Last visit was: 19 Nov 2025, 15:06 It is currently 19 Nov 2025, 15:06
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 19 Nov 2025
Posts: 105,390
Own Kudos:
778,363
 [5]
Given Kudos: 99,977
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,390
Kudos: 778,363
 [5]
Kudos
Add Kudos
5
Bookmarks
Bookmark this Post
User avatar
chetan2u
User avatar
GMAT Expert
Joined: 02 Aug 2009
Last visit: 15 Nov 2025
Posts: 11,238
Own Kudos:
43,706
 [3]
Given Kudos: 335
Status:Math and DI Expert
Location: India
Concentration: Human Resources, General Management
GMAT Focus 1: 735 Q90 V89 DI81
Products:
Expert
Expert reply
GMAT Focus 1: 735 Q90 V89 DI81
Posts: 11,238
Kudos: 43,706
 [3]
2
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
avatar
TarunKumar1234
Joined: 14 Jul 2020
Last visit: 28 Feb 2024
Posts: 1,107
Own Kudos:
Given Kudos: 351
Location: India
Posts: 1,107
Kudos: 1,348
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
GCMEMBER
Joined: 09 Dec 2019
Last visit: 03 Jun 2021
Posts: 123
Own Kudos:
176
 [1]
Given Kudos: 5
Posts: 123
Kudos: 176
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Find the area of common portion when two circles intersect as shown below

(1) Distance between the centers of two circle is 2√2.
No info. Whether the circles have same or different radius.
Not sufficient

(2) Arcs in common portion subtend 90 degree angle at the centers of respective circles.

This statement tells that both the circles are equal but their radius can be any number.

Not sufficient

(1) + (2)

We get that both the circles are equal in size and the distance between their centers is fixed. So, the common portion can be determined.
Sufficient

Option C

Posted from my mobile device
User avatar
CEdward
Joined: 11 Aug 2020
Last visit: 14 Apr 2022
Posts: 1,203
Own Kudos:
Given Kudos: 332
Posts: 1,203
Kudos: 272
Kudos
Add Kudos
Bookmarks
Bookmark this Post
chetan2u
Bunuel
Find the area of common portion when two circles intersect as shown below

(1) Distance between the centers of two circle is 2√2.

(2) Arcs in common portion subtend 90 degree angle at the centers of respective circles.



We require to know the radius and the angle subtended by the arc from Center of each circle.

(1) Distance between the centers of two circle is 2√2.
We do not know the radius or the angle.

(2) Arcs in common portion subtend 90 degree angle at the centers of respective circles.
Angles subtended is 90.
So we can draw the figure as attached.
The line AB bisects the angle subtended from Center, so each angle is 90/2=45.
ACB = 180-45-45=90.
This triangle ACB is a right angled triangle with the two sides as r. Hypotenuse =AB=\(r\sqrt{2}\)

Combined
Now AB from statement I is \(2\sqrt{2}=r\sqrt{2}........r=2\).
We know the angle subtended from Center as 90 and radius is 2. We can find the area of common portion.

C

chetan2u, a couple of follow up questions

RE: St1 - Why can't we just divide 2√2 to get the radius?
RE: Why do we need to know the angle that subtends the centres at 90 degrees
RE: Given all the work you did, how would you actually figure out the area of the common portion?
User avatar
chetan2u
User avatar
GMAT Expert
Joined: 02 Aug 2009
Last visit: 15 Nov 2025
Posts: 11,238
Own Kudos:
Given Kudos: 335
Status:Math and DI Expert
Location: India
Concentration: Human Resources, General Management
GMAT Focus 1: 735 Q90 V89 DI81
Products:
Expert
Expert reply
GMAT Focus 1: 735 Q90 V89 DI81
Posts: 11,238
Kudos: 43,706
Kudos
Add Kudos
Bookmarks
Bookmark this Post
CEdward

RE: St1 - Why can't we just divide 2√2 to get the radius?
RE: Why do we need to know the angle that subtends the centers at 90 degrees
RE: Given all the work you did, how would you actually figure out the area of the common portion?

RE: St1 - Why can't we just divide 2√2 to get the radius?
Look at the attached figure. The sketch shows just 3 of the possible ways circles can be made when the distance between the centers is AB.
In the brown color circles, the radius will be AB/2, while in the blue colour circle, the radius is almost AB.


RE: Why do we need to know the angle that subtends the centers at 90 degrees
This tells us that both circle have equal radius.

RE: Given all the work you did, how would you actually figure out the area of the common portion?
Check the sketch on right
A(ACXD)= \(\frac{90}{360}*\pi r^2=\frac{1}{4}*\pi *2^2=\pi\)
Similarly for BCYD, A(BCYD)=\(\pi\)
Area of square ACBD = \(r^2=4\)

A(common portion)=\(2\pi - 4\)

Quote:
Why are the two circles have same radius, when the subtend same angle 90.

Join CD. ACD is a 45-45-90 triangle as AC=AD=r, and CAD is 90. CD =\(r_1\sqrt{2}\)....(I)

Now BCD is also 45-45-90 triangle for similar reasons. If radius is \(r_2\), then CD=\(r_2\sqrt{2}\)....(II)

Equate the two values of CD from I and II => \(r_1=r_2\)
Both radius are the same.

Harshjha001
Attachments

Untitled4.png
Untitled4.png [ 38.13 KiB | Viewed 2315 times ]

avatar
Harshjha001
Joined: 14 Sep 2019
Last visit: 08 Oct 2021
Posts: 60
Own Kudos:
Given Kudos: 19
Posts: 60
Kudos: 25
Kudos
Add Kudos
Bookmarks
Bookmark this Post
How can we assume that both circles have equal dimensions ? It is nowhere stated .
If they are not equal then line AB will not bisect angle A and angle B . The solution will fall apart. chetan2u
Moderators:
Math Expert
105390 posts
496 posts