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ankitaprsd
Joined: 17 Jun 2014
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Location: India
Schools: ISB '15 NUS '17 CEIBS '16 Great Lakes '16 LBS '17 HEC '15 HKUST '16 Imperial '16 Boston U '16 Tepper '17 Kellogg 1YR '17 Stern '17 ESADE '17 Insead Sept '16
WE:Information Technology (Computer Software)
Schools: ISB '15 NUS '17 CEIBS '16 Great Lakes '16 LBS '17 HEC '15 HKUST '16 Imperial '16 Boston U '16 Tepper '17 Kellogg 1YR '17 Stern '17 ESADE '17 Insead Sept '16
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21 Aug 2014, 04:53
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Hi,
If somebody could help out in this
DS question :-
WHat is the length of AB ?
1)BE=3
2)DE=4
Diagram in attachment
DOUBT: This question is solved using similarity conditions, sides of similar triangles are proportional.
Since we are not given any side lengths and angles except right angle, how do we get to know which sides are proportional. THis is required because accordingly one will apply the proportionality
That is if
AB (ABD) ~ DB(BDE) and
AD(ABD)~BE(BDE)
then AB/DB= AD/BE
PS. '~' means corresponds to
OA :
D
If somebody could help out in this
DS question :-
WHat is the length of AB ?
1)BE=3
2)DE=4
Diagram in attachment
DOUBT: This question is solved using similarity conditions, sides of similar triangles are proportional.
Since we are not given any side lengths and angles except right angle, how do we get to know which sides are proportional. THis is required because accordingly one will apply the proportionality
That is if
AB (ABD) ~ DB(BDE) and
AD(ABD)~BE(BDE)
then AB/DB= AD/BE
PS. '~' means corresponds to
OA :
D
Attachments
File comment: Diagram in attached file
Diagram.jpg [ 127.45 KiB | Viewed 2673 times ]
21 Aug 2014, 07:15
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In the figure,
AB and DE are both perpendicular to BC, so AB || DE
(Using < to denote Angle)
So, <ABD = <BDE (Alternate angles)
Now, In Triangle ABD and BDE
<ABD = <BDE (proved above)
<ADB = <DEB = 90 degree
So, Third angle of both the triangles will also be equal (as sum of all three angles is 180 degree and two are same)
So, Triangle ABD ~ Triangle BDE
(Although not required but in a similar way we can prove ABD ~ BDE ~ ACB ~ BCD ~ DCE)
So, Sides will be in same ratio
So, DE/BD = BD/AB
BE = 3, DE= 4, BD = 5
So, AB = 25/4 (In both the cases)
So, Answer is D
Hope it helps!
AB and DE are both perpendicular to BC, so AB || DE
(Using < to denote Angle)
So, <ABD = <BDE (Alternate angles)
Now, In Triangle ABD and BDE
<ABD = <BDE (proved above)
<ADB = <DEB = 90 degree
So, Third angle of both the triangles will also be equal (as sum of all three angles is 180 degree and two are same)
So, Triangle ABD ~ Triangle BDE
(Although not required but in a similar way we can prove ABD ~ BDE ~ ACB ~ BCD ~ DCE)
So, Sides will be in same ratio
So, DE/BD = BD/AB
BE = 3, DE= 4, BD = 5
So, AB = 25/4 (In both the cases)
So, Answer is D
Hope it helps!
ankitaprsd
ankitaprsd
Joined: 17 Jun 2014
Last visit: 17 Apr 2017
Posts: 24
Own Kudos:
Given Kudos: 228
Location: India
Schools: ISB '15 NUS '17 CEIBS '16 Great Lakes '16 LBS '17 HEC '15 HKUST '16 Imperial '16 Boston U '16 Tepper '17 Kellogg 1YR '17 Stern '17 ESADE '17 Insead Sept '16
WE:Information Technology (Computer Software)
Schools: ISB '15 NUS '17 CEIBS '16 Great Lakes '16 LBS '17 HEC '15 HKUST '16 Imperial '16 Boston U '16 Tepper '17 Kellogg 1YR '17 Stern '17 ESADE '17 Insead Sept '16
Posts: 24
Kudos:
60
24 Aug 2014, 05:40
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thanks alot !
Your explanation helped clear my doubt.
Your explanation helped clear my doubt.
