Question 1: Okay, let us assume the number of managers are M and the number of directors are D. So the total number of employees = M +D
Average Salary of Manager = x
Average Salary of Director = y
So, we have: Total salary of all employees = Mx + Dy
Average salary of employee = Total salary/Total employees = \(\frac{Mx+Dy}{M+D}\)
Statement 1:
Average salary of manager = Average salary of employee - 5000
\(x = \frac{Mx+Dy}{M+D} - 5000\)
Cross multiplying to the other side we get:
\(x(M+D) = Mx + Dy - 5000\)
Cancelling Mx on both sides and rearranging like terms together we get:
\(D(y-x) = 5000\) - (1)
However, this doesn't say anything specific to us. So we move on to the second statement.
Statement 1:
Average salary of director = Average salary of employee + 15000
\(y = \frac{Mx+Dy}{M+D} + 15000\)
Cross multiplying to the other side we get:
\(y(M+D) = Mx + Dy + 15000\)
Cancelling Mx on both sides and rearranging like terms together we get:
\(M(y-x) = 15000\) - (2)
This doesn't say anything by itself either. But when we put the results of the two statements [(1) and (2)] together, we get:
\(D(y-x) = 5000\)
\(M(y-x) = 15000\)
Dividing statement 1 by 2 we get
\(\frac{D}{M} = \frac{5000}{15000} = \frac{1}{3}\)
M = 3D
Total = M+D = 4D
From here, we can say percentage of directors = \(\frac{D}{4D}*100 = 25%\).
Hence answer is C.