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GMAT 1: 800 Q51 V49
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manishuol
Each student at a certain university is given a four-character identification code, the …rest two characters of which are digits between 0 and 9, inclusive, and the last two characters of which are selected from the 26 letters of the alphabet. If characters may be repeated and the same characters used in a different order constitute a different code, how many different identification codes can be generated following these rules?

A. 135,200
B. 67,600
C. 64,000
D. 60,840
E. 58,500

10*10*26*26

26*26 ends in a 6 and then we tack two zeros on in the hundreds and units digits.

Answer choice B.
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A B C D = THE CODE

A - .-0-9 = 10 Possibilities
B - 0-9 = 10 Possibilities
C - A-Z = 26 Possibilities
D - A-Z = 26 Possibilities

So ABCD = 10*10*26*26 = 67600
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There are ten choices to be made between 0 and 9 inclusive and there are 26 choices to be made for the alphabets

Hence, 10*10*26*26 = 67,600

Answer choice; B
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