Stmt1 . We know only one co-ordinate. we don't know altitude, base or one side of triangle. Hence insufficient.

Stmt2: We know altitude when draw from C to opposite base is 6. Also this altitude will bisect the angle ACB making each angle 30.

So cos30 = altitude/CA {imagine a line from C to AB}

\(\sqrt{3}/2=6/CA\)

\(CA= 12/\sqrt{3}.\) We know one side of EQUILATERAL triangle.

\(Apply formula Area of equilateral triangle= s^2 * \sqrt{3}/4

= (12/\sqrt{3})^2* \sqrt{3}/4

= 12\sqrt{3}\)

Hence sufficient.

OA B.

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