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555-605 Level|   Fractions and Ratios|            
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leafsrule99
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Equal amounts of water were poured into two empty jars of different ca Updated on: 01 Aug 2021, 03:29
Originally posted by leafsrule99 on 11 Aug 2010, 14:17.
Last edited by Bunuel on 01 Aug 2021, 03:29, edited 4 times in total.
Edited the question and added the OA
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74% (01:28) correct 26% (01:37) wrong based on 2636 sessions

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Equal amounts of water were poured into two empty jars of different capacities, which made one jar 1/4 full and other jar 1/3 full. If the water in the jar with lesser capacity is then poured into the jar with greater capacity, what fraction of the larger jar will be filled with water?

A. 1/7
B. 2/7
C. 1/2
D. 7/12
E. 2/3
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C
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Bunuel
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Equal amounts of water were poured into two empty jars of different ca 11 Aug 2010, 17:21
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Equal amount of water were poured into two empty jars of different capacities, which made one jar 1/4 full and other jar 1/3 full. If the water in the jar with lesser capacity is then poured into the jar with greater capacity, what fraction of the larger jar will be filled with water?

A. 1/7
B. 2/7
C. 1/2
D. 7/12
E. 2/3

Shortcut solution:

Some amount of water made bigger jar 1/4 full, then the same amount of water (stored for a while in smaller jar) were added to bigger jar, so bigger jar is 1/4+1/4=1/2 full.

Answer: C.
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sandeeepsharma
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Equal amounts of water were poured into two empty jars of different ca 07 Dec 2011, 00:12
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Equal amounts of water were poured into both jars and this made big jar as 1/4 full then same amount from smaller jar is poured . It will make 2*(1/4)= 1/2 full
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mbafall2011
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Equal amounts of water were poured into two empty jars of different ca 10 Feb 2011, 20:15
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1/2 seems straight forward. If x amount of water fills up the jar upto 1/4th of its capacity, 2x will fill up 1/2.
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Equal amounts of water were poured into two empty jars of different ca 11 Feb 2011, 07:14
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My take on this (although Mavens like Bunuel can always expound in 2 lines)

Let v be the volume of water added to both :

v = x/4

v = y/3

x = 4v (total capacity of larger jar)

y = 3v (total capacity of smaller jar)

So v is added again to larger jar, hence total water = v+v
2v
--- = 1/2
4v
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Equal amounts of water were poured into two empty jars of different ca 04 Dec 2011, 11:29
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Capacity larger jar = x
Let 20 litters water poured into each jar
so x*1/4 = 20
x = 80
Total water of larger jar after pouring the water of smaller jar = 20+20 = 40
40/80 = 1/2
Ans. C
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Equal amounts of water were poured into two empty jars of different ca 04 May 2013, 05:52
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Hi Experts
Why below answer is wrong.....

Let the capacity of both jug X(small) & Y(big)
After pouring water... capacity of water both jug x/4 and y/3... as given x/4=y/3 so x=4y/3

now given smaller jug water poured into bigger made the equ- x/4+y/3=>3x+4y/12..putting x=4y/3...we got 2y/3 which mean 2/3 rd of y

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Equal amounts of water were poured into two empty jars of different ca 04 May 2013, 06:58
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prasannajeet
Hi Experts
Why below answer is wrong.....

Let the capacity of both jug X(small) & Y(big)
After pouring water... capacity of water both jug x/4 and y/3... as given x/4=y/3 so x=4y/3

now given smaller jug water poured into bigger made the equ- x/4+y/3=>3x+4y/12..putting x=4y/3...we got 2y/3 which mean 2/3 rd of y

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Prasannajeet

x/4=y/3, thus x is larger jar and y is smaller jar.
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Equal amounts of water were poured into two empty jars of different ca 01 Dec 2014, 01:01
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First determine which is the big one?

\(\frac{1}{4} th\) is the big container as equal quantities of water poured made it "less full"

Same quantity of water added twice, so multiply by 2

\(2 * \frac{1}{4} = \frac{1}{2}\)

Answer = C
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Equal amounts of water were poured into two empty jars of different ca 04 Jan 2015, 07:41
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I actually drew the jars to solve it, without calculating anything...

Just to give you a good laugh, I will describe how:

So, I first created one jar, and marked its 1/4th and 1/3rd. This showed me that if these were 2 jars, the one filled up to its 1/4th must be the bigger one.

Then I just drew 2 same jars, next to eac other, and marked 1/4th in one and 1/3rd in the other. I pulled the line that marked the 1/4th of one jar on the second jar, and saw that there was only a little it lower than the 1/3rd. The I realised that if I moved the rest to jar one, it would be filled half way... So, 1/2.

:) Mind that I am a psychologist... Sometimes, it is easier for me not to do the math!
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Equal amounts of water were poured into two empty jars of different ca 05 Jan 2018, 10:05
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leafsrule99
Equal amount of water were poured into two empty jars of different capacities, which made one jar 1/4 full and other jar 1/3 full. If the water in the jar with lesser capacity is then poured into the jar with greater capacity, what fraction of the larger jar will be filled with water?

A. 1/7
B. 2/7
C. 1/2
D. 7/12
E. 2/3

Let’s say that one jar has a capacity of 16 liters and the other, 12 liters. So, when equal parts water are poured into each jar, one jar has 4 liters and the other has 4 liters. When the contents of the small jar (4 liters from the 12-liter jar) are poured into the larger jar (4 litters in the 16-liter jar), the larger jar is now 8/16 = 1/2 full.

Alternate Solution:

Consider only the larger jar. When the first amount of water is poured into it, the jar becomes ¼ full. Now, a second amount of water, which is actually equal to the first amount, is poured into the larger jar. This second amount of water is also equivalent to ¼ of the jar’s capacity. Thus, the jar is now ¼ + ¼ = ½ full.

Answer: C
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Equal amounts of water were poured into two empty jars of different ca 27 Jun 2020, 08:30
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One way to solve this is by assigning values that are divisible by both 3 and 4, let one jar be 36, the other one be 48.

Posted from my mobile device
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Equal amounts of water were poured into two empty jars of different ca 31 Jul 2023, 09:03
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Equal amounts of water were poured into two empty jars of different capacities, which made one jar 1/4 full and other jar 1/3 full. If the water in the jar with lesser capacity is then poured into the jar with greater capacity, what fraction of the larger jar will be filled with water?

To ease the problem, let us first get rid of fractions and take the volume of water poured = LCM {3,4} = 12

For first jar, filled = (1/4)*V1 = 12 => V1 = 48
For second jar, filled = (1/3)*V2 = 12 => V2 = 36

If the water in the jar with lesser capacity is then poured into the jar with greater capacity, water in 1st jar = 12+12=24
fraction filled = 24/48=1/2

Hence C
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Equal amounts of water were poured into two empty jars of different ca 21 Nov 2024, 01:05
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subhashghosh
My take on this (although Mavens like Bunuel can always expound in 2 lines)

Let v be the volume of water added to both :

v = x/4

v = y/3

x = 4v (total capacity of larger jar)

y = 3v (total capacity of smaller jar)

So v is added again to larger jar, hence total water = v+v
2v
--- = 1/2
4v
We are not given the volume of these jars are equal. Hence 2v might not be possible!
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