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# Each family in a locality has at most two adults, and no family has fe

Author Message
Intern
Joined: 29 Jun 2018
Posts: 15
Location: India
GMAT 1: 530 Q42 V26
GPA: 4
Each family in a locality has at most two adults, and no family has fe  [#permalink]

### Show Tags

Updated on: 09 Aug 2018, 09:34
2
00:00

Difficulty:

55% (hard)

Question Stats:

29% (01:02) correct 71% (01:14) wrong based on 7 sessions

### HideShow timer Statistics

Each family in a locality has at most two adults, and no family has fewer than 3 children. Considering all the families together, there are more adults than boys, more boys than girls, and more girls than families. Then the minimum possible number of families in the locality is :
(a) 4
(b) 5
(c) 2
(d) 3
(e) 6

Originally posted by LMP on 09 Aug 2018, 07:35.
Last edited by chetan2u on 09 Aug 2018, 09:34, edited 1 time in total.
Updated topic name
Math Expert
Joined: 02 Aug 2009
Posts: 7102
Re: Each family in a locality has at most two adults, and no family has fe  [#permalink]

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09 Aug 2018, 09:33
1
Bulusuchaitanya wrote:
Each family in a locality has at most two adults, and no family has fewer than 3 children. Considering all the families together, there are more adults than boys, more boys than girls, and more girls than families. Then the minimum possible number of families in the locality is :
(a) 4
(b) 5
(c) 2
(d) 3
(e) 6

Let us see the choices and take the least possible as per choices, so family=2
C.2
F=2
A>B>G>F........since $$A\leq{2F}.........A\leq{2*2}$$
But A>B>G>F means A=5 as 5>4>3>2
Not possible

Next choice
D.3
F=3
A>B>G>F........since $$A\leq{2F}.........A\leq{2*3}$$
And A>B>G>F means A=6 as 6>5>4>3..... possible
But what about case of children
B+G=5+4=9 and =3F.. again possible
Correct

D
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Intern
Joined: 29 Jun 2018
Posts: 15
Location: India
GMAT 1: 530 Q42 V26
GPA: 4
Re: Each family in a locality has at most two adults, and no family has fe  [#permalink]

### Show Tags

09 Aug 2018, 09:37
chetan2u wrote:
Bulusuchaitanya wrote:
Each family in a locality has at most two adults, and no family has fewer than 3 children. Considering all the families together, there are more adults than boys, more boys than girls, and more girls than families. Then the minimum possible number of families in the locality is :
(a) 4
(b) 5
(c) 2
(d) 3
(e) 6

Let us see the choices and take the least possible as per choices, so family=2
C.2
F=2
A>B>G>F........since $$A\leq{2F}.........A\leq{2*2}$$
But A>B>G>F means A=5 as 5>4>3>2
Not possible

Next choice
D.3
F=3
A>B>G>F........since $$A\leq{2F}.........A\leq{2*3}$$
And A>B>G>F means A=6 as 6>5>4>3..... possible
But what about case of children
B+G=5+4=9 and =3F.. again possible
Correct

D

Thank you Chetan2U.
Re: Each family in a locality has at most two adults, and no family has fe &nbs [#permalink] 09 Aug 2018, 09:37
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