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# Divide 64*5^(1/2) by 3*5^(1/2).

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Math Expert
Joined: 02 Sep 2009
Posts: 53020

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04 Mar 2018, 23:04
00:00

Difficulty:

5% (low)

Question Stats:

93% (00:34) correct 7% (01:02) wrong based on 68 sessions

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Divide $$6\sqrt{45}$$ by $$3\sqrt{5}$$.

(A) 4
(B) 6
(C) 9
(D) 15
(E) 54

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Re: Divide 64*5^(1/2) by 3*5^(1/2).  [#permalink]

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05 Mar 2018, 04:49
Bunuel wrote:
Divide $$6\sqrt{45}$$ by $$3\sqrt{5}$$.

(A) 4
(B) 6
(C) 9
(D) 15
(E) 54

$$6\sqrt{45}$$ / $$3\sqrt{5}$$ = $$6\sqrt{9}\sqrt{5} / 3\sqrt{5}$$

$$= 6*3 / 3 = 6$$

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Re: Divide 64*5^(1/2) by 3*5^(1/2).  [#permalink]

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05 Mar 2018, 05:57
Bunuel wrote:
Divide $$6\sqrt{45}$$ by $$3\sqrt{5}$$.

(A) 4
(B) 6
(C) 9
(D) 15
(E) 54

$$\frac{6√ 45}{3√ 5}$$

Or, $$\frac{18√5}{3√ 5}$$

Or, 6 , Answer must be (B)
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Re: Divide 64*5^(1/2) by 3*5^(1/2).  [#permalink]

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06 Mar 2018, 10:20
Bunuel wrote:
Divide $$6\sqrt{45}$$ by $$3\sqrt{5}$$.

(A) 4
(B) 6
(C) 9
(D) 15
(E) 54

(6√45)/(3√5) = 2√9 = 2 x 3 = 6

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Re: Divide 64*5^(1/2) by 3*5^(1/2).  [#permalink]

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06 Mar 2018, 10:29
Bunuel wrote:
Divide $$6\sqrt{45}$$ by $$3\sqrt{5}$$.

(A) 4
(B) 6
(C) 9
(D) 15
(E) 54

=18\sqrt{5}/3\sqrt{5}
=6
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Re: Divide 64*5^(1/2) by 3*5^(1/2).  [#permalink]

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13 Mar 2018, 09:15
1
IMO B. But the OA is E!! Can anyone explain?
Math Expert
Joined: 02 Sep 2009
Posts: 53020
Re: Divide 64*5^(1/2) by 3*5^(1/2).  [#permalink]

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13 Mar 2018, 09:22
1
urvashis09 wrote:
IMO B. But the OA is E!! Can anyone explain?

Edited. Thank you.
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Re: Divide 64*5^(1/2) by 3*5^(1/2).   [#permalink] 13 Mar 2018, 09:22
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