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Re: Each side of a certain parallelogram has length 6. If the area of the [#permalink]

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26 Jan 2008, 11:48

Since it is a PS question, I would pick D on exam. sides are equal so it most probably a rhomb. if i recall correctly, the area of a rhomb is half the product of its diagonals? d1d2 = 18*2 = 36. perhaps diagonals are equal in lenght (sqrt 36 = 6).

so we have two equilateral traingles. where angles are equal to 60 degrees.

Re: Each side of a certain parallelogram has length 6. If the area of the [#permalink]

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28 Jan 2008, 09:40

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Given each side is 6 and area is 18. We can find the altitude, ie: alt = 18/6 = 3. Now we have a triangle with one side as 6, the alt as 3, and the base which we don't know.

Using Pythagoras theorem, 6^2 = 3^2 + Base^2 => Base = 3V3 So, the sides are now 3*1, 3*V3, 3*2 => 1:V3:2, which is a 30-60-90 triangle.

Hence the angle that we know is 30, which forms a side of the parallelogram. Ans: A.

Each side of a certain parallelogram has length 6. if the [#permalink]

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25 Sep 2008, 14:26

Each side of a certain parallelogram has length 6. if the area of the parallelogram is 18. which of the following is the measure of one of its angles? A. 30’ B. 45’ C. 60’ D. 90’ E.120’

Equal sides of a parallegrame means it's a rhombus -> angle should be either 60 or 120?

Each side of a certain parallelogram has length 6. if the area of the parallelogram is 18. which of the following is the measure of one of its angles? A. 30’ B. 45’ C. 60’ D. 90’ E.120’

Equal sides of a parallegrame means it's a rhombus -> angle should be either 60 or 120?

Well, you could rule out 60 and 120 right away, because if the parallelogram had an angle of 60 degrees, it would also need to have an angle of 120 degrees (adjacent angles in a parallelogram add to 180), and then there would be two correct answers to the question, which can't happen.

The area of a parallelogram is base*height. The height of this parallelogram must be 3. We therefore need to find the angles in a right angled triangle with a hypotenuse of 6 and a height of 3. That's a 30-60-90, of course, and 30 is the angle opposite the 3, so 30 degrees is one of the angle measures in the parallelogram, and 150 the other.
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A=b*h or 1/2 d1*d2, if all 4 sides are equal then this is a rhombus, which is basically a tilted square. How can you have a height of 3 and area of 18? Shouldnt height be 6 and area 36? Is this question correctly worded?

A=b*h or 1/2 d1*d2, if all 4 sides are equal then this is a rhombus, which is basically a tilted square. How can you have a height of 3 and area of 18? Shouldnt height be 6 and area 36? Is this question correctly worded?

If you have a rhombus with sides b and c, the area will only be b*c if the rhombus is a square. Otherwise the area will be less than b*c. To find the area of a rhombus (or any other parallelogram), you need to multiply the base and the height. If your parallelogram is 'tilted' (i.e. if the angles are not all 90 degrees), then the height is definitely not one of the sides. In this example, the rhombus is pretty seriously tilted to get an area as small as 18.
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Re: Each side of a certain parallelogram has length 6. If the area of the [#permalink]

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11 Oct 2014, 05:24

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Re: Each side of a certain parallelogram has length 6. If the area of the [#permalink]

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31 Oct 2015, 11:08

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Re: Each side of a certain parallelogram has length 6. If the area of the [#permalink]

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24 May 2017, 05:39

Hello from the GMAT Club BumpBot!

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Can you be more specific with your query. If you drop a perpendicular on the base of the parallelogram then it will form a right angles triangle with one of the side of the parallelogram as its hypotenuse.

Re: Each side of a certain parallelogram has length 6. If the area of the [#permalink]

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11 Sep 2017, 00:53

We can work on options to get to the answer quickly, Option C and option E can be eliminated easily as if one angle is 60 one of the other angle has to be 120. Option D is not possible as if one angle is 90 all angles will be 90, thus it becomes a square with side 6 and area of square is 6*6 = 36. Not matching. Out of option A and option B, working on option A is easier, thus even if someone doesnt know how to work on this answer can still guess it correct.

Now working on option A we can draw a diagonal and break parallelogram into two triangles of equal area. One angle of triangle is 30 and sides are 6. Using formula area of triangle = \(\frac{1}{2}\) * a*b*sin(x) area of one triangle becomes \(\frac{1}{2}\) * 6*6*sin(30) = \(\frac{1}{2}\) * 6*6*\(\frac{1}{2}\) = 9 Thus total area = 9+9 =18 Thus option A _________________

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