To determine the amount he invested, we can use the simple interest formula:
P × r × t = Interest
P is the invested amount, or principal.
r is the simple annual interest rate on his investment portfolio, which, in this case, is the weighted average of the given interest rates:
(1/3)4% + (2/3)6% = 16/3% = 16/300 (Remember that in the simple interest formula, we have to use the fraction or decimal form of the interest rate.)
t = 1, since the length of the investment period is 1 year.
P × 16/300 × 1 = $320
P = (320)(300)/16 = $6,000
Therefore, the purchase price of the house was:
$100,000 - $6,000 = $94,000
Answer: B