Edgar was among those responsible for purchasing door prizes for his company’s party. Edgar purchased 6 items for $10x each = 6*10x
And y items for $30 each = Y*30
The total amount of Edgar’s door prize purchases was $600.
Such that,
60X + 30Y = 600
Or,
2X + Y = 20
Let's put value one by one.
A. 3 Put X = 3
=> 2X + Y = 20
=> 2(3)+y = 20
=> Y = 20-6
=> Y = 14 (not available value of Y) (Not sufficient)
B. 4 Put X = 4
=> 2X + Y = 20
=> 2(4)+y = 20
=> Y = 20-8
=> Y = 12 (not available value of Y) (Not sufficient)
C. 5 Put X = 5
=> 2X + Y = 20
=> 2(5)+y = 20
=> Y = 20-10
=> Y = 10 (not available value of Y) (Not sufficient)
D. 7 Put X = 3
=> 2X + Y = 20
=> 2(7)+y = 20
=> Y = 20-14
=> Y = 6 (not available value of Y) (Not sufficient)
E. 8 Put X = 3
=> 2X + Y = 20
=> 2(8)+y = 20
=> Y = 20-16
=> Y = 4 (Available value of Y) (Sufficient)
F. 9 Put X = 3
=> 2X + Y = 20
=> 2(9)+y = 20
=> Y = 20-18
=> Y = 2 (not available value of Y) (not Sufficient)
The only pair of X and Y available = (8&4)
X = 8 and Y = 4
Posted from my mobile device