Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 2007:30 AM PST
-08:30 AM PST
Learn what truly sets the UC Riverside MBA apart and how it helps in your professional growth
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
24 May 2024, 10:23
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
82% (01:04) correct
18%
(01:21)
wrong
based on 239
sessions
History
Date
Time
Result
Not Attempted Yet
Each of the dogs enrolled in an obedience course either passed or failed. What percent of the dogs enrolled in the course passed?
(1) Of the female dogs enrolled, 70 percent passed.
(2) Of the male dogs enrolled, 63 percent passed.
(1) Of the female dogs enrolled, 70 percent passed.
(2) Of the male dogs enrolled, 63 percent passed.
24 May 2024, 11:24
Kudos
Bookmarks
joaquincollado
We can use a 2 × 2 matrix to plot the data, as shown below
| Male | Female | ||
|---|---|---|---|
| Pass | |||
| Fail | |||
| m | x - m | x |
Statement 1
(1) Of the female dogs enrolled, 70 percent passed.
| Male | Female | ||
|---|---|---|---|
| Pass | 0.7(x-m) | ? | |
| Fail | |||
| m | x-m | x |
We have no information on male dogs. Hence, this statement alone is not sufficient. Eliminate A and D
Statement 2
(2) Of the male dogs enrolled, 63 percent passed.
| Male | Female | ||
|---|---|---|---|
| Pass | 0.63*x | ? | |
| Fail | |||
| m | x-m | x |
We have no information on female dogs. Hence, this statement alone is not sufficient. Eliminate B
Combined
| Male | Female | ||
|---|---|---|---|
| Pass | 0.63*x | 0.7(x-m) | ? |
| Fail | |||
| m | x-m | x |
Number of dogs passed = 0.63x + 0.7x - 0.7m
Percentage = \(\frac{0.63x + 0.7x - 0.7m}{x} = 1.33 - 0.7 \frac{m}{x}\)
The statements combined do not help us get the ratio \(\frac{m}{x}\). Hence, the statements combined are not sufficient either.
Option E
25 May 2024, 03:28
Kudos
Bookmarks
There are only 4 possible categories here
(1) Male Passed
(2) Female Passed
(3) Male Failed
(4) Female Failed
Also, (1) + (2) + (3) + (4) = 100 (percent)
Question: (2) + (4) = ?
Statement 1: 0.7* [(2) + (4)] = (2)
but we have no information about their actual number as percentage of total dogs hence
NOT SUFFICIENT
Statement 2: 0.63* [(1) + (3)] = (1)
but we have no information about their actual number as percentage of total dogs hence
NOT SUFFICIENT
Combining the statements
We still have no information about the total percentage of male or female dog hence
NOT SUFFICIENT
Answer: Option E
(1) Male Passed
(2) Female Passed
(3) Male Failed
(4) Female Failed
Also, (1) + (2) + (3) + (4) = 100 (percent)
Question: (2) + (4) = ?
Statement 1: 0.7* [(2) + (4)] = (2)
but we have no information about their actual number as percentage of total dogs hence
NOT SUFFICIENT
Statement 2: 0.63* [(1) + (3)] = (1)
but we have no information about their actual number as percentage of total dogs hence
NOT SUFFICIENT
Combining the statements
We still have no information about the total percentage of male or female dog hence
NOT SUFFICIENT
Answer: Option E
joaquincollado
