hellosanthosh2k2 wrote:

Great Question.

Let n = number of piglets.

Let 4x = total oats in pounds, 6y = total barley in pounds

Piglet A: \(x(1/4th) + y(1/6th) = 1.5\) ----(1)

Remaining piglets: \(3x + 5y = 1.5(n-1)\)

= \(3x + 3y + 2y = 1.5n - 1.5\)

= 3(x+y) + 2y = 1.5n - 1.5

= \(3(1.5) + 2y = 1.5n - 1.5\) (from --(1))

= \(1.5n = 6 + 2y\)

= \(n = 2(y+3)/1.5\)

=> \(n = 4(y+3)/3\)

Now note, n is an integer, also we have 4, (y+3)/3 which is a fraction,

multiplication of 4 and (y+3)/3 a fraction can yield integer, only if the fraction is multiple of 1.25

if \((y+3)/3\) = 1.25 => y = 0.75

if \((y+3)/3\) = 2.5 => y = 4.5 (but y cannot be greater than 1.5)

also y cannot be zero and make (y+3)/3 = 1 ((as given prompt, each piglet is fed some grain))

so \((y+3)/3\) must be 1.25 and n = 5 => sufficient (C)

Hello

hellosanthosh2k2,

How did u get this

\(x(1/4th) + y(1/6th) = 1.5\) . shouldn't it be 0.5.

Well i used a approach similar to yours, here is what i did

Say total piglets is x

say piglet a was fed\(\frac{1}{4}\) of and\(\frac{1}{6}\) of , then each piglet was fed\(\frac{1}{4}\)+\(\frac{1}{6}\) = \(\frac{5}{12}.\)

Remaining food is\(\frac{3}{4}+\frac{5}{6}\) =\(\frac{19}{12}\)

So the Remaining food was equally divided among (x-1) piglets with each getting \(\frac{5}{12}\)

so \(\frac{5}{12}* (x-1)= \frac{19}{12)\)

So x is some value.

Hence C is sufficient.

Probus